Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Anil purchases two books for Rs.100. He sells first at loss of 5% and second al 20% profit. If he gets Overall profit of 5% then what is cost of first book? 1692 05b5cc60de4d2b4197774b61d
5b5cc60de4d2b4197774b61d- 158false
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उत्तर : 2. "60"
व्याख्या :
Answer: B) 60 Explanation: -5-----------------------5-------------------20 5-(-5) = 10 20-5= 15 Ratio of cost price of book1 and book2 = 3:2 Then cost price of book 1 is given by (3/5) x 100 = Rs. 60.
प्र: Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev? 2028 05b5cc655e4d2b4197774bd70
5b5cc655e4d2b4197774bd70- 112false
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उत्तर : 4. "10"
व्याख्या :
Answer: D) 10 Explanation: Let Rajeev's present age be x years. Rajeev's age after 15 years = (x + 15) years. Rajeev's age 5 years back = (x - 5) years Then ATQ, x + 15 = 5 (x - 5) x + 15 = 5x - 25 => x = 10 Hence, Rajeev's present age = x = 10 years.
प्र: एक कक्षा में 60% छात्र अंग्रेजी में और 45% हिंदी में उत्तीर्ण होते हैं। यदि उनमें से 25% दोनों विषयों में उत्तीर्ण होते हैं, तो कितने प्रतिशत छात्र दोनों विषयों में अनुत्तीर्ण होते हैं? 2883 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
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उत्तर : 1. "20%"
व्याख्या :
Answer: A) 20% स्पष्टीकरण: अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60% हिंदी में उत्तीर्ण छात्रों का प्रतिशत = 45% दोनों विषयों में उत्तीर्ण छात्रों का प्रतिशत = 25% एटीक्यू, केवल अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60 - 25 = 35% का प्रतिशत विद्यार्थी केवल हिंदी में उत्तीर्ण हुए = 45 - 25 = 20% इसलिए, अनुत्तीर्ण छात्रों का प्रतिशत = 100 - (35 + 25 + 20) = 100 - 80 = 20%।
प्र: दी गई संख्या श्रंखला में गलत संख्या ज्ञात कीजिए? 10, 21, 54, 109, 189 9135 05b5cc607e4d2b4197774b553
5b5cc607e4d2b4197774b553- 1189true
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उत्तर : 1. "189"
व्याख्या :
Answer: A) 189 स्पष्टीकरण: दी गई संख्या श्रृंखला 10, 21, 54, 109, 189 है श्रृंखला एक पैटर्न का अनुसरण करती है कि 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186 इसलिए दिए गए में गलत संख्या संख्या श्रृंखला 189 है।
प्र: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1590 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
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उत्तर : 3. "2"
व्याख्या :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2
प्र: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 2098 05b5cc619e4d2b4197774b705
5b5cc619e4d2b4197774b705- 1720false
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उत्तर : 4. "24"
व्याख्या :
Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.
प्र: The ratio of K’s and M’s ages is 4: 5. If the difference between the present age of M and the age of K, 5 years hence is 3 years, then what is the difference and total of present ages of K and M? 1557 05b5cc639e4d2b4197774ba7d
5b5cc639e4d2b4197774ba7d- 18, 72 yrstrue
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उत्तर : 1. "8, 72 yrs"
व्याख्या :
Answer: A) 8, 72 yrs Explanation: Let the present ages be K,M Given K/M = 4/5 5K - 4M = 0 ......(1) Also given that, M - (K + 5) = 3 M - K = 8 .........(2) Then, by solving (1) & (2) M = 40 yrs and K = 32 yrs Hence, Total of ages = 40 + 32 = 72 yrs Difference of ages = 40 - 32 = 8 yrs.
प्र: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 1718 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
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उत्तर : 1. "277"
व्याख्या :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.