Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A shopkeeper has a job to print certain number of documents and there are three machines P, Q and R for this job. P can complete the job in 3 days, Q can complete the job in 4 days and R can complete the job in 6 days. How many days the shopkeeper will it take to complete the job if all the machines are used simultaneously ? 2192 05b5cc758e4d2b4197774fbf4
5b5cc758e4d2b4197774fbf4- 14/3 daystrue
- 22 daysfalse
- 33/2 daysfalse
- 44 daysfalse
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उत्तर : 1. "4/3 days"
व्याख्या :
Answer: A) 4/3 days Explanation: Let the total number of documents to be printed be 12. The number of documents printed by P in 1 day = 4. The number of documents printed by Q in 1 day = 3. The number of documents printed by R in 1 day = 2. Thus, the total number of documents that can be printed by all the machines working simultaneously in a single day = 9. Therefore, the number of days taken to complete the whole work = 12/9 = 4/3 days.
प्र: 40% of 265 + 35% of 180 = 50% of ? 2192 05b5cc75ce4d2b4197774fc57
5b5cc75ce4d2b4197774fc57- 1383false
- 2338true
- 384.5false
- 4253.5false
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उत्तर : 2. "338"
व्याख्या :
Answer: B) 338 Explanation: We know that 40% = 25 40% of 265 + 35% of 180 = 50% ? 25 x 265 + 35% of 180 = 50% ? We know that (35% of 180 = 180% of 35) & 180% = 95 25 x 265 + 95 x 35 = 50% ? 106 + 63 = 50% ? ?= 2 x 169 = 338.
प्र: Which expression is equivalent to i233? 2190 05b5cc645e4d2b4197774bbd1
5b5cc645e4d2b4197774bbd1- 1itrue
- 21false
- 3-ifalse
- 4-1false
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उत्तर : 1. "i"
व्याख्या :
Answer: A) i Explanation: We know that, i2 = -1i3 = i2 x i = -1 x i = -ii4 = i2 x i2 = -1 x -1 = 1Hence, i233 =i4 x 58 + 1 = i232 x i1 = 1 x i = i
प्र: A train covers a distance between station A and station B in 45 min.If the speed of the train is reduced by 5 km/hr,then the same distance is covered in 48 min.what is the distance between the stations A and B ? 2189 05b5cc70ee4d2b4197774f347
5b5cc70ee4d2b4197774f347- 180 kmsfalse
- 260 kmstrue
- 345 kmsfalse
- 432 kmsfalse
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उत्तर : 2. "60 kms"
व्याख्या :
Answer: B) 60 kms Explanation: Let 'd' be the distance and 's' be the speed and 't' be the timed=sxt45 mins = 3/4 hr and 48 mins = 4/5 hrAs distance is same in both cases;s(3/4) = (s-5)(4/5)3s/4 = (4s-20)/515s = 16s-80s = 80 km.=> d = 80 x 3/4 = 60 kms.
प्र: The circumference of a circular base of Cylinder is 44 cm and its hight is 15 cm. Then the volume of the cylinder is? 2188 05b5cc6ade4d2b4197774d109
5b5cc6ade4d2b4197774d109- 12759 cub. cmfalse
- 22247 cub. cmfalse
- 32614 cub. cmfalse
- 42311 cub. cmtrue
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उत्तर : 4. "2311 cub. cm"
व्याख्या :
Answer: D) 2311 cub. cm Explanation: Given Circumference of a circular base of a cylinder = 44 cm We know that Circumference of a circle = 2πr = 44⇒r = 22π Now given the height of a cylinder h = 15 cm Volume of a cylinder V = πr2h = π22π215 = 22 x 22 x 153.14 = 2311 cm3.
प्र: How many four digit even numbers can be formed using the digits {2, 7, 5, 3, 9, 1} ? 2188 05b5cc6d7e4d2b4197774e705
5b5cc6d7e4d2b4197774e705- 159false
- 260true
- 361false
- 464false
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उत्तर : 2. "60"
व्याख्या :
Answer: B) 60 Explanation: The given digits are 1, 2, 3, 5, 7, 9 A number is even when its units digit is even. Of the given digits, two is the only even digit.Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways. Number of even numbers = ⁵P₃ = 60.
प्र: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 2188 15b5cc73ae4d2b4197774f8bf
5b5cc73ae4d2b4197774f8bf- 114th elementfalse
- 29th elementfalse
- 312th elementtrue
- 47th elementfalse
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उत्तर : 3. "12th element"
व्याख्या :
Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.
प्र: The ratio of Pens and Pencils in a shop is 3 : 2 respectively. The average number of Pens and Pencils is 180. What is the number of Pencils in the shop? 2187 05b5cc6a7e4d2b4197774ce18
5b5cc6a7e4d2b4197774ce18- 1444false
- 2344false
- 3244false
- 4144true
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उत्तर : 4. "144"
व्याख्या :
Answer: D) 144 Explanation: Given ratio of pens and pencils = 3 :2 Number of Pens = 3x Number of Pencils = 2x Average number of pencils & Pens = 3x + 2x2 = 180 5x = 360 => x = 72 Hence, the number of pencils = 2x = 72 x 2 = 144.