Quantitative Aptitude Practice Question and Answer

Q: Find out the wrong number in the following series: 5, 15, 30, 80, 180, 540, 1080 4378 0

  • 1
    540
    Correct
    Wrong
  • 2
    180
    Correct
    Wrong
  • 3
    30
    Correct
    Wrong
  • 4
    80
    Correct
    Wrong
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Answer : 4. "80"
Explanation :

Answer: D) 80 Explanation: There should be 90 instead of 80so we can have a series5, 5x3, 15x2, 30x3, 90x2, 180x3, 540x2 and 1080x3 and so on...

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Answer : 1. "26"
Explanation :

Answer: A) 26 Explanation: Gold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600 Find a number which exactly divide all these numbers  That is HCF of 18000, 9600& 3600  All the value has 00 at end so the factor will also have 00. HCF for 180, 96 & 36.   Factors of   180 = 3 x 3 x 5 x 2 x 2 96 = 2 x 2 x 2 x 2 x 2 x 3  36 = 2 x 2 x 3 x 3  Common factors are 2x2×3=12  Therefore, Actual HCF is 1200      Gold Coins 18000/1200 will be in 15 rooms Silver Coins 9600/1200 will be in 8 rooms Bronze Coins 3600/1200 will be in 3 rooms Total rooms will be (15+8+3)  =  26 rooms.

Q: Find the Odd One Out of the following Number Series? 3, 14, 36, 67, 113, 168 4341 0

  • 1
    14
    Correct
    Wrong
  • 2
    36
    Correct
    Wrong
  • 3
    67
    Correct
    Wrong
  • 4
    113
    Correct
    Wrong
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Answer : 3. "67"
Explanation :

Answer: C) 67 Explanation: Here the given number series is 3, 14, 36, 67, 113, 168 It follows a pattern that 3 3 + 1 x 11 = 3 + 11 = 14 14 + 2 x 11 = 14 + 22 = 36 36 + 3 x 11 = 36 + 33 = 69 69 + 4 x 11 = 69 + 44 = 113 113 + 5 x 11 = 113 + 55 = 168   Hence, the wrong number is 67.

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Answer : 2. "6 mile/hr"
Explanation :

Answer: B) 6 mile/hr Explanation: Let the speed of river and boat be 'r' m/min and 'b' m/min.so relative speed in upstream (b-r)m/min and in downstream (b+r)m/min.Now in upstream distnce covered in 5 min is 5(b-r)milesso total distnce covered => 1 + 5(b-r)miles in upstreamIn downstream distance covered in 5min is 5(b+r)miles Now 1 + 5(b-r) = 5(b+r)1+5b-5r = 5b+5r1 = 10rr = 1/10 mile/min => 6 mile/hr.

Q: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ? 4327 0

  • 1
    50 yrs
    Correct
    Wrong
  • 2
    60 yrs
    Correct
    Wrong
  • 3
    70 yrs
    Correct
    Wrong
  • 4
    65 yrs
    Correct
    Wrong
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Answer : 2. "60 yrs"
Explanation :

Answer: B) 60 yrs Explanation: Let the Father be x years when he died Average Age 10 years ago be A Total Age 10 years ago = 6*A Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60 Father Died and Baby was born => the Total number of people in the family is Same (6) Baby born today so age of baby = 0 (6A +60 - x)/6 = 6A/6 => A + 10 -(x/6) = A => x/6 = 10 => x = 60 Therefore we can conclude that the father was 60 years old when he died.

Q: If log 64 = 1.8061, then the value of log 16 will be (approx)? 4298 0

  • 1
    1.9048
    Correct
    Wrong
  • 2
    1.2040
    Correct
    Wrong
  • 3
    0.9840
    Correct
    Wrong
  • 4
    1.4521
    Correct
    Wrong
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Answer : 2. "1.2040"
Explanation :

Answer: B) 1.2040 Explanation: Given that, log 64 = 1.8061  i.e log43=1.8061  --> 3 log 4 = 1.8061 --> log 4 = 0.6020 --> 2 log 4 = 1.2040 ⇒log42=1.2040 Therefore, log 16 = 1.2040

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Answer : 4. "Rs. 15000"
Explanation :

Answer: D) Rs. 15000 Explanation: It won't requires that much solving. Here given the increase in weekly collection by Rs. 1,05,000 That is this increase denotes for all 7 days. => Gross Collection increase per day = Rs. 1,05,0007 = Rs. 15,000 Hence, the gross collection increase per day = Rs. 15,000.

Q: Find the one which does not belong to that group ? 4253 0

  • 1
    KMNL
    Correct
    Wrong
  • 2
    JLMK
    Correct
    Wrong
  • 3
    PRSQ
    Correct
    Wrong
  • 4
    VWYZ
    Correct
    Wrong
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Answer : 4. "VWYZ"
Explanation :

Answer: D) VWYZ Explanation: K+2 M+1 N-2 L,  P+2 R+1 S-2 Q,   V+1 W+2 Y+1 Z,   J+2 L+1 M-2 K  and  W+2 Y+1 Z-2 X. Except VWYZ, all the other groups follow similar pattern.

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