Answer: B) 5 Explanation: Let M, N and O worked together for x days. From the given data,M alone worked for 8 daysM,N,O worked for x daysN, O worked for 1 day But given thatM alone can complete the work in 18 daysN alone can complete the work in 36 daysO alone can complete the work in 54 days The total work can be the LCM of 18, 6, 54 = 108 units M's 1 day work = 108/18 = 6 unitsN's 1 day work = 108/36 = 3 unitsO's 1 day work = 108/54 = 2 units Now, the equation is8 x 6 + 11x + 5 x 1 = 10848 + 11x + 5 = 10811x = 103 - 4811x = 55x = 5 days. Hence, all M,N and O together worked for 5 days.

Answer: A) 20% स्पष्टीकरण: अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60% हिंदी में उत्तीर्ण छात्रों का प्रतिशत = 45% दोनों विषयों में उत्तीर्ण छात्रों का प्रतिशत = 25% एटीक्यू, केवल अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60 - 25 = 35% का प्रतिशत विद्यार्थी केवल हिंदी में उत्तीर्ण हुए = 45 - 25 = 20% इसलिए, अनुत्तीर्ण छात्रों का प्रतिशत = 100 - (35 + 25 + 20) = 100 - 80 = 20%।

Answer: A) 189 स्पष्टीकरण: दी गई संख्या श्रृंखला 10, 21, 54, 109, 189 है श्रृंखला एक पैटर्न का अनुसरण करती है कि 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186 इसलिए दिए गए में गलत संख्या संख्या श्रृंखला 189 है।

Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a)   2(3b + 2g) = 7 6b + 4g = 7 ........(b)   Solving (a) & (b), we get b = 1, g = 1/4   Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2.   Hence, number of girls required = 2

Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.

Answer: A) 8, 72 yrs Explanation: Let the present ages be K,M Given K/M = 4/5 5K - 4M = 0 ......(1) Also given that, M - (K + 5) = 3 M - K = 8 .........(2) Then, by solving (1) & (2) M = 40 yrs and K = 32 yrs Hence, Total of ages = 40 + 32 = 72 yrs Difference of ages = 40 - 32 = 8 yrs.

Answer: A) 277 Explanation: The given number series is    71      88       113       150       203          277    +17    +25       +37      +53        +74         +8      +12        +16       +21             +4          +4         +5   The series should be  71  88  112   150    203   276 i.e, the differences of the difference should be +4.   Hence, the odd man in the given series is 277.

Answer: C) 50 l Explanation: Let the tin contain 5x litres of liquids 5x - 45 x 455x - 45 x 15 + 45 = 25 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 15 + 45  = 50 litres.