Answer: D) Rs. 1,00,000 Explanation: Deepa invested Rs.50,000 for 12 months, Rs.(50000 + 20000) for 12 months and Rs.(50000 + 20000 + 20000) for 12 months.i.e, she invested Rs.50,000 for 12 months, Rs.70000 for 12 months and Rs.90000 for 12 months.Sushma invested Rs. 70000 for 2 years; i.e, Rs.70000 for 24 monthsAnd, Avanthi invested Rs.70000 for 1 year; i.e, Rs. 70000 for 12 months. Their investing ratio:Deepa : Sushma : Avanthi = (50,000 x 12 + 70000 x 12 + 90000 x 12):(70000 x 24):(70000 x 12)= (25,20,000):(16,80,000):(8,40,000) = 252:168:84 = 3:2:1 Total profit for 3 years = Rs.3,00,000Therefore, Sushma's share = Rs.(3,00,000 x 2 /(3+2+1)) = Rs.(3,00,000 x 2/6) = Rs.1,00,000.

Answer: C) 24,000 Explanation: Let K = Kalyan's monthly salaryN = Nandu's monthly salaryS = Sarnesh's monthly salary.Then from given data, 12% of K = 16% of NS = N/2 => N = 2SK = 16/12 x N = 16/12 x 2S= 16/6 x 1.08/12 = 16/6 x 0.09 = 0.24 lacs = 24,000

Answer: A) Sunday Explanation: The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 5th March, 2005 will be 1 day beyond the day on 5th March, 2004. Given that, 5th March, 2005 is Monday. 5th March, 2004 is Sunday (1 day before to 5th March, 2005).

Answer: A) 22 Explanation: Let the number be 'x'.       x+x22 = 11x x2= 22x => x = 22.

Answer: B) 14 lts Explanation: To know the the measuring cylinder that can fill all the given capacities , they must be divisible by the required number. 98,182,266 all are divisible by 14 So  14 litres  is the largest cylinder that can fill all the given cylinders.                                        (or) The other method is take HCF of all given capacities i.e 98, 182 and 266.

Answer: C) 40 Explanation: Given M.P=45,S.P=42, Profit = 0.05 Let C.P=x , Then Profit = (42-x)/x = 0.05=> x = 40.

Answer: A) 1/3 Explanation: In a family with 2 children there are four possibilities:1) the first child is a boy and the second child is a boy (bb)2) the first child is a boy and the second child is a girl (bg)3) the first child is a girl and the second child is a boy (gb)4) the first child is a girl and the second child is a girl (gg) But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).n(E)= both are boys=BB=1n(S)= 3Required probability P = n(E)/n(S) = 1/3.

Answer: C) 22 minutes Explanation: Let the two conditioners be A and B 'A' cools at 40min 'B' at 45min Together =(axb)/(a+b) = (45x40)/85 = 21.1764 = (approx) 22 min.