Quantitative Aptitude Practice Question and Answer
8Q: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man ? 1878 05b5cc6d7e4d2b4197774e728
5b5cc6d7e4d2b4197774e728- 14.58 kmsfalse
- 26.35 kmsfalse
- 35.76 kmstrue
- 45.24 kmsfalse
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Answer : 3. "5.76 kms"
Explanation :
Answer: C) 5.76 kms Explanation: Speed in still water = 6 kmph Stream speed = 1.2 kmph Down stream = 7.2 kmph Up Stream = 4.8 kmph x/7.2 + x/4.8 = 1 x = 2.88 Total Distance = 2.88 x 2 = 5.76 kms
Q: Three numbers are in the ratio of 3:4:5 and their L.C.M is 3600.Their HCF is: 1878 05b5cc783e4d2b41977750200
5b5cc783e4d2b41977750200- 140false
- 260true
- 3100false
- 4120false
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Answer : 2. "60"
Explanation :
Answer: B) 60 Explanation: Let the numbers be 3x, 4x, 5x. Then, their L.C.M = 60x. So, 60x=3600 or x=60. Therefore, The numbers are (3 x 60), (4 x 60), (5 x 60). Hence,required H.C.F=60
Q: In what ratio must wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg so that the mixture be worth Rs. 3/kg? 1877 05b5cc639e4d2b4197774baa0
5b5cc639e4d2b4197774baa0- 11:2false
- 23:2false
- 32:1true
- 42:3false
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Answer : 3. "2:1"
Explanation :
Answer: C) 2:1 Explanation: Given rate of wheat at cheap = Rs. 2.90/kg Rate of wheat at cost = Rs. 3.20/kg Mixture rate = Rs. 3/kg Ratio of mixture = 2.90 3.20 3 (3.20 - 3 = 0.20) (3 - 2.90 = 0.10) 0.20 : 0.10 = 2:1 Hence, wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg in the ratio of 2:1, so that the mixture be worth Rs. 3/kg.
Q: A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs.100 at the end of one year. In order clear his dues at the end of 2 years, he would pay : 1875 05b5cc77fe4d2b419777501d8
5b5cc77fe4d2b419777501d8- 1Rs. 100false
- 2Rs. 105false
- 3Rs. 115true
- 4Rs. 110false
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Answer : 3. "Rs. 115"
Explanation :
Answer: C) Rs. 115 Explanation: Amount to be paid = Rs.100+200×5×1100+100×5×1100= Rs. 115.
Q: If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ? 1875 05b5cc728e4d2b4197774f6c8
5b5cc728e4d2b4197774f6c8- 113/125false
- 214/57false
- 311/120true
- 416/41false
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Answer : 3. "11/120"
Explanation :
Answer: C) 11/120 Explanation: Let the numbers be a and b.We know that product of two numbers = Product of their HCF and LCMThen, a + b = 55 and ab = 5 x 120 = 600.=> The required sum = (1/a) + (1/b) = (a+b)/ab=55/600 = 11/120
Q: A train sets off at 3 p.m. at the speed of 70 kmph. Another train starts at 4:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet ? 1875 05b5cc6e7e4d2b4197774ed79
5b5cc6e7e4d2b4197774ed79- 110:10 pmfalse
- 29:50 pmfalse
- 311:30 pmtrue
- 410:30 pmfalse
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Answer : 3. "11:30 pm"
Explanation :
Answer: C) 11:30 pm Explanation: Distance = 70 x 1 ½ = 105 km Relative Speed = 85 – 70 = 15 Time = 105/15 = 7 hrs 4:30 + 7 hrs = 11.30 p.m.
Q: A train covers a distance between station A and station B in 45 min.If the speed of the train is reduced by 5 km/hr,then the same distance is covered in 48 min.what is the distance between the stations A and B ? 1871 05b5cc70ee4d2b4197774f347
5b5cc70ee4d2b4197774f347- 180 kmsfalse
- 260 kmstrue
- 345 kmsfalse
- 432 kmsfalse
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Answer : 2. "60 kms"
Explanation :
Answer: B) 60 kms Explanation: Let 'd' be the distance and 's' be the speed and 't' be the timed=sxt45 mins = 3/4 hr and 48 mins = 4/5 hrAs distance is same in both cases;s(3/4) = (s-5)(4/5)3s/4 = (4s-20)/515s = 16s-80s = 80 km.=> d = 80 x 3/4 = 60 kms.
Q: A person says that his son is 5 times as old as his daughter and his wife is 5 times older than his son and he is twice the age of his wife . The sum total of all the ages equals the age of the grand mother who celebrated her 81st birthday today. How old was his son? 1867 05b5cc715e4d2b4197774f413
5b5cc715e4d2b4197774f413- 150 yrstrue
- 225 yrsfalse
- 372 yrsfalse
- 440 yrsfalse
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Answer : 1. "50 yrs"
Explanation :
Answer: A) 50 yrs Explanation: Let the daughter age be 'x'Therefore, Son age = 5x, Mother age = 25x, Person age = 50x. Thus we get, x+5x+25x+50x = 8181x = 81x = 1 Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.