Quantitative Aptitude Practice Question and Answer

Q: The average age of a class is 15.8 years. The average age of the boys in the class is 16.4 years and that of the girls is 15.4 years. What is the ratio of boys to girls in the class ? 1080 0

  • 1
    1:3
    Correct
    Wrong
  • 2
    2:3
    Correct
    Wrong
  • 3
    3:2
    Correct
    Wrong
  • 4
    3:1
    Correct
    Wrong
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Answer : 2. "2:3"
Explanation :

Answer: B) 2:3 Explanation: Let number of boys = x  , Let number of girls = yTotal numbers of students = x + y(x + y) × 15.8 = 16.4x + 15.4y 0.6x = 0.4yx/y = 0.4/0.6 = 2/3    Ratio of boys and girls in the class is 2:3

Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 3331 0

  • 1
    70 years
    Correct
    Wrong
  • 2
    30 years
    Correct
    Wrong
  • 3
    60 years
    Correct
    Wrong
  • 4
    40 years
    Correct
    Wrong
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Answer : 2. "30 years"
Explanation :

Answer: B) 30 years Explanation: Let Karan’s present age be x years and Shiva’s present age be y years.Then, according to the first condition,x - 10 = 3(y - 10) or x - 3y = - 20 ..(1) Now, Karan’s age after 10 years = (x + 10) yearsShiva’s age after 10 years = (y + 10)(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2) Solving (1) and (2), we get x = 70 and y = 30Karan’s age = 70 years and Shiva’s age = 30 years.

Q: Pipe K fills a tank in 30 minutes. Pipe L can fill the same tank 5 times as fast as pipe K. If both the pipes were kept open when the tank is empty, how much time will it take for the tank to overflow ? 2659 0

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    3 minutes
    Correct
    Wrong
  • 2
    2 minutes
    Correct
    Wrong
  • 3
    4 minutes
    Correct
    Wrong
  • 4
    5 minutes
    Correct
    Wrong
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Answer : 4. "5 minutes"
Explanation :

Answer: D) 5 minutes Explanation: Let the total capacity of tank be 90 liters.Capacity of tank filled in 1 minute by K = 3 liters.Capacity of tank filled in 1 minute by L = 15 liters.Therefore, capacity of the tank filled by both K and L in 1 minute = 18 liters.Hence, time taken by both the pipes to overflow the tank = 90/18 = 5 minutes.

Q: Without any stoppage, a person travels a certain distance at an average speed of 42 km/h, and with stoppages he covers the same distance at an average speed of 28 km/h. How many minutes per hour does he stop? 5786 0

  • 1
    15 minutes
    Correct
    Wrong
  • 2
    20 minutes
    Correct
    Wrong
  • 3
    18 minutes
    Correct
    Wrong
  • 4
    22 minutes
    Correct
    Wrong
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Answer : 2. "20 minutes"
Explanation :

Answer: B) 20 minutes Explanation: Let the total distance to be covered is 84 kms.Time taken to cover the distance without stoppage = 84/42 hrs = 2 hrsTime taken to cover the distance with stoppage = 84/28 = 3 hrs.Thus, he takes 60 minutes to cover the same distance with stoppage.Therefore, in 1 hour he stops for 20 minutes.

Q: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 1838 0

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    27 %
    Correct
    Wrong
  • 2
    26 %
    Correct
    Wrong
  • 3
    29 %
    Correct
    Wrong
  • 4
    21 %
    Correct
    Wrong
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Answer : 1. "27 %"
Explanation :

Answer: A) 27 % Explanation: Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135  X = 27 So, required percentage of benzene = 27 %

Q: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 3718 0

  • 1
    6:31
    Correct
    Wrong
  • 2
    11:30
    Correct
    Wrong
  • 3
    7:30
    Correct
    Wrong
  • 4
    31:6
    Correct
    Wrong
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Answer : 3. "7:30"
Explanation :

Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30   Therefore, the ratio is 7 : 30

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Answer : 4. "81.5"
Explanation :

Answer: D) 81.5 Explanation: Let the number of students in classes A, B and C be P, Q and R respectively.Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.Also given that,(83P + 76Q) / (P + Q) = 79=>4P = 3Q.(76Q + 85R)/(Q + R) = 81=>4R = 5Q,=>Q = 4P/3 and R = 5P/3Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5

Q: 'A' sold an article to 'B' at a profit of 20%. 'B' sold the same article to 'C' at a loss of 25% and 'C' sold the same article to 'D' at a profit of 40%. If 'D' paid Rs 252 for the article, then find how much did 'A' pay for it? 2001 0

  • 1
    Rs.196
    Correct
    Wrong
  • 2
    Rs.210
    Correct
    Wrong
  • 3
    Rs.200
    Correct
    Wrong
  • 4
    Rs.235
    Correct
    Wrong
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Answer : 3. "Rs.200"
Explanation :

Answer: C) Rs.200 Explanation: Let the article costs 'X' to ACost price of B = 1.2XCost price of C = 0.75(1.2X) = 0.9XCost price of D = 1.4(0.9X) = 1.26X = 252Amount paid by A for the article = Rs. 200.

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