Quantitative Aptitude Practice Question and Answer
8Q: A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ? 2066 05b5cc731e4d2b4197774f7e2
5b5cc731e4d2b4197774f7e2- 110.5 kgsfalse
- 212 kgsfalse
- 39.6 kgsfalse
- 411.5 kgstrue
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Answer : 4. "11.5 kgs"
Explanation :
Answer: D) 11.5 kgs Explanation: Screws weight = 90x100 = 9000gmsbolts weight = 100 x 150 = 15000gmsweight = screws + bolts => 24000 gms =>24 kgGiven entire box weight = 35.5kgempty box = entire box weight - weight => 35.5kg - 24kg => 11.5kgso the empty box is 11.5kg.
Q: Length of train is 170 meters and speed of train is 63 km/hour. This train can pass a bridge in 30 seconds, then find the length of the bridge. 2064 05b5cc76fe4d2b4197774ff49
5b5cc76fe4d2b4197774ff49- 1355 mtstrue
- 2325 mtsfalse
- 3365 mtsfalse
- 4312 mtsfalse
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Answer : 1. "355 mts"
Explanation :
Answer: A) 355 mts Explanation: Given speed = 63 km/hr = 63×518=352 m/s Let the length of the bridge = x mts Given time taken to cover the distance of (170 + x)mts is 30 sec. We know speed = distancetimem/s ⇒352=170+x30 --> x = 355 mts.
Q: Three numbers are in the ratio of 3:4:5 and their L.C.M is 3600.Their HCF is: 2064 05b5cc783e4d2b41977750200
5b5cc783e4d2b41977750200- 140false
- 260true
- 3100false
- 4120false
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Answer : 2. "60"
Explanation :
Answer: B) 60 Explanation: Let the numbers be 3x, 4x, 5x. Then, their L.C.M = 60x. So, 60x=3600 or x=60. Therefore, The numbers are (3 x 60), (4 x 60), (5 x 60). Hence,required H.C.F=60
Q: 5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible? 2053 15b5cc7d1e4d2b4197775129f
5b5cc7d1e4d2b4197775129f- 12880true
- 21440false
- 3720false
- 42020false
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Answer : 1. "2880"
Explanation :
Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd. 4 women can be arranged at 4 even places in 4! ways. and 5 men can be placed in remaining 5 places in 5! ways. Hence, the required number of permutations = 4! x 5! = 24 x 120 = 2880
Q: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? 2050 05b5cc741e4d2b4197774f9e5
5b5cc741e4d2b4197774f9e5- 112 pmtrue
- 21 pmfalse
- 311 amfalse
- 411:30 amfalse
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Answer : 1. "12 pm"
Explanation :
Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.
Q: Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ? 2048 05b5cc6c5e4d2b4197774dd23
5b5cc6c5e4d2b4197774dd23- 15.75 kmsfalse
- 27.36 kmstrue
- 38.2 kmsfalse
- 46.98 kmsfalse
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Answer : 2. "7.36 kms"
Explanation :
Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms
Q: एक व्यापारी को एक रेडियो पर बिक्री हेतु क्या दाम अंकित करना चाहिए जिसे उसने 1200 रूपये में खरीदा था और जबकि वह उसके अंकित मूल्य पर 20 प्रतिशत छुट देना चाहता है तथा चाहता है कि तब भी उसे 25 प्रतिशत का लाभ उसकी बिक्री से मिले- 2039 05d133e2fd2441c3c5ff90a46
5d133e2fd2441c3c5ff90a46- 120%false
- 250%false
- 360%false
- 440%true
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Answer : 4. "40%"
Q: Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev? 2038 05b5cc655e4d2b4197774bd70
5b5cc655e4d2b4197774bd70- 112false
- 214false
- 322false
- 410true
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Answer : 4. "10"
Explanation :
Answer: D) 10 Explanation: Let Rajeev's present age be x years. Rajeev's age after 15 years = (x + 15) years. Rajeev's age 5 years back = (x - 5) years Then ATQ, x + 15 = 5 (x - 5) x + 15 = 5x - 25 => x = 10 Hence, Rajeev's present age = x = 10 years.