Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: When 0.46 is written in simplest form, the sum of the numerator and the denominator is ? 1831 05b5cc6dee4d2b4197774ea9e
5b5cc6dee4d2b4197774ea9e- 169false
- 273true
- 396false
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उत्तर : 2. "73"
व्याख्या :
Answer: B) 73 Explanation: 0.46 = 46/100 = 23/50. Sum of the numerator and denominator is 23 + 50 = 73
प्र: पाँच संख्याओं का औसत 49 है। पहली और दूसरी संख्याओं का औसत 48 है और चौथे और पाँचवे नंबरों का औसत 28 है। तीसरा नंबर क्या है?
1825 05d4a9cab11160f20523711a5
5d4a9cab11160f20523711a5- 192false
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- 4निर्धारित नहीं किया जा सकताfalse
- 5इनमें से कोई नहींtrue
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उत्तर : 5. "इनमें से कोई नहीं"
प्र: A and B started a business investing the money in ratio 4:6, after 6 months B withdraw his investment and C joins him with twice the amount of B. At the end of the year total profit is Rs.3315. Find share of C ? 1824 05b5cc6c5e4d2b4197774ddd7
5b5cc6c5e4d2b4197774ddd7- 1Rs. 450false
- 2Rs. 1020false
- 3Rs. 765false
- 4Rs. 1530true
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उत्तर : 4. "Rs. 1530"
व्याख्या :
Answer: D) Rs. 1530 Explanation: Ratio of investments of A, B & C => Share of C = 1530 Share of B = 765 Share of A = 1020
प्र: Total 100 members are writing exam. In that 48 members are writing first exam, 45 members are writing second exam and 38 members are writing third exam. 5 members are writing all the three exams. How many members are writing 2 exams ? 1823 05b5cc6fbe4d2b4197774f0a4
5b5cc6fbe4d2b4197774f0a4- 126false
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उत्तर : 4. "21"
व्याख्या :
Answer: D) 21 Explanation: Total number of exams written by 100 students = 48 + 45 + 38 = 131Now let us say x members are writing only 1 exam, y members are writing only 2 exams, z members are writing only 3 exams.Therefore, x + 2y + 3z = 131 also x + y + z = 100.Given that z = 5. So x + 2y = 116 and x + y = 95.Solving we get y = 21.So 21 members are writing exactly 2 exams.
प्र: A house owner wants to get his house painted. He is told that this would require 45 kg of paint allowing 6% wasting. And if the paint is available in 4 kg tins only, the number of tins required for painting the house is ? 1823 05b5cc6d1e4d2b4197774e3e3
5b5cc6d1e4d2b4197774e3e3- 112true
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उत्तर : 1. "12"
व्याख्या :
Answer: A) 12 Explanation: Given 45 kg for painting And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg Now total paint required = 45+2.7 = 47.7 kgs But tins are available in only 4kgs Then, no. of tins req = 47.7/4 = 11.4 => 12 tins
प्र: Ravi and Ramu are partners in a business.Ravi contributes 1/6 of the capital for 16 months and Ramu received 2/3 of the profit. For how long Ramu's money was used ? 1822 05b5cc71ee4d2b4197774f590
5b5cc71ee4d2b4197774f590- 111 monthsfalse
- 210 monthsfalse
- 39 monthsfalse
- 48 monthstrue
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उत्तर : 4. "8 months"
व्याख्या :
Answer: D) 8 months Explanation: Let the total Profit be Z.Ramu's profit share is 2/3 of profit (i.e 2Z/3)Ravi's profit is (Z-2Z/3) =Z/3Hence the profit ratio is , Ravi : Ramu = Z/3 : 2Z/3 = 1:2 Let total Capital be Rs.X and Ramu has contributed for Y months.Since Ramu's profit share is 2/3, his invest share will be 2/3 in capital. Ravi's invest for 16 months / Ramu's invest for Y months = Ravi's profit share / Ramu's profit sharei.e. (X/6 x 16) / (2X/3 x Y) = 1/2 Solving the above equation, we get Y = 8.So Ramu's money has been used for 8 months.
प्र: If the given two numbers are respectively 7% and 28% of a third number, then what percentage is the first of the second ? 1817 05b5cc75ce4d2b4197774fc48
5b5cc75ce4d2b4197774fc48- 124%false
- 229%false
- 334%false
- 425%true
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उत्तर : 4. "25%"
व्याख्या :
Answer: D) 25% Explanation: Here, k = 7 and l = 28Therefore, first number = klx100 % of second number = 7/28 x 100% of second number = 25% of second number.
प्र: If a+b=5 and 3a+2b=20,then (3a+b)will be : 1817 05b5cc783e4d2b419777501fb
5b5cc783e4d2b419777501fb- 120false
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- 325true
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उत्तर : 3. "25"
व्याख्या :
Answer: C) 25 Explanation: a+b=5 ...(1) and 3a+2b=20 ...(2) Multiplying (1) by 2 and subtracting from (2), we get : a=10. Putting a=10 in (1), we get : b=-5 Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.