Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev? 2038 05b5cc655e4d2b4197774bd70
5b5cc655e4d2b4197774bd70- 112false
- 214false
- 322false
- 410true
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उत्तर : 4. "10"
व्याख्या :
Answer: D) 10 Explanation: Let Rajeev's present age be x years. Rajeev's age after 15 years = (x + 15) years. Rajeev's age 5 years back = (x - 5) years Then ATQ, x + 15 = 5 (x - 5) x + 15 = 5x - 25 => x = 10 Hence, Rajeev's present age = x = 10 years.
प्र: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 2037 05b5cc6bfe4d2b4197774da0a
5b5cc6bfe4d2b4197774da0a- 11/3false
- 22/3false
- 31/6true
- 45/6false
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उत्तर : 3. "1/6"
व्याख्या :
Answer: C) 1/6 Explanation: Given X can do in 10 days => 1 day work of X = 1/10 Y can do in 15 days => 1 day work of Y = 1/15 1day work of (X + Y) = 1/10 + 1/15 = 1/6 Given they are hired for 5 days => 5 days work of (X + Y) = 5 x 1/6 = 5/6 Therefore, Unfinished work = 1 - 5/6 = 1/6
प्र: Sonika invested an amount of Rs.5800 for 2 years. At what rate of compound interest will she get an amount of Rs.594.50 at the end of 2 years ? 2035 05b5cc73ae4d2b4197774f89c
5b5cc73ae4d2b4197774f89c- 16.5%false
- 26%false
- 35%true
- 44.5%false
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उत्तर : 3. "5%"
व्याख्या :
Answer: C) 5% Explanation: C.I = P1+r100t-1 594.5 = 58001+r1002-1 594.55800+1=1+r1002 r100=1.05-1=0.05=> r = 5 % .
प्र: A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece? 2030 05b5cc6bbe4d2b4197774d85d
5b5cc6bbe4d2b4197774d85d- 128 cmfalse
- 23.5 cmfalse
- 37 cmfalse
- 414 cmtrue
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उत्तर : 4. "14 cm"
व्याख्या :
Answer: D) 14 cm Explanation: Circular piece is 4 x 11 = 44 cm long, Then Circumference of circle is given by, 44 = pi x D, where D is the diameter D = 44 / pi Take pi = 22 / 7, then D = 44 / (22/7) = (44 x 7) / 22 D = 14 cm.
प्र: If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ? 2029 05b5cc73ae4d2b4197774f8a1
5b5cc73ae4d2b4197774f8a1- 131/25false
- 215/17true
- 314/25false
- 411/16false
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उत्तर : 2. "15/17"
व्याख्या :
Answer: B) 15/17 Explanation: The original fraction is 2551 × 350+100150+100 = 15/17.
प्र: Find the next number in the given series 0.25, 8, 128, 1024, ? 2027 05b5cc6bce4d2b4197774d8b1
5b5cc6bce4d2b4197774d8b1- 14096true
- 22526false
- 38486false
- 42620false
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उत्तर : 1. "4096"
व्याख्या :
Answer: A) 4096 Explanation: Here given series follows a pattern that 0.25, 8, 128, 1024, ? 0.25 x 32 = 8 8 x 16 = 128 128 x 8 = 1024 1024 x 4 = 4096
प्र: A person got Rs.48 more when he invested a certain sum at compound interest instead of simple interest for two years at 8% p.a. Find the sum ? 2020 05b5cc6e0e4d2b4197774eb61
5b5cc6e0e4d2b4197774eb61- 1Rs.8000false
- 2Rs.6500false
- 3Rs.7500true
- 4Rs.5000false
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उत्तर : 3. "Rs.7500"
व्याख्या :
Answer: C) Rs.7500 Explanation: p=d×1002R2 Where d is difference, r is rate of interest. => (48 x 100 x 100) / 8 x 8 = Rs.7500
प्र: How many numbers up to 300 and 700 are divisible by 2, 3 and 7 both together ? 2019 05b5cc6e5e4d2b4197774ed01
5b5cc6e5e4d2b4197774ed01- 17false
- 29true
- 311false
- 45false
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उत्तर : 2. "9"
व्याख्या :
Answer: B) 9 Explanation: LCM of 2, 3, 7 is 42. => (700 – 300)/42 = 9 22/42 => 9 Numbers.