Quantitative Aptitude Practice Question and Answer
8Q: If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ? 1515 05b5cc764e4d2b4197774fd80
5b5cc764e4d2b4197774fd80- 1100 mtsfalse
- 296 mtsfalse
- 398 mtstrue
- 4120 mtsfalse
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Answer : 3. "98 mts"
Explanation :
Answer: C) 98 mts Explanation: Let the distance between home and school is 'x'.Let actual time to reach be 't'.Thus, x/4 = t + 4 ---- (1)and x/6 = t - 30 -----(2)Solving equation (1) and (2)=> x = 98 mts.
Q: एक रेलगाड़ी की लम्बाई 300 मीटर हैं। वह 72 किमी प्रति घंटे की रफ्तार से एक खम्भे को कितनी देर में पार कर जाएगी? 1514 05d15fd8e44a3a75f13296b87
5d15fd8e44a3a75f13296b87- 118 सैंकण्डfalse
- 215 सैंकण्डtrue
- 312 सैंकण्डfalse
- 420 सैंकण्डfalse
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Answer : 2. "15 सैंकण्ड"
Q: After working for 8 days, Hari Ram finds that only 1/3 rd of the work has been done. He employs Satya who is 60% as efficient as Hari Ram. How many days more would Satya take to complete the work ? 1514 05b5cc6d3e4d2b4197774e4fa
5b5cc6d3e4d2b4197774e4fa- 124 1/2 daysfalse
- 225 3/2 daysfalse
- 324 2/3 daysfalse
- 426 2/3 daystrue
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Answer : 4. "26 2/3 days"
Explanation :
Answer: D) 26 2/3 days Explanation: 1/3 ---- 8 1 -------? Hari can do total work in = 24 days As satya is 60% efficient as Hari, then Satya = 1/24 x 60/100 = 1/40 => Satya can do total work in 40 days 1 ----- 40 2/3 ---- ? => 26 2/3 days.
Q: H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is : 1512 05b5cc6e7e4d2b4197774eda6
5b5cc6e7e4d2b4197774eda6- 1360false
- 2180true
- 390false
- 4120false
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Answer : 2. "180"
Explanation :
Answer: B) 180 Explanation: 4 x 27 x 3125 = 22 × 33 × 55 ; 8 x 9 x 25 x 7 = 23 × 32 × 52 × 7 16 x 81 x 5 x 11 x 49 = 24 × 34 × 5 × 11 × 72 H.C.F = 22 × 32 × 5 = 180.
Q: A,B,C together can do a piece of work in 10 days.All the three started workingat it together and after 4 days,A left.Then,B and C together completed the work in 10 more days.In how many days can complete a work alone ? 1512 05b5cc70ee4d2b4197774f34c
5b5cc70ee4d2b4197774f34c- 125true
- 224false
- 323false
- 421false
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Answer : 1. "25"
Explanation :
Answer: A) 25 Explanation: (A+B+C) do 1 work in 10 days. So (A+B+C)'s 1 day work=1/10 and as they work together for 4 days so workdone by them in 4 days=4/10=2/5 Remaining work=1-2/5=3/5 (B+C) take 10 more days to complete 3/5 work. So( B+C)'s 1 day work=3/50 Now A'S 1 day work=(A+B+C)'s 1 day work - (B+C)'s 1 day work=1/10-3/50=1/25 A does 1/25 work in in 1 day Therefore 1 work in 25 days.
Q: 7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age? 1511 05b5cc6bbe4d2b4197774d849
5b5cc6bbe4d2b4197774d849- 191 yearsfalse
- 2115 yearsfalse
- 3103 yearstrue
- 4Can't be determinedfalse
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Answer : 3. "103 years"
Explanation :
Answer: C) 103 years Explanation: Let present Anirudh's age be 'A' and Bhavana's age be 'B' Given seven years, their ratio is 7:9 => A-7 : B-7 = 7 : 9 => 9A - 7B = 14 .......(1) And given, Chandhu is 12 years older than A nad 12 years younger than B => C = A + 12....(2) => B = C + 12 => B = A + 12 + 12 .....(From (2)) => B = A + 24 ....(3) Put (3) in (1) 9A - 7(A+24) = 14 9A - 7A - 168 = 14 2A = 182 => A = 91 years => C = A + 12 = 91 +12 = 103 years.
Q: A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is ? 1509 05b5cc720e4d2b4197774f640
5b5cc720e4d2b4197774f640- 111false
- 27false
- 39true
- 413false
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Answer : 3. "9"
Explanation :
Answer: C) 9 Explanation: Here the number of cogs is inveresly proportional to number of revolutions => More cogs less revolution=> 6 : 14 :: x : 21=> (21x6)/14 = 9
Q: Pavan and Sravan are two persons. If Pavan works with his actual efficiency and Sravan twice of his actual efficiency then it takes 25 days to complete the work. But If Pavan works twice of his actual efficiency and Sravan with his normal efficiency then the work is completed in 20 days. How many days would it take if Sravan alone works with his actual efficiency (in Days)? 1509 05b5cc6c7e4d2b4197774ded2
5b5cc6c7e4d2b4197774ded2- 150false
- 2100true
- 370false
- 435false
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Answer : 2. "100"
Explanation :
Answer: B) 100 Explanation: Let the Efficiency of pavan be E(P) Let the Efficiency of sravan be E(S) Here Work W = LCM(25,20) = 100 Now, E(P+2S) = 100/25 = 4 ....(1) E(2P+S) = 100/20 = 5 ....(2) Hence, from (1) & (2) we get E(S) = 1 => Number of days Savan alone work to complete the work = 100/1 = 100 days.