Join ExamsbookAnswer : 2. "20"
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ?5
Q: How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ?
- 115false
- 220true
- 35false
- 410false
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Answer : 2. "20"
Explanation :
Answer: B) 20 Explanation: Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5. So, there is one way of doing it. Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place. The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it. Required number of numbers = (1 x 5 x 4) = 20.