Quantitative Aptitude Practice Question and Answer
8Q: Sandeep got Rs. 6000 as his share out of the total profit of Rs. 9000 which he and Saketh earned at the end of one year. If Sandeep invested Rs. 20000 for 6 months, whereas Saketh invested his amount for the whole year, the amount invested by Saketh? 1276 05b5cc6a6e4d2b4197774cdd9
5b5cc6a6e4d2b4197774cdd9- 1Rs. 5000true
- 2Rs. 6200false
- 3Rs. 8100false
- 4R. 7600false
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Answer : 1. "Rs. 5000"
Explanation :
Answer: A) Rs. 5000 Explanation: Let the amount invested by saketh = RS. p Now, that of sandeep = 20,000 x 6 saketh = 12 x p Ratio of their earnings = 120000 : 12p = 6000 : (9000 - 6000) => 12000012p = 60003000 => p= Rs. 5000 Hence, the amount investe by saketh = Rs. p = Rs. 5000.
Q: एक कक्षा में 60% छात्र अंग्रेजी में और 45% हिंदी में उत्तीर्ण होते हैं। यदि उनमें से 25% दोनों विषयों में उत्तीर्ण होते हैं, तो कितने प्रतिशत छात्र दोनों विषयों में अनुत्तीर्ण होते हैं? 2634 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
- 225%false
- 330%false
- 415%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% स्पष्टीकरण: अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60% हिंदी में उत्तीर्ण छात्रों का प्रतिशत = 45% दोनों विषयों में उत्तीर्ण छात्रों का प्रतिशत = 25% एटीक्यू, केवल अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60 - 25 = 35% का प्रतिशत विद्यार्थी केवल हिंदी में उत्तीर्ण हुए = 45 - 25 = 20% इसलिए, अनुत्तीर्ण छात्रों का प्रतिशत = 100 - (35 + 25 + 20) = 100 - 80 = 20%।
Q: दी गई संख्या श्रंखला में गलत संख्या ज्ञात कीजिए? 10, 21, 54, 109, 189 8887 05b5cc607e4d2b4197774b553
5b5cc607e4d2b4197774b553- 1189true
- 2109false
- 354false
- 421false
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Answer : 1. "189"
Explanation :
Answer: A) 189 स्पष्टीकरण: दी गई संख्या श्रृंखला 10, 21, 54, 109, 189 है श्रृंखला एक पैटर्न का अनुसरण करती है कि 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186 इसलिए दिए गए में गलत संख्या संख्या श्रृंखला 189 है।
Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1458 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
- 23false
- 32true
- 41false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2
Q: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 2000 05b5cc619e4d2b4197774b705
5b5cc619e4d2b4197774b705- 1720false
- 2360false
- 3120false
- 424true
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Answer : 4. "24"
Explanation :
Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.
Q: The ratio of K’s and M’s ages is 4: 5. If the difference between the present age of M and the age of K, 5 years hence is 3 years, then what is the difference and total of present ages of K and M? 1476 05b5cc639e4d2b4197774ba7d
5b5cc639e4d2b4197774ba7d- 18, 72 yrstrue
- 216, 65 yrsfalse
- 312, 84 yrsfalse
- 410, 60 yrsfalse
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Answer : 1. "8, 72 yrs"
Explanation :
Answer: A) 8, 72 yrs Explanation: Let the present ages be K,M Given K/M = 4/5 5K - 4M = 0 ......(1) Also given that, M - (K + 5) = 3 M - K = 8 .........(2) Then, by solving (1) & (2) M = 40 yrs and K = 32 yrs Hence, Total of ages = 40 + 32 = 72 yrs Difference of ages = 40 - 32 = 8 yrs.
Q: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 1596 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
- 2203false
- 3150false
- 4113false
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Answer : 1. "277"
Explanation :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.
Q: A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold? 1612 05b5cc6a7e4d2b4197774cdef
5b5cc6a7e4d2b4197774cdef- 158 lfalse
- 265 lfalse
- 350 ltrue
- 462 lfalse
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Answer : 3. "50 l"
Explanation :
Answer: C) 50 l Explanation: Let the tin contain 5x litres of liquids 5x - 45 x 455x - 45 x 15 + 45 = 25 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 15 + 45 = 50 litres.