Quantitative Aptitude Practice Question and Answer

Q: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is ? 4252 0

  • 1
    8 kmph
    Correct
    Wrong
  • 2
    6 kmph
    Correct
    Wrong
  • 3
    7.5 kmph
    Correct
    Wrong
  • 4
    5.5 kmph
    Correct
    Wrong
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Answer : 2. "6 kmph"
Explanation :

Answer: B) 6 kmph Explanation: Speed of the stream = 1Motor boat speed in still water be = x kmphDown Stream = x + 1 kmphUp Stream = x - 1 kmph[35/(x + 1)] + [35/(x - 1)] = 12x = 6 kmph

Q: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow ? 4231 0

  • 1
    3/17
    Correct
    Wrong
  • 2
    4/21
    Correct
    Wrong
  • 3
    2/21
    Correct
    Wrong
  • 4
    5/17
    Correct
    Wrong
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Answer : 3. "2/21"
Explanation :

Answer: C) 2/21 Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.   Probability that both marbles are blue = ³C₂/¹⁵C₂ = (3 x 2)/(15 x 14) = 1/35 Probability that both are yellow = ²C₂/¹⁵C₂ = (2 x 1)/(15 x 14) = 1/105 Probability that one blue and other is yellow = (³C₁ x ²C₁)/¹⁵C₂ = (2 x 3 x 2)/(15 x 14) = 2/35   Required probability = 1/35 + 1/105 + 2/35 = 3/35 + 1/105 = 1/35(3 + 1/3) = 10/(3 x 35) = 2/21

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Answer : 2. "26.166 minutes"
Explanation :

Answer: B) 26.166 minutes Explanation: Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120 For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120 So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120 So remaining tank = 13/120 Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes   Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.

Q: Karan started a business investing Rs 29000. After five months, Satish joined with a capital of Rs 18000. If at the end of the year, they earn a profit of Rs. 16970, then what will be the share of Satish in the profit ? 4203 0

  • 1
    Rs. 5422
    Correct
    Wrong
  • 2
    Rs. 5489
    Correct
    Wrong
  • 3
    Rs. 4511
    Correct
    Wrong
  • 4
    Rs. 6145
    Correct
    Wrong
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Answer : 3. "Rs. 4511"
Explanation :

Answer: C) Rs. 4511 Explanation: Now as per question, Karan invested for 12 months and Satish invested for 7 months. So, Karan:Satish = (29000 x 12):(18000 x 7) = 348:126 = 58:21   Satish Ratio in profit will be= 16970×2179 = Rs. 4511

Q: Find the odd one out ? Hawk ,  Parrot ,  Owl ,  Eagle 4202 0

  • 1
    Eagle
    Correct
    Wrong
  • 2
    Owl
    Correct
    Wrong
  • 3
    Parrot
    Correct
    Wrong
  • 4
    Hawk
    Correct
    Wrong
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Answer : 3. "Parrot"
Explanation :

Answer: C) Parrot Explanation: All except Parrot are birds of prey.

Q: In a class of 39 students the ratio of boys and girls is 2 : 1. Radhika ranks 15th among all the students from top and 8th among girls from bottom. How many boys are there below Radhika ? 4174 0

  • 1
    9
    Correct
    Wrong
  • 2
    17
    Correct
    Wrong
  • 3
    11
    Correct
    Wrong
  • 4
    15
    Correct
    Wrong
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Answer : 2. "17"
Explanation :

Answer: B) 17 Explanation: Total student= 39, boys : girls = 2:1, hence no of boys= 2/3(39)= 26num of girls= 1/3(39) = 13 , since radhika ranked 15 among 39 student from topand ranked 8 among girls from bottom , this means 7 girls are below radhika, rest 13-9= 5 girls are above her, now from 14 toper 5 are girls hence 14-5=9 boys.Hence num of boys below radhika are 26-9=17

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