Quantitative Aptitude Practice Question and Answer
8Q: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ? 2797 05b5cc6e1e4d2b4197774ebb1
5b5cc6e1e4d2b4197774ebb1- 1Rs. 820false
- 2Rs. 830true
- 3Rs. 840false
- 4Rs. 850false
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Answer : 2. "Rs. 830"
Explanation :
Answer: B) Rs. 830 Explanation: Let the total amount in the partnership be 'x'.Then A's share = x/3B's share = x/4C's share = x/5D's share = x - (x/3 + x/4 +x/5) = 13x/60 A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13 A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
Q: Three men, four women and six children can complete a work in 9 days. A women does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 9 days? 2794 05b5cc6b2e4d2b4197774d374
5b5cc6b2e4d2b4197774d374- 17true
- 28false
- 39false
- 46false
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Answer : 1. "7"
Explanation :
Answer: A) 7 Explanation: Given (3 Men + 4 Women + 6 Children) -----> 9 days But W = 2M and C = M/2 Now, convert Men and Children into Women by 3W2 + 4W + 6W4=> 32 + 4 + 32 = 7 Women Therefore, 7 women alone can complete this work in 9 days.
Q: There are several peacocks and deers in a cage (with no other types of animals). There are 72 heads and 200 feet inside the cage. How many peacocks are there, and how many deers ? 2793 05b5cc73de4d2b4197774f95d
5b5cc73de4d2b4197774f95d- 142 & 24false
- 238 & 26false
- 336 & 24false
- 444 & 28true
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Answer : 4. "44 & 28"
Explanation :
Answer: D) 44 & 28 Explanation: Letx = peacocks y = deers 2x + 4y = 200 x + y = 72 y = 72 - x 2x + 288 - 4x = 200 x = 44 peacocks y = 28 deers
Q: The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ? 2790 05b5cc6c6e4d2b4197774de59
5b5cc6c6e4d2b4197774de59- 112 yearstrue
- 210 yearsfalse
- 314 yearsfalse
- 413 yearsfalse
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Answer : 1. "12 years"
Explanation :
Answer: A) 12 years Explanation: Given the average age of couple and their son = 40 => Sum of age (H +W +S) = 40×3 Let the age of daughter in law at the time of marriage = D years Now after 10 years, (H + S +W) + 3×12 + D +12 + 10 = 38×5 178 + D = 190 D = 190 -178 = 12 years
Q: The ages of Anushka, Kajal and Charu latha together are 57 years. Bharti is thrice as old as Anushka and Charu latha is 12 years older than Anushka. Then, the respective age of Anushka, Kajal and Charu latha is ? 2787 05b5cc741e4d2b4197774f9b8
5b5cc741e4d2b4197774f9b8- 127, 9, 21false
- 29, 21, 27false
- 321, 27, 9false
- 49, 27, 21true
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Answer : 4. "9, 27, 21"
Explanation :
Answer: D) 9, 27, 21 Explanation: Let Anushka age = XCharu latha 12 yrs older than Anushka so Charu latha age = x+12Kajal is thrice as old as Anushka so Kajal age = 3xThe ages of Anushka, Kajal and Charu latha together are 57 yearsi.e x + (x+12) + 3x = 57=> 5x = 45:- x = 9Anushka age = 9Kajal age = 3x = 27Charu latha age = x+12 = 21
Q: At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ? 2782 05b5cc720e4d2b4197774f636
5b5cc720e4d2b4197774f636- 160true
- 274false
- 382false
- 458false
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Answer : 1. "60"
Explanation :
Answer: A) 60 Explanation: Let, no. of rice bowl = xno. of dal bowl = yno. of meat bowl = z Then, x + y + z = 65 ....(1) Also given that, 2x = 3y = 4z substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),We get x = 30. As 1 rice bowl is shared between 2 guests, Therefore, there are 60 guests.
Q: How many parallelograms will be formed if 7 parallel horizontal lines intersect 6 parallel vertical lines? 2776 05b5cc754e4d2b4197774fbb4
5b5cc754e4d2b4197774fbb4- 1215false
- 2315true
- 3415false
- 4115false
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Answer : 2. "315"
Explanation :
Answer: B) 315 Explanation: Parallelograms are formed when any two pairs of parallel lines (where each pair is not parallel to the other pair) intersect. Hence, the given problem can be considered as selecting pairs of lines from the given 2 sets of parallel lines. Therefore, the total number of parallelograms formed = 7C2 x 6C2 = 315
Q: Three taps P, Q and R can fill a tank in 12 hrs, 15 hrs and 20 hrs respectively. If P is open all the time and Q and R are open for one hour each alternately, starting with Q, then the tank will be full in how many hours ? 2775 05b5cc6c0e4d2b4197774dafb
5b5cc6c0e4d2b4197774dafb- 19 hrsfalse
- 27 hrstrue
- 313 hrsfalse
- 411 hrsfalse
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Answer : 2. "7 hrs"
Explanation :
Answer: B) 7 hrs Explanation: Given, P can fill in 12 hrs Q can fill in 15 hrs R can fill in 20 hrs => Volume of tank = LCM of 12, 15, 20 = 60 lit => P alone can fill the tank in 60/12 = 5 hrs => Q alone can fill the tank in 60/15 = 4 hrs => R alone can fill the tank in 60/20 = 3 hrs Tank can be filled in the way that (P+Q) + (P+R) + (P+Q) + (P+R) + .... => Tank filled in 2 hrs = (5+4) + (5+3) = 9 + 8 = 17 lit => In 6 hrs = 17 x 6/2 = 51 lit => In 7th hr = 51 + (5+4) = 51 + 9 = 60 lit => So, total tank will be filled in 7 hrs.