Quantitative Aptitude Practice Question and Answer

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Answer : 4. "149600 kgs"
Explanation :

Answer: D) 149600 kgs Explanation: Let the total quantity of gold be p kgs. According to the question, 50% of p + 25% of p + 12.5% of p = 130900 87.5% of p = 130900 p = 130900 x 100/87.5  = 149600 kgs.   Therefore, the initial gold quantity that king has = p = 149600 kgs.

Q: Find the number of factors of 9321 ? 3117 0

  • 1
    4
    Correct
    Wrong
  • 2
    5
    Correct
    Wrong
  • 3
    7
    Correct
    Wrong
  • 4
    8
    Correct
    Wrong
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Answer : 4. "8"
Explanation :

Answer: D) 8 Explanation: 9321 = 3 x 13 x 239 = 31 x 13 1 x 239 1 ; add one to all the powers ie., (1+1) x (1+1) x (1+1)= 8 ; we get eight factors.

Q: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17th innings ? 3113 0

  • 1
    34
    Correct
    Wrong
  • 2
    36
    Correct
    Wrong
  • 3
    35
    Correct
    Wrong
  • 4
    37
    Correct
    Wrong
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Answer : 4. "37"
Explanation :

Answer: D) 37 Explanation: 16x + 85 = 17(x + 3) x = 34 + 3 = 37

Q: If HCF of two numbers is 8,which of the following can never be their LCM? 3099 0

  • 1
    32
    Correct
    Wrong
  • 2
    48
    Correct
    Wrong
  • 3
    60
    Correct
    Wrong
  • 4
    152
    Correct
    Wrong
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Answer : 3. "60"
Explanation :

Answer: C) 60 Explanation: 60 is not a multiple of 8

Q: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3075 0

  • 1
    1:3
    Correct
    Wrong
  • 2
    2:1
    Correct
    Wrong
  • 3
    3:2
    Correct
    Wrong
  • 4
    2:3
    Correct
    Wrong
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Answer : 3. "3:2"
Explanation :

Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

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Answer : 4. "31"
Explanation :

Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.

Q:

निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आना चाहिए?
635×455÷403=?

3061 0

  • 1
    735
    Correct
    Wrong
  • 2
    795
    Correct
    Wrong
  • 3
    695
    Correct
    Wrong
  • 4
    685
    Correct
    Wrong
  • 5
    715
    Correct
    Wrong
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Answer : 5. "715"

Q: Find the next number in the sequence? 28, 16, 28, 76, 274 3058 0

  • 1
    1233
    Correct
    Wrong
  • 2
    1243
    Correct
    Wrong
  • 3
    1256
    Correct
    Wrong
  • 4
    1276
    Correct
    Wrong
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Answer : 2. "1243"
Explanation :

Answer: B) 1243 Explanation: Given number sequence is 28, 16, 28, 76, 274 Here the sequence follows a pattern that 28 28 x 0.5 + 2 = 14 + 2 = 16 16 x 1.5 + 4 = 24 + 4 = 28 28 x 2.5 + 6 = 70 + 6 = 76 76 x 3.5 + 8 = 266 + 8 = 274 274 x 4.5 + 10 = 1233 + 10 = 1243   Hence, the next number in the given number sequence is 1243.

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