Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Which expression is equivalent to i233? 2142 05b5cc645e4d2b4197774bbd1
5b5cc645e4d2b4197774bbd1- 1itrue
- 21false
- 3-ifalse
- 4-1false
- उत्तर देखें
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उत्तर : 1. "i"
व्याख्या :
Answer: A) i Explanation: We know that, i2 = -1i3 = i2 x i = -1 x i = -ii4 = i2 x i2 = -1 x -1 = 1Hence, i233 =i4 x 58 + 1 = i232 x i1 = 1 x i = i
प्र: A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately? 2138 05b5cc6bfe4d2b4197774da97
5b5cc6bfe4d2b4197774da97- 120true
- 219false
- 317false
- 422false
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उत्तर : 1. "20"
व्याख्या :
Answer: A) 20 Explanation: Given height of the conical tent = 3 m Diameter = 10 => Radius = D/2 = 10/2 = 5 m Now, as the tent is in the conical form Volume of the conical tent = πr2h3 => (22 x 5 x 5 x 3) / (7 x 3) = 22 x 25/7 = 78.54 cu.m Given each person requires 3.92 cu.m of air => Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20
प्र: A motorboat goes 8 km an hour in still water, but takes thrice as much time in going the same distance against the current than going with the current. Then find the speed of the current? 2137 05b5cc6ace4d2b4197774d09b
5b5cc6ace4d2b4197774d09b- 14 kmphtrue
- 26 kmphfalse
- 33 kmphfalse
- 42 kmphfalse
- उत्तर देखें
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उत्तर : 1. "4 kmph"
व्याख्या :
Answer: A) 4 kmph Explanation: Let the speed of current = 'C' km/hr Given the speed of boat in still water = 6 kmph Let 'd' kms be the distance it covers. According to the given data, Boat takes thrice as much time in going the same distance against the current than going with the current i.e, d8 - C = 3 × d8 + C ⇒ 24 - 3C = 8 + C⇒ 4C = 16⇒ C = 4 kmph Hence, the speed of the current C = 4 kmph.
प्र: Sum of present ages of P and Q is 41. Age of P 2 year hence is equal to age of R, 1 year ago. Age of P, 4 year hence is equal to age of Q 1 year ago and ratio of present age of P and S is 3 : 4. Find the difference of age of R and S. 2124 05b5cc6aae4d2b4197774cf4c
5b5cc6aae4d2b4197774cf4c- 12false
- 23true
- 34false
- 45false
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उत्तर : 2. "3"
व्याख्या :
Answer: B) 3 Explanation: According to the given data, P + Q = 41 ......(1) R - 1 = P + 2 R = P + 3 and P + 4 = Q - 1 => Q = P + 5 ....(2) From (1)&(2) P = 18 Q = 18 + 5 = 23 R = 18 + 3 = 21 => P/S = 3/4 => S = 4/3 x 18 = 24 Required Difference = S - R = 24 - 21 = 3.
प्र: Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 30% profit ? 2115 05b5cc6f1e4d2b4197774ef44
5b5cc6f1e4d2b4197774ef44- 1Rs. 17.80false
- 2Rs. 16.30true
- 3Rs. 14false
- 4Rs. 15.40false
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उत्तर : 2. "Rs. 16.30"
व्याख्या :
Answer: B) Rs. 16.30 Explanation: C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630. S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819. S.P. per kg = 819/50 = Rs. 16.38 = 16.30.
प्र: 40% of 265 + 35% of 180 = 50% of ? 2104 05b5cc75ce4d2b4197774fc57
5b5cc75ce4d2b4197774fc57- 1383false
- 2338true
- 384.5false
- 4253.5false
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उत्तर : 2. "338"
व्याख्या :
Answer: B) 338 Explanation: We know that 40% = 25 40% of 265 + 35% of 180 = 50% ? 25 x 265 + 35% of 180 = 50% ? We know that (35% of 180 = 180% of 35) & 180% = 95 25 x 265 + 95 x 35 = 50% ? 106 + 63 = 50% ? ?= 2 x 169 = 338.
प्र: Rushi and Arun are two business partners. They invest their capital in the ratio 7 : 9. After 6 months, a third person Ram joins them with a capital of two third of that of Arun. After a year, profit share of Rushi was Rs. 5600, then find total profit? 2097 05b5cc619e4d2b4197774b70f
5b5cc619e4d2b4197774b70f- 126,250false
- 219,200false
- 318,650,false
- 415,200true
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उत्तर : 4. "15,200"
व्याख्या :
Answer: D) 15,200 Explanation: Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6) = 7 : 9 : 3 Given Rushi's one year profit = Rs. 5600 => Let the total profit = Rs. P Then, P x 7/19 = 5600 Total profit P = 19 x 5600/7 = Rs. 15,200.
प्र: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 2096 05b5cc619e4d2b4197774b705
5b5cc619e4d2b4197774b705- 1720false
- 2360false
- 3120false
- 424true
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उत्तर : 4. "24"
व्याख्या :
Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.