Quantitative Aptitude Practice Question and Answer
8Q: A certain job was assigned to a group of women to do it in 20 days. But 12 women did not turn up for the job and the remaining did the job in 32 days. The original number of women in the group was? 1766 05b5cc6bae4d2b4197774d794
5b5cc6bae4d2b4197774d794- 136false
- 232true
- 322false
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Answer : 2. "32"
Explanation :
Answer: B) 32 Explanation: Let the total women in the group be 'W' Then according to the given data, W x 20 = (W-12) x 32 => W = 32 Therefore, the total number of women in the group = 32
Q: A fair six-sided die is rolled twice. What is the probability of getting 4 on the first roll and not getting 6 on the second roll ? 1764 05b5cc6d7e4d2b4197774e6c1
5b5cc6d7e4d2b4197774e6c1- 11/36false
- 25/36true
- 31/12false
- 41/9false
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Answer : 2. "5/36"
Explanation :
Answer: B) 5/36 Explanation: The two events mentioned are independent. The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied. P(getting first 4) = 1/6 P(no second 6) = 5/6 Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36
Q: A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold? 1764 05b5cc6a7e4d2b4197774cdef
5b5cc6a7e4d2b4197774cdef- 158 lfalse
- 265 lfalse
- 350 ltrue
- 462 lfalse
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Answer : 3. "50 l"
Explanation :
Answer: C) 50 l Explanation: Let the tin contain 5x litres of liquids 5x - 45 x 455x - 45 x 15 + 45 = 25 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 15 + 45 = 50 litres.
Q: Mr. X sold two properties P1 and P2 for Rs 1,00,000 each. He sold property P1 for 20% less than what he paid for it. What is the percentage of profit of property P2, so that he is not in gain or loss on the sale of two properties? 1762 05b5cc6aae4d2b4197774cf6f
5b5cc6aae4d2b4197774cf6f- 133.33%true
- 229.97%false
- 325%false
- 422.22%false
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Answer : 1. "33.33%"
Explanation :
Answer: A) 33.33% Explanation: Let 'A' be the cost price of property P1. Then from the given data, the selling price of P1 = Rs. 1,00,000 He got 20% loss on selling P1 ⇒A - 20A100 = 100000⇒A = 1,25,000 Therefore, the amount he lossed on selling P1 = 25,000 As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000 But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000 Hence, the profit percentage on P2 = GainCPx 100 = 2500075000x100 = 1003= 33.33%
Q: What is the probability that a leap year has 53 Saturdays and 52 Sundays ? 1762 05b5cc6dfe4d2b4197774eada
5b5cc6dfe4d2b4197774eada- 11/7true
- 22/7false
- 31/2false
- 43/2false
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Answer : 1. "1/7"
Explanation :
Answer: A) 1/7 Explanation: A leap year has 52 weeks and two daysTotal number of cases = 7Number of favourable cases = 1i.e., {Friday, Saturday} Required Probability = 1/7
Q: The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ? 1759 05b5cc6fbe4d2b4197774f09f
5b5cc6fbe4d2b4197774f09f- 187true
- 281false
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Answer : 1. "87"
Explanation :
Answer: A) 87 Explanation: Cp1 = p2 - p1 , Cp2 = p3 - p2 ......Cp23 = p24 - p23Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)All terms get cancelled, except p1 = 2 and p24 = 89 So Sum = -p1 + p24Sum of series = -2 + 89 = 87
Q: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 1759 05b5cc701e4d2b4197774f170
5b5cc701e4d2b4197774f170- 1Rs. 1,24,000false
- 2Rs. 1,44,000true
- 3Rs. 1,32,000false
- 4Rs. 1,62,000false
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Answer : 2. "Rs. 1,44,000"
Explanation :
Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.
Q: A store owner is packing books into larger boxes that measure 25 by 42 by 60 inches. If the measurement of each book is 7 by 6 by 5 inches, then how many books can be placed in the box ? 1757 05b5cc74ae4d2b4197774fad6
5b5cc74ae4d2b4197774fad6- 1175false
- 2345false
- 3265false
- 4300true
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Answer : 4. "300"
Explanation :
Answer: D) 300 Explanation: Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.Now, n = 25 x 42 x 60 / 7 x 6 x 5 = 63000 / 210 = 300.Therefore, 300 books can be in that box.