Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 1972 05b5cc728e4d2b4197774f6dc
5b5cc728e4d2b4197774f6dc- 135false
- 2165true
- 3221false
- 477false
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उत्तर : 2. "165"
व्याख्या :
Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.
प्र: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 1971 05b5cc73ae4d2b4197774f8ab
5b5cc73ae4d2b4197774f8ab- 12101 hrsfalse
- 24125 hrsfalse
- 35124 hrsfalse
- 46011 hrstrue
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उत्तर : 4. "6011 hrs"
व्याख्या :
Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
प्र: Three milkmen rented a pasture. A grazed 24 cows for 4 months; B 10 cows for 6 months; C 56 cows for 5 months. If A's share of rent is Rs. 960, find the total rent of the field? 1968 05b5cc783e4d2b419777501f1
5b5cc783e4d2b419777501f1- 14530false
- 24440false
- 34360true
- 44280false
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उत्तर : 3. "4360"
व्याख्या :
Answer: C) 4360 Explanation: Ratio of shares of A,B,C = (24 x 4) : (10 x 6) : (56 x 5) = 96 : 60 : 280. Let total rent be Rs. x. Then, A's share = Rs.96x436 ∴96x436=960 ⇔x=960×43696=4360 Hence total rent of the field is Rs. 4360.
प्र: A sold an article to B at 40% profit and B sold it to C at 50% profit, then what will be profit percent with respect to A ? 1968 05b5cc6e9e4d2b4197774ee3c
5b5cc6e9e4d2b4197774ee3c- 197 %false
- 2110 %true
- 3135 %false
- 4115 %false
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उत्तर : 2. "110 %"
व्याख्या :
Answer: B) 110 % Explanation: % Profit with respect to A = 40 + 50 + (40 x 50)/100 = 90 + 20 = 110 %.
प्र: The capacity of a tank is 2400 m3. A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 m3/minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump. 1967 05b5cc6b1e4d2b4197774d332
5b5cc6b1e4d2b4197774d332- 146 cub.m/minfalse
- 244 cub.m/minfalse
- 348 cub.m/minfalse
- 450 cub.m/mintrue
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उत्तर : 4. "50 cub.m/min"
व्याख्या :
Answer: D) 50 cub.m/min Explanation: Let filling capacity of the pump be 'F' m3/min Then, the filling capacity of the pump will be (F + 10) m3/min From the given data, 2400F - 2400F+10= 8⇒ 2400 F+10-FF(F+10) =8⇒ F2 + 10F - 3000 = 0⇒ F = 50 m3/min
प्र: The ratio of Pens and Pencils in a shop is 3 : 2 respectively. The average number of Pens and Pencils is 180. What is the number of Pencils in the shop? 1965 05b5cc6a7e4d2b4197774ce18
5b5cc6a7e4d2b4197774ce18- 1444false
- 2344false
- 3244false
- 4144true
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उत्तर : 4. "144"
व्याख्या :
Answer: D) 144 Explanation: Given ratio of pens and pencils = 3 :2 Number of Pens = 3x Number of Pencils = 2x Average number of pencils & Pens = 3x + 2x2 = 180 5x = 360 => x = 72 Hence, the number of pencils = 2x = 72 x 2 = 144.
प्र: 5% of a number is 25% more than another number. The difference between the numbers is 96. Then find the value of the numbers? 1964 05b5cc6bbe4d2b4197774d80c
5b5cc6bbe4d2b4197774d80c- 1102 & 6false
- 299 & 3false
- 3104 & 8false
- 4100 & 4true
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उत्तर : 4. "100 & 4"
व्याख्या :
Answer: D) 100 & 4 Explanation: Let the first number be x and the second number be y. Given 5% of x = (25% of y) + y => 5x/100 = 5y/4 => x = 25y ......(1) and also given that, x - y = 96 => x = 96 + y .....(2) From (1)&(2) 25y = 96 + y => 24y = 96 => y = 4 From (1) x = 96 + 4 = 100 Hence, the numbers are 100 & 4.
प्र: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 1963 05b5cc6bfe4d2b4197774da0a
5b5cc6bfe4d2b4197774da0a- 11/3false
- 22/3false
- 31/6true
- 45/6false
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उत्तर : 3. "1/6"
व्याख्या :
Answer: C) 1/6 Explanation: Given X can do in 10 days => 1 day work of X = 1/10 Y can do in 15 days => 1 day work of Y = 1/15 1day work of (X + Y) = 1/10 + 1/15 = 1/6 Given they are hired for 5 days => 5 days work of (X + Y) = 5 x 1/6 = 5/6 Therefore, Unfinished work = 1 - 5/6 = 1/6