Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 1981 05b5cc75ee4d2b4197774fcc0
5b5cc75ee4d2b4197774fcc0- 127 %true
- 226 %false
- 329 %false
- 421 %false
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उत्तर : 1. "27 %"
व्याख्या :
Answer: A) 27 % Explanation: Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %
प्र: If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ? 1979 05b5cc73ae4d2b4197774f8a1
5b5cc73ae4d2b4197774f8a1- 131/25false
- 215/17true
- 314/25false
- 411/16false
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उत्तर : 2. "15/17"
व्याख्या :
Answer: B) 15/17 Explanation: The original fraction is 2551 × 350+100150+100 = 15/17.
प्र: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 1978 05b5cc60ae4d2b4197774b5b5
5b5cc60ae4d2b4197774b5b5- 15 kmphtrue
- 26 kmphfalse
- 37.5 kmphfalse
- 48 kmphfalse
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उत्तर : 1. "5 kmph"
व्याख्या :
Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.
प्र: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 1975 05b5cc73ae4d2b4197774f8ab
5b5cc73ae4d2b4197774f8ab- 12101 hrsfalse
- 24125 hrsfalse
- 35124 hrsfalse
- 46011 hrstrue
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उत्तर : 4. "6011 hrs"
व्याख्या :
Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
प्र: Three milkmen rented a pasture. A grazed 24 cows for 4 months; B 10 cows for 6 months; C 56 cows for 5 months. If A's share of rent is Rs. 960, find the total rent of the field? 1973 05b5cc783e4d2b419777501f1
5b5cc783e4d2b419777501f1- 14530false
- 24440false
- 34360true
- 44280false
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उत्तर : 3. "4360"
व्याख्या :
Answer: C) 4360 Explanation: Ratio of shares of A,B,C = (24 x 4) : (10 x 6) : (56 x 5) = 96 : 60 : 280. Let total rent be Rs. x. Then, A's share = Rs.96x436 ∴96x436=960 ⇔x=960×43696=4360 Hence total rent of the field is Rs. 4360.
प्र: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 1973 05b5cc728e4d2b4197774f6dc
5b5cc728e4d2b4197774f6dc- 135false
- 2165true
- 3221false
- 477false
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उत्तर : 2. "165"
व्याख्या :
Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.
प्र: The capacity of a tank is 2400 m3. A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 m3/minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump. 1972 05b5cc6b1e4d2b4197774d332
5b5cc6b1e4d2b4197774d332- 146 cub.m/minfalse
- 244 cub.m/minfalse
- 348 cub.m/minfalse
- 450 cub.m/mintrue
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उत्तर : 4. "50 cub.m/min"
व्याख्या :
Answer: D) 50 cub.m/min Explanation: Let filling capacity of the pump be 'F' m3/min Then, the filling capacity of the pump will be (F + 10) m3/min From the given data, 2400F - 2400F+10= 8⇒ 2400 F+10-FF(F+10) =8⇒ F2 + 10F - 3000 = 0⇒ F = 50 m3/min
प्र: 5% of a number is 25% more than another number. The difference between the numbers is 96. Then find the value of the numbers? 1971 05b5cc6bbe4d2b4197774d80c
5b5cc6bbe4d2b4197774d80c- 1102 & 6false
- 299 & 3false
- 3104 & 8false
- 4100 & 4true
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उत्तर : 4. "100 & 4"
व्याख्या :
Answer: D) 100 & 4 Explanation: Let the first number be x and the second number be y. Given 5% of x = (25% of y) + y => 5x/100 = 5y/4 => x = 25y ......(1) and also given that, x - y = 96 => x = 96 + y .....(2) From (1)&(2) 25y = 96 + y => 24y = 96 => y = 4 From (1) x = 96 + 4 = 100 Hence, the numbers are 100 & 4.