Quantitative Aptitude Practice Question and Answer

Q: A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ? 2066 0

  • 1
    10.5 kgs
    Correct
    Wrong
  • 2
    12 kgs
    Correct
    Wrong
  • 3
    9.6 kgs
    Correct
    Wrong
  • 4
    11.5 kgs
    Correct
    Wrong
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Answer : 4. "11.5 kgs"
Explanation :

Answer: D) 11.5 kgs Explanation: Screws weight = 90x100 = 9000gmsbolts weight = 100 x 150 = 15000gmsweight = screws + bolts => 24000 gms =>24 kgGiven entire box weight = 35.5kgempty box = entire box weight - weight => 35.5kg - 24kg => 11.5kgso the empty box is 11.5kg.

Q: Length of train is 170 meters and speed of train is 63 km/hour. This train can pass a bridge in 30 seconds, then find the length of the bridge. 2064 0

  • 1
    355 mts
    Correct
    Wrong
  • 2
    325 mts
    Correct
    Wrong
  • 3
    365 mts
    Correct
    Wrong
  • 4
    312 mts
    Correct
    Wrong
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Answer : 1. "355 mts"
Explanation :

Answer: A) 355 mts Explanation: Given speed = 63 km/hr = 63×518=352 m/s Let the length of the bridge = x mts Given time taken to cover the distance of (170 + x)mts is 30 sec. We know speed = distancetimem/s ⇒352=170+x30  -->  x = 355 mts.

Q: Three numbers are in the ratio of 3:4:5 and their L.C.M is 3600.Their HCF is: 2064 0

  • 1
    40
    Correct
    Wrong
  • 2
    60
    Correct
    Wrong
  • 3
    100
    Correct
    Wrong
  • 4
    120
    Correct
    Wrong
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Answer : 2. "60"
Explanation :

Answer: B) 60 Explanation: Let the numbers be 3x, 4x, 5x.   Then, their L.C.M = 60x.   So, 60x=3600 or x=60.   Therefore,  The numbers are (3 x 60), (4 x 60), (5 x 60).   Hence,required H.C.F=60

Q: 5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible? 2053 1

  • 1
    2880
    Correct
    Wrong
  • 2
    1440
    Correct
    Wrong
  • 3
    720
    Correct
    Wrong
  • 4
    2020
    Correct
    Wrong
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Answer : 1. "2880"
Explanation :

Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd.   4 women can be arranged at 4 even places in 4! ways.   and 5 men can be placed in remaining 5 places in 5! ways.   Hence, the required number of permutations  = 4! x 5! = 24 x 120 = 2880

Q: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? 2050 0

  • 1
    12 pm
    Correct
    Wrong
  • 2
    1 pm
    Correct
    Wrong
  • 3
    11 am
    Correct
    Wrong
  • 4
    11:30 am
    Correct
    Wrong
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Answer : 1. "12 pm"
Explanation :

Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.

Q: Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ? 2048 0

  • 1
    5.75 kms
    Correct
    Wrong
  • 2
    7.36 kms
    Correct
    Wrong
  • 3
    8.2 kms
    Correct
    Wrong
  • 4
    6.98 kms
    Correct
    Wrong
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Answer : 2. "7.36 kms"
Explanation :

Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms

Q: Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev? 2038 0

  • 1
    12
    Correct
    Wrong
  • 2
    14
    Correct
    Wrong
  • 3
    22
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 4. "10"
Explanation :

Answer: D) 10 Explanation: Let Rajeev's present age be  x years. Rajeev's age after 15 years = (x + 15) years. Rajeev's age 5 years back = (x - 5) years Then ATQ,  x + 15 = 5 (x - 5) x + 15 = 5x - 25 => x = 10   Hence, Rajeev's present age = x = 10 years.

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