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प्र: K can finish the work in 18 days and L can do the same work in 15 days. L worked for 10 days and left the job. In how many days, K alone can finish the remaining work ? 1411 0

  • 1
    5.5 days
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  • 2
    6 days
    सही
    गलत
  • 3
    4.2 days
    सही
    गलत
  • 4
    5 days
    सही
    गलत
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उत्तर : 2. "6 days"
व्याख्या :

Answer: B) 6 days Explanation: L's 10 days work = 115×10=23   Remaining work = 1-23=13   Now,  work is done by K in one day = 1/18   1/3 work is done by K in  18×13 = 6 days

प्र: Twenty men can do a work in eighteen days. Eighteen women can complete the same work in fifteen days. What is the ratio between the capacity of a woman and a man ? 1767 0

  • 1
    4:5
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  • 2
    3:4
    सही
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  • 3
    4:3
    सही
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  • 4
    2:3
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उत्तर : 3. "4:3"
व्याख्या :

Answer: C) 4:3 Explanation: (20 x 18) men can complete the work in in one day. one man's one day work = 1/360 (18 x 15) women can complete the work in 1 day 1 woman's one day work = 1/270 So, required ratio = 1270:1360= 4:3

प्र: In a hostel, there was food for 1000 students for one month. After 10 days, 1000 more students joined the hostel. How long would the students be able to carry on with the remaining food? 2213 0

  • 1
    10 days
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  • 2
    15 days
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  • 3
    20 days
    सही
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  • 4
    5 days
    सही
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उत्तर : 1. "10 days"
व्याख्या :

Answer: A) 10 days Explanation: After 10 days, the remaining food would be sufficient for the 1000 students for 20 more days -->If 1000 more students are added, it shall be sufficient for only 10 days (as the no. of students is doubled, the days are halved).

प्र: A tank-full petrol in Veeru’s Car last for 20 days. If he starts using 25% more every day, how many days will the tank-full petrol last? 2542 0

  • 1
    18 days
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  • 2
    12 days
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  • 3
    14 days
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  • 4
    16 days
    सही
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उत्तर : 4. "16 days"
व्याख्या :

Answer: D) 16 days Explanation: The analogy here is like this: Veeru has 20 lt of petrol and he uses 1 lt per each day and consumes it in 20 days. If he uses 1.25 lt every day, in how many days it will be consumed?We considered 1.25 lt here because it’s 25% more than 1 lt. The answer would be  20/1.25=16 days.

प्र: A box contains 5 green, 4 yellow and 5 white pearls. Four pearls are drawn at random. What is the probability that they are not of the same colour ? 1998 0

  • 1
    11/91
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  • 2
    4/11
    सही
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  • 3
    1/11
    सही
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  • 4
    90/91
    सही
    गलत
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उत्तर : 4. "90/91"
व्याख्या :

Answer: D) Option D Explanation: Let S be the sample space. Then,n(s) = number of ways of drawing 4 pearls out of 14 = C414 ways = 14×13×12×114×3×2×1= 1001 Let E be the event of drawing 4 pearls of the same colour.Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5)   ⇒C15+ C44+ C15 = 5+1+5 =11  P(E) = n(E)n(S)=111001=191      Required probability = 1-191=9091

प्र: In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ? 1311 0

  • 1
    13
    सही
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  • 2
    821
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  • 3
    621
    सही
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  • 4
    2021
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उत्तर : 1. "13"
व्याख्या :

Answer: A) Option A Explanation: Total number of flowers = (8+7+6) = 21.   Let E = event that the flower drawn is neither red nor green.  = event taht the flower drawn is blue.    --> n(E)= 7  --> P(E)=  721=13

प्र: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1664 0

  • 1
    205
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  • 2
    194
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  • 3
    209
    सही
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  • 4
    159
    सही
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उत्तर : 3. "209"
व्याख्या :

Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24  + (C36× C14) + (C46)   = (24+90+80+15)  = 209.

प्र: How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ? 1323 0

  • 1
    15
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  • 2
    20
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  • 3
    5
    सही
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  • 4
    10
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उत्तर : 2. "20"
व्याख्या :

Answer: B) 20 Explanation: Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5.   So, there is one way of doing it.   Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place.   The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.   Required number of numbers = (1 x 5 x 4) = 20.

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