Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: 64 boys and 40 girls form a group for social work. During their membership drive, the same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4:3 ? 6114 0

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    168
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  • 2
    201
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  • 3
    147
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  • 4
    154
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उत्तर : 1. "168"
व्याख्या :

Answer: A) 168 Explanation: Let us say x boys and x girls joined the group. (64 + x)/(40 + x) = 4/3 192 + 3x = 160 + 4x => x = 32 Number of members in the group = 64 + x + 40 + x = 104 + 2x = 168.

प्र: The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of ? 6093 0

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    4:5
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  • 2
    6:5
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  • 3
    3:2
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  • 4
    1:3
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उत्तर : 2. "6:5"
व्याख्या :

Answer: B) 6:5 Explanation:     4:5    3:2   -------=> 12:15:10  12:10 => 6:5

प्र: 3 men, 4 women and 6 children can complete a work in 7 days. A woman does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 7 days  ? 6069 0

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    6
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  • 2
    9
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  • 3
    5
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  • 4
    7
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उत्तर : 4. "7"
व्याख्या :

Answer: D) 7 Explanation: Let 1 woman's 1 day work = x. Then, 1 man's 1 day work = x/2 and 1 child's 1 day work  x/4. So, (3x/2 + 4x + + 6x/4) = 1/7 28x/4 = 1/7 => x = 1/49 1 woman alone can complete the work in 49 days. So, to complete the work in 7 days, number of women required = 49/7 = 7.

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उत्तर : 3. "528"
व्याख्या :

Answer: C) 528 Explanation: Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)= (1200)(30)(3) kg. Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k As the same provisions are available=> (1200)(30)(3) = (1200 + x)(25)(2.5) x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.

प्र: If 78K928L is divisible by 6, then which of the following can Q and R take ? 6064 0

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    K=2 & L=3
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  • 2
    K=1 & L=4
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  • 3
    K=1 & L=2
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  • 4
    K=3 & L=3
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उत्तर : 2. "K=1 & L=4"
व्याख्या :

Answer: B) K=1 & L=4 Explanation: As per divisibility rule a number is divisible by 6 means it should be divisible by 2 and 3 case 1 : the divisibility rule for 2 is the number should be end with even number in this case R =2 & R=4 case 2 : The divisibility rule for 3 is the sum of numbers should be divisible by 3so if we take option (2) Q=1 & R=4 the sum is 39 if we take option (3) Q=1 & R=2 the sum is 37 So Option (2) is correct 39 is divided by 3

प्र: Taps X and Y can fill a tank in 30 and 40 minutes respectively.Tap Z can empty the filled tank in 60 minutes.If all the three taps are kept open for one minute each,how much time will the taps take to fill the tank? 6057 0

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    48min
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  • 2
    72min
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  • 3
    24min
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  • 4
    None of these
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उत्तर : 3. "24min"
व्याख्या :

Answer: C) 24min Explanation: Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore,   part filled by tap X in 1 minute = 1/30   part filled by tap Y in 1 minute = 1/40   Tap Z can empty the tank in 60 minutes. Therefore,   part emptied by tap Z in 1 minute = 1/60   Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24   i.e., the tank can be filled in 24 minutes.

प्र: यदि 2 वर्ष बाद देय राशि पर 14% प्रतिवर्ष की दर से वास्तविक छूट 168रु हो, तो देय राशि है? 6008 7

  • 1
    Rs.948
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  • 2
    Rs.876
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  • 3
    Rs.768
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  • 4
    Rs.658
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उत्तर : 3. "Rs.768"
व्याख्या :

Answer: C) Rs.768 Explanation: P.W. = 100×T.DR×T = 100×16814×2 = 600. Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.

प्र: A boatman can row 3 km against the stream in 20 minutes and return in 18 minutes. Find the rate of current ? 5986 0

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    1/3 kmph
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  • 2
    2/3 kmph
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  • 3
    1/4 kmph
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  • 4
    1/2 kmph
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उत्तर : 4. "1/2 kmph"
व्याख्या :

Answer: D) 1/2 kmph Explanation: Speed in upstream = Distance / Time = 3 x 60/20 = 9 km/hr. Speed in downstream = 3 x 60/18 = 10 km/hr Rate of current = (10-9)/2 = 1/2 km/hr.

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