Answer: B) Flying Officer Explanation: Major and Squadron leader are equivalent ranks in Army and Air Force respectively . In the same way Lieutenant and Flying officer are equivalent ranks in Army and Air Force respectively.

Answer: C) Option C Explanation: Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.

Answer: C) 28 Explanation: Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.   We may consider the two cases as under: Case I:  ←3C↔8B↔5A→21   Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40   Case II:  ←3C A↔5B   Number of persons between A and C                     = (8 - 6) = 2    ∵[C↔8B A→21B]   Clearly number of persons in the queue = (3+1+2+1+21) = 28   Now, 28 < 40. So, 28 is the minimum number of persons in the queue.

Answer: A) 80 deg Explanation: As minute hand covers, 60 degrees Minute hand covers 4800/60 = 80°

Answer: B) Masculine titles Explanation: As they are the titles of male gender, they are called as Masculine titles.

Answer: A) 99 Explanation: Given 2 is to 55 2 + 3 = 5  5 x 11 = 55 Similarly, 6 6 + 3 = 9 9 x 11 = 99   Hence, 2 is to 55 as 6 is to 99.

Answer: B) 13 Explanation:  Let   Let x=333 = 333    Then, logx = 33 log3     = 27 x 0.47712 = 12.88224    Since the characteristic in the resultant value of log x is 12   ∴The number of digits in x is (12 + 1) = 13    Hence the required number of digits in 333is 13.

Answer: D) ²²C₁₀ - 1 Explanation: The total number of ways of forming the group of ten representatives is ²²C₁₀. The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way The required number of ways = ²²C₁₀ - 1