Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: How many three digit numbers 'abc' are formed where two of the three digits are same ? 1392 05b5cc701e4d2b4197774f1b7
5b5cc701e4d2b4197774f1b7- 1252false
- 2648false
- 3243true
- 4900false
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 3. "243"
व्याख्या :
Answer: C) 243 Explanation: Digits are 0,1,2,3,4,5,6,7,8,9. So no. of digits are 10 First all possible case => 9(0 excluded) x 10 x 10 = 900 Second no repetition allowed =>9 x 9 x 8 = 648 Third all digits are same => 9 (111,222,333,444,555,666,777,888,999) Three digit numbers where two of the three digits are same = 900 - 648 - 9 = 243 ;
प्र: The sum of the digits of a two-digits number is 10,while when the digits are reversed, the number decreases by 54. Find the changed number ? 1609 05b5cc701e4d2b4197774f1b2
5b5cc701e4d2b4197774f1b2- 128true
- 219false
- 337false
- 446false
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 1. "28"
व्याख्या :
Answer: A) 28 Explanation: Let the original number is 82 i.e 8 + 2 = 10 and when the digits are reversed i.e 28The difference is 82 - 28 = 54 i.e, the number is decreased by 54.
प्र: Find the principal if the interest compounded at the rate of 10% per annum for two years is Rs. 420 ? 1140 05b5cc701e4d2b4197774f17a
5b5cc701e4d2b4197774f17a- 1Rs. 2000true
- 2Rs. 2100false
- 3Rs. 1900false
- 4Rs. 2150false
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 1. "Rs. 2000"
व्याख्या :
Answer: A) Rs. 2000 Explanation: Given, Compound rate, R = 10% per annumTime = 2 yearsC.I = Rs. 420Let P be the required principal.A = (P+C.I)Amount, A = P1 + r100n (P+C.I) = P1 + 101002 (P+420) = P[11/10][11/10] P-1.21P = -420 0.21P = 420 Hence, P = 420/0.21 = Rs. 2000
प्र: In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ? 2500 05b5cc701e4d2b4197774f175
5b5cc701e4d2b4197774f175- 1Quarter monthsfalse
- 2Half yeartrue
- 32 yearsfalse
- 41 yearfalse
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 2. "Half year"
व्याख्या :
Answer: B) Half year Explanation: 3300 ----- 3% ↑ (1st time interval, 99) → 3399. Here, time interval is given as half-yearly i.e. 6 months.
प्र: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 1732 05b5cc701e4d2b4197774f170
5b5cc701e4d2b4197774f170- 1Rs. 1,24,000false
- 2Rs. 1,44,000true
- 3Rs. 1,32,000false
- 4Rs. 1,62,000false
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 2. "Rs. 1,44,000"
व्याख्या :
Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.
प्र: Althaf borrows Rs. 1500 from two moneylenders. He pays interest at the rate of 12% per annum for one loan and at the rate of 14% per annum for the other. The total interest he pays for the entire year is Rs. 186. How much does he borrow at the rate of 12% ? 2557 05b5cc6fee4d2b4197774f166
5b5cc6fee4d2b4197774f166- 1Rs. 300false
- 2Rs. 400false
- 3Rs. 1200true
- 4Rs. 1100false
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 3. "Rs. 1200"
व्याख्या :
Answer: C) Rs. 1200 Explanation: Let Althaf lent Rs. A at 14% per year.Hence, Money lent at 12% = (1500-A);Given, total interest = Rs. 186.{(A x 14x 1)/100} + {[(1500-A) x 12 x 1/100]} = 186;14A/100 + (18000 -12A)/100 = 186;14A + 18000 - 12A = 186x100;2A = 18600-18000;A = 600/2 = Rs. 300.Hence, money lent at 12% = 1500-300 = Rs. 1200.
प्र: A user type a content on 20 sheets, each sheet consist of 55 lines, and each line can have 66 characters. The content is again retyped on another set of sheets, these new sheets have 65 lines and each line can take 70 characters. Calculate the reduction in sheets ? 2476 05b5cc6fee4d2b4197774f15c
5b5cc6fee4d2b4197774f15c- 12 or 60%false
- 24 or 20%true
- 36 or 10%false
- 48 or 5%false
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 2. "4 or 20%"
व्याख्या :
Answer: B) 4 or 20% Explanation: 20 x 55 x 66 = L x 65 x 70Here L = 72,600/4550 = 15.95 =~ 16Reduction is 20-16 = 4 which is 20% reduction.
प्र: If 6 (P's Capital ) = 8 ( Q's Capital ) = 12 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive ? 1576 05b5cc6fee4d2b4197774f161
5b5cc6fee4d2b4197774f161- 1Rs. 1033.33true
- 2Rs. 1024false
- 3Rs. 1148.14false
- 4Rs. 1245.32false
- उत्तर देखें
- Workspace
- SingleChoice
उत्तर : 1. "Rs. 1033.33"
व्याख्या :
Answer: A) Rs. 1033.33 Explanation: Let P's capital = p, Q's capital = q and R's capital = r.Then 6p = 8q = 12r=> 3p = 4q = 6r=>q = 3p/4r = 3p/6 = p/2P : Q : R = p : 3p/4 : p/2= 4 : 3 : 2R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.