Quantitative Aptitude Practice Question and Answer
8Q: X और Y नामक दो संस्थानों में दाखिल छात्रों की संख्या क्रमशः 5ः8 के अनुपात में है।यदि संस्थान X में छात्रों की संख्या में 20 प्रतिशत की वृद्धि हो जाए, और संस्थान Y में 10 प्रतिशत वृद्धि हो जाए, तो क्रमशः नया अनुपात क्या होगा? 5143 15d1b13e08a754124194a7564
5d1b13e08a754124194a7564- 115:22true
- 215:16false
- 35:4false
- 45:7false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "15:22"
Q: विपणन विभाग में महिलाओं की संख्या लगभग कितने प्रतिशत है जो विपणन और ग्राहक संबंध विभाग के कुल कर्मचारियों का एक साथ है?
5114 05d4aba5e11160f20523749fa
5d4aba5e11160f20523749fa- 126false
- 236false
- 36false
- 446false
- 516true
- Show Answer
- Workspace
- SingleChoice
Answer : 5. "16"
Q: 21 वस्तुओं का क्रय मूल्य 15 वस्तुओं के विक्रय मूल्य के बराबर है। लाभ प्रतिशत होगा? 5110 05d132f44925caa2d5bbbff66
5d132f44925caa2d5bbbff66- 125%false
- 230%false
- 333%false
- 440%true
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "40%"
Q: What was the day of the week on 17th June, 1998 ? 5106 75b5cc761e4d2b4197774fd16
5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 3. "Wednesday"
Explanation :
Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.
Q: Two boys and a girl can do a work in 5 days, while a boy and 2 girls can do it in 6 days. If the boy is paid at the rate of 28$ a week, what should be the wages of the girl a week ? 5098 05b5cc74ae4d2b4197774faa4
5b5cc74ae4d2b4197774faa4- 124 $false
- 222 $false
- 316 $true
- 414 $false
- Show Answer
- Workspace
- SingleChoice
Answer : 3. "16 $"
Explanation :
Answer: C) 16 $ Explanation: Let the 1 day work of a boy=b and a girl=g, then2b + g = 1/5 ---(i) andb + 2g = 1/6 ---(ii)On solving (i) & (ii), b=7/90, g=2/45As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week, so a girl will be paid 28×245790 = 16 $.
Q: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5095 05b5cc6bae4d2b4197774d7f8
5b5cc6bae4d2b4197774d7f8- 1264true
- 2220false
- 3241false
- 4Nonefalse
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "264"
Explanation :
Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264
Q: एक साइकिल को 2070 रू. में बेचने पर एक व्यक्ति को 15 प्रतिशत लाभ होता है। वह इसे कितने रू. में बेचे तो उसे 25 प्रतिशत लाभ हो? 5081 05d13299509a40f38019e53a2
5d13299509a40f38019e53a2- 12150false
- 22250true
- 32350false
- 42450false
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "2250"
Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5074 05b5cc74ae4d2b4197774fa68
5b5cc74ae4d2b4197774fa68- 120 kmfalse
- 216 kmfalse
- 314 kmfalse
- 410 kmtrue
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "10 km"
Explanation :
Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.