Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: The average monthly salary of 24 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 400. What is the manager's monthly salary ? 1799 05b5cc6e1e4d2b4197774ebe3
5b5cc6e1e4d2b4197774ebe3- 1Rs. 8840false
- 2Rs. 11,500true
- 3Rs. 12,800false
- 4Rs. 9450false
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उत्तर : 2. "Rs. 11,500"
व्याख्या :
Answer: B) Rs. 11,500 Explanation: Manager's monthly salary = Rs. (1900 x 25 - 1500 x 24) = Rs. 11,500
प्र: A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27, what is the total amount ? 1798 05b5cc6e0e4d2b4197774eb66
5b5cc6e0e4d2b4197774eb66- 1Rs. 159false
- 2Rs. 96false
- 3Rs. 147false
- 4Rs. 105true
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उत्तर : 4. "Rs. 105"
व्याख्या :
Answer: D) Rs. 105 Explanation: K : L : M = 100 : 45 : 30 = 20 : 9 : 6 Given L share is 27 => 9 ------ 27 35 ------ ? => 105
प्र: If price of rice increased by 25%, so that a man is can able to purchase 5 kg less rice in Rs. 500. Find the original price of rice per kg ? 1797 05b5cc6c3e4d2b4197774dc31
5b5cc6c3e4d2b4197774dc31- 1Rs. 20true
- 2Rs. 24false
- 3Rs. 26false
- 4Rs. 29false
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उत्तर : 1. "Rs. 20"
व्याख्या :
Answer: A) Rs. 20 Explanation: Let the original price of rice be Rs. x Let rice a man can buy for Rs. 500 at rs. x/kg be = R kgs From given data, for Rs. 500 x ---- R kgs (x + 25x/100) ---- (R - 5) kgs => Rx = (R - 5)(x + 25x/100) => Rx = (R - 5)(125x/100) => 100Rx = 125Rx - 625x => R = 25 So at rate of Rs. x/kg, man get 25 kgs for Rs. 500 => x = 500/25 = Rs. 20
प्र: 270 मीटर लम्बी एक रेलगाड़ी 10 किमी/घंटा की चाल से चल रही हैं। विपरीत दिशा से 80 किमी/घंटा की चाल से आ रही है एक दूसरी को 20 सैकण्ड में पार कर जाती है। दूसरी गाड़ी की लम्बाई क्या है? 1796 05d15e01044a3a75f13296b30
5d15e01044a3a75f13296b30- 1240 मीटरfalse
- 2320 मीटरfalse
- 3260 मीटरfalse
- 4230 मीटरtrue
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उत्तर : 4. "230 मीटर"
प्र: A shop keeper sells an article at a loss of 8%, but when he increases the selling price of the article by Rs. 164 he earns a profit of 2.25% on the cost price. If he sells the same article at Rs. 1760, what is his profit percentage? 1796 05b5cc62ae4d2b4197774b89f
5b5cc62ae4d2b4197774b89f- 12.5%false
- 25%false
- 310%true
- 47.5%false
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उत्तर : 3. "10%"
व्याख्या :
Answer: C) 10% Explanation: According to the given data, Let Cost price of the article be 'cp' Then, 102.25 cp - 92 cp = 164 x 100 10.25 cp = 16400 cp = 1600 Now, if he sells at Rs. 1760 Profit = 1760 - 1600 = 160 Profit% = 160/1600 x 100 = 10%.
प्र: What comes next in this sequence 196, 169, 144, 121, 100, 81, ? 1795 05b5cc6ade4d2b4197774d13e
5b5cc6ade4d2b4197774d13e- 177false
- 274false
- 367false
- 464true
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उत्तर : 4. "64"
व्याख्या :
Answer: D) 64 Explanation: The given number series follows a pattern that 196, 169, 144, 121, 100, 81, ? -27 -25 -23 -21 -19 -17 => 81 - 17 = 64 Therefore, the series is 196, 169, 144, 121, 100, 81, 64.
प्र: If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream. 1794 05b5cc6afe4d2b4197774d278
5b5cc6afe4d2b4197774d278- 12.8 hrsfalse
- 22.7 hrstrue
- 32.6 hrsfalse
- 42.5 hrsfalse
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उत्तर : 2. "2.7 hrs"
व्याख्या :
Answer: B) 2.7 hrs Explanation: Let Speed of boat in still water = b Let Speed of still water = w Then we know that, Speed of Upstream = U = boat - water Speed of Downstream = D = boat + water Given, U + D = 82 b - w + b + w = 82 2b = 82 => b = 41 kmph From the given data, 41 - w = 105/3 = 35 w = 6 kmph Now, b + w = 126/t => 41 + 6 = 126/t => t = 126/47 = 2.68 hrs.
प्र: A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after ? 1794 05b5cc71ee4d2b4197774f5b8
5b5cc71ee4d2b4197774f5b8- 119 monthsfalse
- 221 monthstrue
- 318 monthsfalse
- 420 monthsfalse
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उत्तर : 2. "21 months"
व्याख्या :
Answer: B) 21 months Explanation: Total savings = 200 + 200 + 200 + 240 + 280 + ... to n months = 11040 = 120 + 80 + 160 + 40 + 200 + 240 + ....n terms= 40 + 80 + 120 + 160 + 200 + 240 + ...n terms= n/2[2a + (n-1)d] + 80 + 40 = 11040= n/2[240 + (n-1)40] = 10920= n[6+n-1] = 546= n[n+5] = 546n = 21