Quantitative Aptitude Practice Question and Answer

Q: दो धनात्मक संख्याओं का अनुपात 3 : 5 है और संख्या का औसत 48 है। संख्याओं का गुणनफल क्या है? 2757 1

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    3365
    Correct
    Wrong
  • 2
    2160
    Correct
    Wrong
  • 3
    1854
    Correct
    Wrong
  • 4
    1632
    Correct
    Wrong
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Answer : 2. "2160"
Explanation :

Answer: B) 2160 स्पष्टीकरण: माना संख्या 3p और 5p ATQ, 8p = 2 x 48 p = 96/8 p = 12 संख्याएँ 36 और 60 हैं। इसलिए, संख्याओं का गुणनफल = 36 x 60 = 2160।

Q: What is the common ratio of the following geometric sequence? 4, 2, 1, 0.5, 0.25, 0.125,... 1997 0

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    0.5
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    Wrong
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    -1
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    1.5
    Correct
    Wrong
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    -0.5
    Correct
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Answer : 1. "0.5"
Explanation :

Answer: A) 0.5 Explanation: In mathematics, a geometric progression, also known as a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.   Herein the given sequence, 4, 2, 1, 0.5, 0.25, 0.125,... Common Ratio r = 2/4 = 1/2 = 0.5/1 = 0.25/0.5 = 0.125/0.25 == 0.5.

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Answer : 1. "20%"
Explanation :

Answer: A) 20% स्पष्टीकरण: अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60% हिंदी में उत्तीर्ण छात्रों का प्रतिशत = 45% दोनों विषयों में उत्तीर्ण छात्रों का प्रतिशत = 25% एटीक्यू, केवल अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60 - 25 = 35% का प्रतिशत विद्यार्थी केवल हिंदी में उत्तीर्ण हुए = 45 - 25 = 20% इसलिए, अनुत्तीर्ण छात्रों का प्रतिशत = 100 - (35 + 25 + 20) = 100 - 80 = 20%।

Q: दी गई संख्या श्रंखला में गलत संख्या ज्ञात कीजिए? 10, 21, 54, 109, 189 8887 0

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    189
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    Wrong
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    109
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    Wrong
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    54
    Correct
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    21
    Correct
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Answer : 1. "189"
Explanation :

Answer: A) 189 स्पष्टीकरण: दी गई संख्या श्रृंखला 10, 21, 54, 109, 189 है श्रृंखला एक पैटर्न का अनुसरण करती है कि 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186 इसलिए दिए गए में गलत संख्या संख्या श्रृंखला 189 है।

Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1456 0

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    4
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    3
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    2
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    1
    Correct
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Answer : 3. "2"
Explanation :

Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a)   2(3b + 2g) = 7 6b + 4g = 7 ........(b)   Solving (a) & (b), we get b = 1, g = 1/4   Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2.   Hence, number of girls required = 2

Q: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 1999 0

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    720
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    Wrong
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    360
    Correct
    Wrong
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    120
    Correct
    Wrong
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    24
    Correct
    Wrong
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Answer : 4. "24"
Explanation :

Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.

Q: The ratio of K’s and M’s ages is 4: 5. If the difference between the present age of M and the age of K, 5 years hence is 3 years, then what is the difference and total of present ages of K and M? 1475 0

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    8, 72 yrs
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    Wrong
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    16, 65 yrs
    Correct
    Wrong
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    12, 84 yrs
    Correct
    Wrong
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    10, 60 yrs
    Correct
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Answer : 1. "8, 72 yrs"
Explanation :

Answer: A) 8, 72 yrs Explanation: Let the present ages be K,M Given K/M = 4/5 5K - 4M = 0 ......(1) Also given that, M - (K + 5) = 3 M - K = 8 .........(2) Then, by solving (1) & (2) M = 40 yrs and K = 32 yrs Hence, Total of ages = 40 + 32 = 72 yrs Difference of ages = 40 - 32 = 8 yrs.

Q: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 1596 0

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    277
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    Wrong
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    203
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    Wrong
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    150
    Correct
    Wrong
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    113
    Correct
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Answer : 1. "277"
Explanation :

Answer: A) 277 Explanation: The given number series is    71      88       113       150       203          277    +17    +25       +37      +53        +74         +8      +12        +16       +21             +4          +4         +5   The series should be  71  88  112   150    203   276 i.e, the differences of the difference should be +4.   Hence, the odd man in the given series is 277.

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