Quantitative Aptitude Practice Question and Answer
8Q: एक बक्से में 300 रूपये है जो 1रूपये, 50 पैसे तथा 25 पैसे के सिक्कों में है एवं उनका अनुपात 2ः4ः8 है। 25 पैसे वाले सिक्कों की संख्या बताइए। 6318 35d1b179d1fc62311c773687f
5d1b179d1fc62311c773687f- 1300false
- 2200false
- 3400true
- 4100false
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Answer : 3. "400"
Q: A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year ? 6187 05b5cc6e5e4d2b4197774ed38
5b5cc6e5e4d2b4197774ed38- 121:29false
- 241:54false
- 332:45true
- 437:51false
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Answer : 3. "32:45"
Explanation :
Answer: C) 32:45 Explanation: A : B(8000x4)+(4000x8) : (9000x6)+(6000x6) 64000 : 90000=> 32 : 45
Q: A Shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net Profit or loss that he makes? 6112 05b5cc7bbe4d2b419777509d7
5b5cc7bbe4d2b419777509d7- 14%true
- 25%false
- 36%false
- 48%false
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Answer : 1. "4%"
Explanation :
Answer: A) 4% Explanation: SP of first article = Rs.1000 Profit = 20% CP = SP x 100100+P% = Rs. 25003 SP of Second Article = Rs.1000 Loss = 20% CP = SP x 100100-L% = Rs. 1250 So, Total SP = Rs.2000; Total CP = Rs.6250/3 As the CP is more than SP, he makes a loss. Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3) So, Loss Percent = Lossx100/CP = 4%
Q: Which is the next number in the sequence: 1, 3, 6, 11, 20, 37, ?? 6102 05b5cc699e4d2b4197774c6fb
5b5cc699e4d2b4197774c6fb- 149false
- 256false
- 364false
- 470true
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Answer : 4. "70"
Explanation :
Answer: D) 70 Explanation: Here the given series is 1, 3, 6, 11, 20, 37, ??, and the logic behind the series is 1 x 2 + 1 = 3 3 x 2 + 0 = 6 6 x 2 + (-1) = 11 11 x 2 + (-2) = 20 20 x 2 + (-3) = 37 37 x 2 + (-4) = 70 Hence, the next number in the given series is 70.
Q: A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ? 6087 05b5cc75ee4d2b4197774fc93
5b5cc75ee4d2b4197774fc93- 1Rs.37,500true
- 2Rs.36,400false
- 3Rs.37,415false
- 4Rs.36,500false
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Answer : 1. "Rs.37,500"
Explanation :
Answer: A) Rs.37,500 Explanation: Assume A be the cost price. Therefore,35×A×10100 - 25×A×5100 = 1500 => A = Rs 37,500.
Q: 240 मीटर लम्बी ट्रेन 48 किमी प्रति घंटा की गति से एक प्लेटफार्म 39 सैकंड में पार करती हैं। प्लेटफार्म की लम्बाई मीटर में कितनी है 6025 05d198ffd1388cd24f08602fd
5d198ffd1388cd24f08602fd- 1520false
- 2280true
- 3480false
- 4270false
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Answer : 2. "280"
Q: In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case ? 5924 05b5cc6e5e4d2b4197774ed24
5b5cc6e5e4d2b4197774ed24- 1693false
- 2741false
- 3528true
- 4654false
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Answer : 3. "528"
Explanation :
Answer: C) 528 Explanation: Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)= (1200)(30)(3) kg. Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k As the same provisions are available=> (1200)(30)(3) = (1200 + x)(25)(2.5) x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.
Q: The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of ? 5888 05b5cc6e0e4d2b4197774eb98
5b5cc6e0e4d2b4197774eb98- 14:5false
- 26:5true
- 33:2false
- 41:3false
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Answer : 2. "6:5"
Explanation :
Answer: B) 6:5 Explanation: 4:5 3:2 -------=> 12:15:10 12:10 => 6:5