Quantitative Aptitude Practice Question and Answer
8Q: नवनीत तथा प्रभात किसी काम को क्रमशः 20 दिन एवं 25 दिन में कर सकता है। दोनों मिलकर 4500 रूपये के लिए संयुक्त रूप से कार्य करना शुरू किया। कार्य समाप्ति के बाद दोनों की मजदूरी अलग-अलग क्रमशः ज्ञात करें? 3819 25d1490e997a68b089a7aa712
5d1490e997a68b089a7aa712- 1Rs 2000, Rs 2500false
- 2Rs 3000, Rs 1500false
- 3Rs 2500, Rs 2000true
- 4Rs 3500, Rs 1000false
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Answer : 3. "Rs 2500, Rs 2000"
Q: एक दुकानदार रूपये में 5 के भाव से नारंगी बेचा और उसे 20 प्रतिशत का लाभ प्राप्त हुआ। वह रूपये में किस भाव से नांरगी खरीदा था? 3818 05d1338f2d2441c3c5ff90a35
5d1338f2d2441c3c5ff90a35- 13false
- 27false
- 34false
- 46true
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Answer : 4. "6"
Q: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 3815 05b5cc73de4d2b4197774f91b
5b5cc73de4d2b4197774f91b- 110true
- 218false
- 312false
- 415false
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Answer : 1. "10"
Explanation :
Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.
Q: Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together? 3812 05b5cc7d0e4d2b419777511db
5b5cc7d0e4d2b419777511db- 16false
- 28true
- 39false
- 412false
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Answer : 2. "8"
Explanation :
Answer: B) 8 Explanation: AmitBharatNo.of Days4540Efficiency2.22Percent(=145)2.5 Percent(=140) Amit did the work in 56 days = 56×145×2=2845 Therefore, Rest work 17/45 was done by Amit and Bharath = 174517360 = 8 days ( since Amit and Bharath do the work in one day = 145+140=17360)
Q: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 3800 05b5cc69de4d2b4197774c8b2
5b5cc69de4d2b4197774c8b2- 188true
- 292false
- 396false
- 4102false
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Answer : 1. "88"
Explanation :
Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676 Hence the missing number in the given number series is 88.
Q: रतन एक काम को \(5-{1-\over-2}\) दिन में करता है जबकि रूपेश इसी काम को \(10-{1-\over-2}\)दिन में समाप्त करता है। दोनों मिलकर उसकी काम को कितने दिन में समाप्त करेंगे? 3785 25d147c239aeb0a08f1e67215
5d147c239aeb0a08f1e67215- 1\(3 {39 \over 64 }\)true
- 2\(4 {39 \over 64 }\)false
- 3\(5 {39 \over 64 }\)false
- 4\(6 {39 \over 64 }\)false
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Answer : 1. "\(3 {39 \over 64 }\) "
Q: A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ? 3766 05b5cc741e4d2b4197774f99f
5b5cc741e4d2b4197774f99f- 1400false
- 2600false
- 3900true
- 4700false
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Answer : 3. "900"
Explanation :
Answer: C) 900 Explanation: 6,400 gents, 2400 ladies in that company.So total 8,800employees.for 8,800 employees, we want 2400 ladies.for 12,100employees we want how many ladies ?=> (12,100/8,800) x 2400 = 3300.So we want 3300 - 2400 = 900 more ladies.
Q: Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work ? 3753 05b5cc6e1e4d2b4197774ebbb
5b5cc6e1e4d2b4197774ebbb- 118 daysfalse
- 220 daystrue
- 316 daysfalse
- 414 daysfalse
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Answer : 2. "20 days"
Explanation :
Answer: B) 20 days Explanation: (5m + 9w)10 = (6m + 12w)8 => 50m + 90w = 48w + 96 w => 1m = 3w 5m + 9w = 5m + 3m = 8m 8 men can do the work in 10 days. 3m +3w = 3m + 1w = 4m So, 4 men can do the work in (10 x 8)/4 = 20 days.