Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: How many square units in 13 by 9? 1801 05b5cc615e4d2b4197774b6b8
5b5cc615e4d2b4197774b6b8- 113false
- 29false
- 3117true
- 413/9false
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उत्तर : 3. "117"
व्याख्या :
Answer: C) 117 Explanation: Number of square units in 13 by 9 is given by the area it forms with length and breadth as 13 & 9 Area = 13 x 9 = 117 Hence, number of square units in 13 by 9 is 117 sq.units.
प्र: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 1975 05b5cc60ae4d2b4197774b5b5
5b5cc60ae4d2b4197774b5b5- 15 kmphtrue
- 26 kmphfalse
- 37.5 kmphfalse
- 48 kmphfalse
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उत्तर : 1. "5 kmph"
व्याख्या :
Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.
प्र: Find the next number in the given number series? 96, 95, 87, 78, ? 2343 05b5cc60ae4d2b4197774b5c9
5b5cc60ae4d2b4197774b5c9- 164false
- 257false
- 329false
- 414true
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उत्तर : 4. "14"
व्याख्या :
Answer: D) 14 Explanation: The given number series is 96, 95, 87, 78, ? It follows a pattern that, 9696 - 12 = 9595 - 23 = 95 - 8 = 8787 - 32 = 87 - 9 = 7878 - 43 = 78 - 64 = 14 Hence, the next number in the given number series is 14.
प्र: A number when subtracted by 1/7 th of itself gives the same value as the sum of all the angles of a triangle. What is the number? 1864 05b5cc619e4d2b4197774b700
5b5cc619e4d2b4197774b700- 1420false
- 2210true
- 370false
- 435false
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उत्तर : 2. "210"
व्याख्या :
Answer: B) 210 Explanation: Let the required number be 'p' We know, sum of angles in a triangle are 180 deg According to given data, p - p/7 = 180 7p - p = 180 x 7 => 6p = 1260 => p = 1260/6 = 210
प्र: एक कक्षा में 60% छात्र अंग्रेजी में और 45% हिंदी में उत्तीर्ण होते हैं। यदि उनमें से 25% दोनों विषयों में उत्तीर्ण होते हैं, तो कितने प्रतिशत छात्र दोनों विषयों में अनुत्तीर्ण होते हैं? 2883 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
- 225%false
- 330%false
- 415%false
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उत्तर : 1. "20%"
व्याख्या :
Answer: A) 20% स्पष्टीकरण: अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60% हिंदी में उत्तीर्ण छात्रों का प्रतिशत = 45% दोनों विषयों में उत्तीर्ण छात्रों का प्रतिशत = 25% एटीक्यू, केवल अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60 - 25 = 35% का प्रतिशत विद्यार्थी केवल हिंदी में उत्तीर्ण हुए = 45 - 25 = 20% इसलिए, अनुत्तीर्ण छात्रों का प्रतिशत = 100 - (35 + 25 + 20) = 100 - 80 = 20%।
प्र: दी गई संख्या श्रंखला में गलत संख्या ज्ञात कीजिए? 10, 21, 54, 109, 189 9135 05b5cc607e4d2b4197774b553
5b5cc607e4d2b4197774b553- 1189true
- 2109false
- 354false
- 421false
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उत्तर : 1. "189"
व्याख्या :
Answer: A) 189 स्पष्टीकरण: दी गई संख्या श्रृंखला 10, 21, 54, 109, 189 है श्रृंखला एक पैटर्न का अनुसरण करती है कि 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186 इसलिए दिए गए में गलत संख्या संख्या श्रृंखला 189 है।
प्र: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1589 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
- 23false
- 32true
- 41false
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उत्तर : 3. "2"
व्याख्या :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2
प्र: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 2098 05b5cc619e4d2b4197774b705
5b5cc619e4d2b4197774b705- 1720false
- 2360false
- 3120false
- 424true
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उत्तर : 4. "24"
व्याख्या :
Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.