Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: How many remainders are possible if 16n is divided by 9 for any positive integral value of n ? 2191 05b5cc77ae4d2b41977750151
5b5cc77ae4d2b41977750151- 11false
- 22false
- 33true
- 44false
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उत्तर : 3. "3"
व्याख्या :
Answer: C) 3 Explanation: When 16nis divided by 9, we have 1619, remainder = 7 1629, remainder = 4 1639, remainder = 1 1649, remainder = 7 1659, remainder = 4 1669, remainder = 1 So, we have cyclicity of 3 factors i.e 7,4,1. Hence only 3 remainders are possible.
प्र: The number of ways that 8 beads of different colours be strung as a necklace is 2187 05b5cc7b4e4d2b4197775089c
5b5cc7b4e4d2b4197775089c- 12520true
- 22880false
- 34320false
- 45040false
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उत्तर : 1. "2520"
व्याख्या :
Answer: A) 2520 Explanation: The number of ways of arranging n beads in a necklace is (n-1)!2=(8-1)!2=7!2 = 2520 (since n = 8)
प्र: The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a. ? 2187 05b5cc6dde4d2b4197774ea19
5b5cc6dde4d2b4197774ea19- 1Rs. 22.5true
- 2Rs. 2.5false
- 3Rs. 202false
- 4Rs. 25false
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उत्तर : 1. "Rs. 22.5"
व्याख्या :
Answer: A) Rs. 22.5 Explanation: We know that I = PTR/100=> P = 20250/4.5 = 4500Now, new Interest at 5% = 4500x1x5/100 = 225Now the additional amount = 225 - 202.5 = Rs. 22.5
प्र: A is 3 times faster than B. If A can finish a work 32 days less than that of B, find the number of days need to finish the work if both are working together? 2179 05b5cc754e4d2b4197774fb62
5b5cc754e4d2b4197774fb62- 112 daystrue
- 224 daysfalse
- 332 daysfalse
- 416 daysfalse
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उत्तर : 1. "12 days"
व्याख्या :
Answer: A) 12 days Explanation: It is given that efficiency ratio =3:1 so time ratio will be 1:3 (since work is same) Also given that time diff = 32 days. ratio difference = 3-1 =2 2 ratio = 32 days 1 ratio = 16 days. So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days. Total work = LCM of 16 and 48 = 48. Total time = Total work/Total efficiency ie; 48/4= 12 days.
प्र: The average of the ages of Sumit, Krishna and Rishabh is 43 years and the average of the ages of Sumit, Rishabh and Rohit is 49 years. If Rohit is 54 years old, what is Krishna'a age ? 2176 05b5cc71be4d2b4197774f4f4
5b5cc71be4d2b4197774f4f4- 148 yrsfalse
- 242 yrsfalse
- 340 yrsfalse
- 436 yrstrue
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उत्तर : 4. "36 yrs"
व्याख्या :
Answer: D) 36 yrs Explanation: Let present ages of Sumit=w, Krishna=x, Rishabh=y and Rohit=z , thenw+x+y = 43x3 = 129 ---(i) andw+y+z = 49x3 = 147 ---(ii)Subtracting (i) from (ii), (w+y+z) - (w+x+y)=147 -129 , z- x =18 ---(iii)Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36
प्र: A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is ? 2172 05b5cc6d8e4d2b4197774e778
5b5cc6d8e4d2b4197774e778- 163false
- 231true
- 316false
- 427false
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उत्तर : 2. "31"
व्याख्या :
Answer: B) 31 Explanation: To get the least number of coconuts :LCM = 30 => 30 + 1 = 31
प्र: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 15%, he is only able to save Rs. 400 per month. What is his monthly salary ? 2171 05b5cc6e1e4d2b4197774ebf2
5b5cc6e1e4d2b4197774ebf2- 1Rs. 6000false
- 2Rs. 4500false
- 3Rs. 5000true
- 4Rs. 6500false
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उत्तर : 3. "Rs. 5000"
व्याख्या :
Answer: C) Rs. 5000 Explanation: Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80x(15/100) = Rs. 12 = 80 + 12 = Rs. 92 Present Savings = 100 – 92 = Rs. 8 100 ------ 8? --------- 400 => 5000 His salary = Rs. 5000
प्र: Find the odd one out? 6, 3, 3, 4.5, 10 2171 05b5cc698e4d2b4197774c670
5b5cc698e4d2b4197774c670- 13false
- 24.5false
- 36false
- 410true
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उत्तर : 4. "10"
व्याख्या :
Answer: D) 10 Explanation: Here the given number series is 6, 3, 3, 4.5, 10 The odd one in the given series is 10 The pattern it follows is 6 6 x 0.5 = 3 3 x 1 = 3 3 x 1.5 = 4.5 4.5 x 2 = 9 Hence, the odd number is 10.