Quantitative Aptitude Practice Question and Answer
8Q: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 1854 05b5cc60ae4d2b4197774b5b5
5b5cc60ae4d2b4197774b5b5- 15 kmphtrue
- 26 kmphfalse
- 37.5 kmphfalse
- 48 kmphfalse
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Answer : 1. "5 kmph"
Explanation :
Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.
Q: Find the next number in the given number series? 50, 51, 47, 56, 40, ? 2627 05b5cc669e4d2b4197774bf52
5b5cc669e4d2b4197774bf52- 158false
- 265true
- 376false
- 481false
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Answer : 2. "65"
Explanation :
Answer: B) 65 Explanation: The given number series is 50, 51, 47, 56, 40, ? 5050 + 12 = 5151 - 22 = 4747 + 32 = 5656 - 42 = 4040 + 52 = 65 Hence, the next number in the given number series is 65.
Q: एक कक्षा में 60% छात्र अंग्रेजी में और 45% हिंदी में उत्तीर्ण होते हैं। यदि उनमें से 25% दोनों विषयों में उत्तीर्ण होते हैं, तो कितने प्रतिशत छात्र दोनों विषयों में अनुत्तीर्ण होते हैं? 2634 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
- 225%false
- 330%false
- 415%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% स्पष्टीकरण: अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60% हिंदी में उत्तीर्ण छात्रों का प्रतिशत = 45% दोनों विषयों में उत्तीर्ण छात्रों का प्रतिशत = 25% एटीक्यू, केवल अंग्रेजी में उत्तीर्ण छात्रों का प्रतिशत = 60 - 25 = 35% का प्रतिशत विद्यार्थी केवल हिंदी में उत्तीर्ण हुए = 45 - 25 = 20% इसलिए, अनुत्तीर्ण छात्रों का प्रतिशत = 100 - (35 + 25 + 20) = 100 - 80 = 20%।
Q: दी गई संख्या श्रंखला में गलत संख्या ज्ञात कीजिए? 10, 21, 54, 109, 189 8887 05b5cc607e4d2b4197774b553
5b5cc607e4d2b4197774b553- 1189true
- 2109false
- 354false
- 421false
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Answer : 1. "189"
Explanation :
Answer: A) 189 स्पष्टीकरण: दी गई संख्या श्रृंखला 10, 21, 54, 109, 189 है श्रृंखला एक पैटर्न का अनुसरण करती है कि 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186 इसलिए दिए गए में गलत संख्या संख्या श्रृंखला 189 है।
Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1457 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
- 23false
- 32true
- 41false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2
Q: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 2000 05b5cc619e4d2b4197774b705
5b5cc619e4d2b4197774b705- 1720false
- 2360false
- 3120false
- 424true
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Answer : 4. "24"
Explanation :
Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.
Q: The ratio of K’s and M’s ages is 4: 5. If the difference between the present age of M and the age of K, 5 years hence is 3 years, then what is the difference and total of present ages of K and M? 1475 05b5cc639e4d2b4197774ba7d
5b5cc639e4d2b4197774ba7d- 18, 72 yrstrue
- 216, 65 yrsfalse
- 312, 84 yrsfalse
- 410, 60 yrsfalse
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Answer : 1. "8, 72 yrs"
Explanation :
Answer: A) 8, 72 yrs Explanation: Let the present ages be K,M Given K/M = 4/5 5K - 4M = 0 ......(1) Also given that, M - (K + 5) = 3 M - K = 8 .........(2) Then, by solving (1) & (2) M = 40 yrs and K = 32 yrs Hence, Total of ages = 40 + 32 = 72 yrs Difference of ages = 40 - 32 = 8 yrs.
Q: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 1596 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
- 2203false
- 3150false
- 4113false
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Answer : 1. "277"
Explanation :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.