Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58 ? 2183 0

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    Rs. 3748
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    Rs. 3847
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  • 3
    Rs. 3944
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  • 4
    Rs. 3154
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उत्तर : 3. "Rs. 3944"
व्याख्या :

Answer: C) Rs. 3944 Explanation: Let the side of the square plot be 'a' ft.Given area of the plot (a x a) = 289 => a = 17Length of the fence = Perimeter of the plot = 4a = 68 ft.Cost of building the fence = 68 x 58 = Rs. 3944.

प्र: Sum of present ages of P and Q is 41. Age of P 2 year hence is equal to age of R, 1 year ago. Age of P, 4 year hence is equal to age of Q 1 year ago and ratio of present age of P and S is 3 : 4. Find the difference of age of R and S. 2176 0

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    2
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    3
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    4
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    5
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उत्तर : 2. "3"
व्याख्या :

Answer: B) 3 Explanation: According to the given data, P + Q = 41 ......(1) R - 1 = P + 2 R = P + 3 and P + 4 = Q - 1 => Q = P + 5 ....(2) From (1)&(2) P = 18 Q = 18 + 5 = 23 R = 18 + 3 = 21 => P/S = 3/4 => S = 4/3 x 18 = 24 Required Difference = S - R = 24 - 21 = 3.

प्र: A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately? 2174 0

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    20
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    19
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    17
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    22
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उत्तर : 1. "20"
व्याख्या :

Answer: A) 20 Explanation: Given height of the conical tent = 3 m Diameter = 10 => Radius = D/2 = 10/2 = 5 m  Now, as the tent is in the conical form Volume of the conical tent = πr2h3  => (22 x 5 x 5 x 3) / (7 x 3)  = 22 x 25/7  = 78.54 cu.m  Given each person requires 3.92 cu.m of air  => Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

प्र: A motorboat goes 8 km an hour in still water, but takes thrice as much time in going the same distance against the current than going with the current. Then find the speed of the current? 2173 0

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    4 kmph
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    6 kmph
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    3 kmph
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    2 kmph
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उत्तर : 1. "4 kmph"
व्याख्या :

Answer: A) 4 kmph Explanation: Let the speed of current = 'C' km/hr   Given the speed of boat in still water = 6 kmph   Let 'd' kms be the distance it covers.   According to the given data,   Boat takes thrice as much time in going the same distance against the current than going with the current   i.e, d8 - C = 3 × d8 + C   ⇒ 24 - 3C = 8 + C⇒ 4C = 16⇒ C = 4 kmph   Hence, the speed of the current C = 4 kmph.

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उत्तर : 2. "25"

प्र: A train sets off at 3 p.m. at the speed of 70 kmph. Another train starts at 4:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet ? 2167 0

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    10:10 pm
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    9:50 pm
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    11:30 pm
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    10:30 pm
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उत्तर : 3. "11:30 pm"
व्याख्या :

Answer: C) 11:30 pm Explanation: Distance = 70 x 1 ½ = 105 km Relative Speed = 85 – 70 = 15 Time = 105/15 = 7 hrs 4:30 + 7 hrs = 11.30 p.m.

प्र: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 2163 0

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    720
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    360
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    120
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    24
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उत्तर : 4. "24"
व्याख्या :

Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.

प्र: Find the Odd One Out? 4, 6, 12, 30, 81, 315. 2161 0

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    6
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    12
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    81
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    315
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उत्तर : 3. "81"
व्याख्या :

Answer: C) 81 Explanation: Given the number series is 4, 6, 12, 30, 81, 315. Here it follows a pattern that 4 4 x 1.5 = 6 6 x 2 = 12 12 x 2.5 = 30 30 x 3 = 90 not equals to 81 90 x 3.5 = 315   Hence the odd one in the series is 81.

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