Quantitative Aptitude Practice Question and Answer
8Q: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ? 6777 05b5cc6e3e4d2b4197774ec98
5b5cc6e3e4d2b4197774ec98- 16/7false
- 219/21false
- 37/31false
- 45/21true
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Answer : 4. "5/21"
Explanation :
Answer: D) 5/21 Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁) As remaining person can be any one among three couples left. Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅= (10 x 6)/252 = 5/21
Q: In a purse there are 30 coins, twenty one-rupee and remaining 50-paise coins. Eleven coins are picked simultaneously at random and are placed in a box. If a coin is now picked from the box, find the probability of it being a rupee coin? 6753 05b5cc60de4d2b4197774b618
5b5cc60de4d2b4197774b618- 14/7false
- 22/3true
- 31/2false
- 45/6false
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Answer : 2. "2/3"
Explanation :
Answer: B) 2/3 Explanation: Total coins 30 In that, 1 rupee coins 20 50 paise coins 10Probability of total 1 rupee coins = 20C11 Probability that 11 coins are picked = 30C11 Required probability of a coin now picked from the box is 1 rupee = 20C11/30C11 = 2/3.
Q: Find the missing number? 15, 30, ? , 40, 8, 48 6728 05b5cc6afe4d2b4197774d264
5b5cc6afe4d2b4197774d264- 121false
- 28false
- 319false
- 410true
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Answer : 4. "10"
Explanation :
Answer: D) 10 Explanation: Given nuber series is 15, 30, ? , 40, 8, 48 Here the number series follows a pattern that 15 15 x 2 = 30 30 ÷ 3 = 10 10 x 4 = 40 40 ÷ 5 = 8 8 x 6 = 48 Hence, the missing number in the series is 10.
Q: Which two months in a year have the same calendar? 6710 05b5cc694e4d2b4197774c498
5b5cc694e4d2b4197774c498- 1October, Decemberfalse
- 2April, Novemberfalse
- 3June, Octoberfalse
- 4April, Julytrue
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Answer : 4. "April, July"
Explanation :
Answer: D) April, July Explanation: If the period between the two months is divisible by 7, then that two months will have the same calender . Now,(a). October + November = 31 + 30 = 61 (not divisible by 7) (b). Apr. + May + June + July + Aug. + Sep. + Oct. = 30 + 31 + 30 + 31 + 31 +30 + 31 = 213 (not divisible by 7) (c). June + July + Aug. + Sep. = 30 + 31 + 31 + 30 = 122 (not divisible by 7) (d). Apr. + May + June = 30 + 31 + 30 = 91 (divisible by 7) Hence, April and July months will have the same calendar.
Q: एक बक्से में 300 रूपये है जो 1रूपये, 50 पैसे तथा 25 पैसे के सिक्कों में है एवं उनका अनुपात 2ः4ः8 है। 25 पैसे वाले सिक्कों की संख्या बताइए। 6660 35d1b179d1fc62311c773687f
5d1b179d1fc62311c773687f- 1300false
- 2200false
- 3400true
- 4100false
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Answer : 3. "400"
Q: Which is the next number in the sequence: 1, 3, 6, 11, 20, 37, ?? 6655 05b5cc699e4d2b4197774c6fb
5b5cc699e4d2b4197774c6fb- 149false
- 256false
- 364false
- 470true
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Answer : 4. "70"
Explanation :
Answer: D) 70 Explanation: Here the given series is 1, 3, 6, 11, 20, 37, ??, and the logic behind the series is 1 x 2 + 1 = 3 3 x 2 + 0 = 6 6 x 2 + (-1) = 11 11 x 2 + (-2) = 20 20 x 2 + (-3) = 37 37 x 2 + (-4) = 70 Hence, the next number in the given series is 70.
Q: A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C which is at midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B ? 6625 15b5cc6e9e4d2b4197774ee41
5b5cc6e9e4d2b4197774ee41- 1180 kmtrue
- 2160 kmfalse
- 3140 kmfalse
- 4120 kmfalse
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Answer : 1. "180 km"
Explanation :
Answer: A) 180 km Explanation: Speed in downstream = (14 + 4) km/hr = 18 km/hr; Speed in upstream = (14 – 4) km/hr = 10 km/hr. Let the distance between A and B be x km. Then, x/18 + (x/2)/10 = 19 ⇔ x/18 + x/20 = 19 ⇒ x = 180 km.
Q: पहली संख्या का 30 प्रतिशत दूसरी संख्या का 75 प्रतिशत है। पहली संख्या का दूसरी संख्या से लगभग क्या अनुपात है? 6622 15d1b04cd8a754124194a751a
5d1b04cd8a754124194a751a- 15:2true
- 25:3false
- 325:14false
- 415:16false
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