Quantitative Aptitude Practice Question and Answer
8Q: The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ? 1728 05b5cc6fbe4d2b4197774f09f
5b5cc6fbe4d2b4197774f09f- 187true
- 281false
- 383false
- 485false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "87"
Explanation :
Answer: A) 87 Explanation: Cp1 = p2 - p1 , Cp2 = p3 - p2 ......Cp23 = p24 - p23Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)All terms get cancelled, except p1 = 2 and p24 = 89 So Sum = -p1 + p24Sum of series = -2 + 89 = 87
Q: 20 men went to a restaurant. Ninteen of them paid Rs.70 each and the twentieth man paid Rs.90.25 more than the average of all the 20 men. What is the total bill ? 1726 05b5cc73ae4d2b4197774f8b5
5b5cc73ae4d2b4197774f8b5- 1Rs. 1495true
- 2Rs. 548false
- 3Rs. 850false
- 4Rs. 1750false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "Rs. 1495"
Explanation :
Answer: A) Rs. 1495 Explanation: Let the average bill paid by twenty members = 'x' But 19 men paid each = Rs. 70 20th man paid Rs. 90.25 more than the avg bill of 20 = x + 90.25 20x = 19(70) + x + 90.2519x = 1330 + 90.2519x = 1420.25x = 1420.25/19 = Rs. 74.75 But the total bill = 20 x 74.75 = Rs. 1495.
Q: If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ? 1726 05b5cc764e4d2b4197774fd80
5b5cc764e4d2b4197774fd80- 1100 mtsfalse
- 296 mtsfalse
- 398 mtstrue
- 4120 mtsfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 3. "98 mts"
Explanation :
Answer: C) 98 mts Explanation: Let the distance between home and school is 'x'.Let actual time to reach be 't'.Thus, x/4 = t + 4 ---- (1)and x/6 = t - 30 -----(2)Solving equation (1) and (2)=> x = 98 mts.
Q: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 1726 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
- 2203false
- 3150false
- 4113false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "277"
Explanation :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.
Q: Shamma lends Rs.40,000 to two of her friends. She gives Rs.24,000 to the first at 8% p.a. simple interest. Shamma wants to make a profit of 10% on the whole. The simple interest rate at which she should lend the remaining sum of money to the second friend is: 1724 05b5cc6b7e4d2b4197774d624
5b5cc6b7e4d2b4197774d624- 113%true
- 28.5%false
- 39.5%false
- 411.25%false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "13%"
Explanation :
Answer: A) 13% Explanation: The ratio of money she lended is 24000 : 16000 = 3 : 2 Let the rate of interest be R% 8% R% 10 3 : 2 R = 13%.
Q: Find the odd one out of the series ? 35, 48, 54, 63, 81, 105 1721 05b5cc6dae4d2b4197774e8c3
5b5cc6dae4d2b4197774e8c3- 163false
- 248false
- 335true
- 481false
- Show Answer
- Workspace
- SingleChoice
Answer : 3. "35"
Explanation :
Answer: C) 35 Explanation: 48, 54, 63, 81 and 105 are divisible by 3 but not 35.
Q: Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ? 1721 05b5cc6cae4d2b4197774e068
5b5cc6cae4d2b4197774e068- 131 yearstrue
- 237 yearsfalse
- 346 yearsfalse
- 429 yearsfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "31 years"
Explanation :
Answer: A) 31 years Explanation: Let the present age of Pinky be x years Then the age of Mary is x - 12 years After 3 years, Ratio of MaryPinky = x - 9x + 3 = 58 8x - 72 = 5x +15 => 3x = 87 => x = 29 => Age of Pinky = 29 years => Age of Mary = 29 - 12 = 17 years Present age of Sam = 29 + 17 = 46 Before 15 years Sam age = 46 - 15 = 31 years.
Q: One girl can eat 112 chocolates in half a minute, and her boy friend can eat half as many in twice the length of time. How many chocolates can both boy and girl eat in 12 seconds ? 1717 05b5cc745e4d2b4197774fa27
5b5cc745e4d2b4197774fa27- 144false
- 232false
- 356true
- 449false
- Show Answer
- Workspace
- SingleChoice
Answer : 3. "56"
Explanation :
Answer: C) 56 Explanation: Girl eats 112 chocolates in 30 sec so she can eat in 12 sec is 12 x 112/30 = 44.8 chocolates. Her boy friend can eat one-half of 112 in twice of 30 sec so he can eat 56 in 60 sec Then he can eat in 12 sec is 56 x 12/60 = 11.2 chocolates. Hence, together they can eat = 44.8 + 11.2 =56 chocolates in 12 seconds.