CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2653 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
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उत्तर : 1. "100"
व्याख्या :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
प्र: What is the probability of an impossible event? 2644 05b5cc69ee4d2b4197774c995
5b5cc69ee4d2b4197774c995- 10true
- 2-1false
- 30.1false
- 41false
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उत्तर : 1. "0"
व्याख्या :
Answer: A) 0 Explanation: The probability of an impossible event is 0. The event is known ahead of time to be not possible, therefore by definition in mathematics, the probability is defined to be 0 which means it can never happen. The probability of a certain event is 1.
प्र: Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ? 2643 05b5cc6d8e4d2b4197774e7c6
5b5cc6d8e4d2b4197774e7c6- 1360 mfalse
- 2420 mtrue
- 3460 mfalse
- 4320 mfalse
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उत्तर : 2. "420 m"
व्याख्या :
Answer: B) 420 m Explanation: Let the length of the stationary train Y be LY Given that length of train X, LX = 300 m Let the speed of Train X be V. Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively. => 300/V = 25 ---> ( 1 ) (300 + LY) / V = 60 ---> ( 2 ) From (1) V = 300/25 = 12 m/sec. From (2) (300 + LY)/12 = 60 => 300 + LY = 60 (12) = 720 => LY = 720 - 300 = 420 m Length of the stationary train = 420 m
प्र: A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1995. She ended counting on which finger ? 2642 05b5cc723e4d2b4197774f66d
5b5cc723e4d2b4197774f66d- 1Thumbfalse
- 2Index fingerfalse
- 3Ring fingerfalse
- 4Middle fingertrue
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उत्तर : 4. "Middle finger"
व्याख्या :
Answer: D) Middle finger Explanation: Clearly, while counting the numbers associated to the thumb will be 1,9,17,25,.........i.e., numbers of the form (8n + 1 ).where n=1,2,3...Since 1994 = 249 × 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger and 1995 to the middle finger.
प्र: Look at the series : 3, 7, 24, 11, __, 19, 19,... What number should fill the blank ? 2642 05b5cc6d5e4d2b4197774e610
5b5cc6d5e4d2b4197774e610- 115true
- 213false
- 321false
- 416false
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उत्तर : 1. "15"
व्याख्या :
Answer: A) 15 Explanation: Two series alternate here, with every third number following a different pattern.In the main series, 4 is added to each number to arrive the next.In alternate series, 5 is subtracted from each number t arrive the next number.Here in the main series 3 + 4 = 77 + 4 = 1111 + 4 = 1515 + 4 = 19 In alternate series 24 - 5 = 1919 - 5 = 14...
प्र: When combining with nonmetallic atoms, metallic atoms generally will 2638 05b5cc64ae4d2b4197774bc11
5b5cc64ae4d2b4197774bc11- 1Lose electrons and forms cationstrue
- 2Gain electrons and forms anionsfalse
- 3Lose electrons and forms anionsfalse
- 4Gain electrons and forms cationsfalse
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उत्तर : 1. "Lose electrons and forms cations"
व्याख्या :
Answer: A) Lose electrons and forms cations Explanation: When combining with nonmetallic atoms, metallic atoms generally will Lose electrons and forms cations. As the ionization energy of te metals are very low, so they can easily lose electrons and form positively charged ion called cations.
प्र: Gases used in normal welding? 2637 05b5cc688e4d2b4197774c327
5b5cc688e4d2b4197774c327- 1Oxygen and Acetylenetrue
- 2Acetylene and Nitrogenfalse
- 3Oxygen, Hydrogen and Acetylenefalse
- 4Oxygen and Hydrogenfalse
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उत्तर : 1. "Oxygen and Acetylene"
व्याख्या :
Answer: A) Oxygen and Acetylene Explanation: Normal Gas welding use oxygen-acetylene. Depending on what materials you are welding, there are some more options that might be used. For example - MIG/TIG use Argon, MAG use an argon-something mix.
प्र: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ? 2634 15b5cc74ae4d2b4197774fabd
5b5cc74ae4d2b4197774fabd- 1Rs. 175false
- 2Rs. 325false
- 3Rs. 340true
- 4Rs. 260false
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उत्तर : 3. "Rs. 340"
व्याख्या :
Answer: C) Rs. 340 Explanation: Assume first child (the youngest) get = Rs. x According to the question ;each son having Rs. 30 more than the younger one Second child will get = Rs. x + 30 Third child will get = Rs. x + 30 + 30 = x + 60 Forth child will get = Rs. x + 30 + 30 + 30 = x + 90 Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120 Total amount they got = Rs. 2000 x + (x+30) + (x+60) + (x+90) + (x+120) = 20005x + 300 = 20005x = 1700x = Rs. 340So the youngest child will get Rs. 340.