Trigonometry Practice Question and Answer

Q:

$$ sin^2 5° + sin^2 10°+sin^2 15°+.....sin^2 85°+sin^2 90°$$ के बराबर है।

1086 0

  • 1
    $$ {17\over2}$$
    Correct
    Wrong
  • 2
    $$ {19\over2}$$
    Correct
    Wrong
  • 3
    $$ {21\over2}$$
    Correct
    Wrong
  • 4
    $$ {18\over2}$$
    Correct
    Wrong
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Answer : 2. "$$ {19\over2}$$"

Q:


1079 0

  • 1
    cosec A
    Correct
    Wrong
  • 2
    cos A
    Correct
    Wrong
  • 3
    secA
    Correct
    Wrong
  • 4
    sinA
    Correct
    Wrong
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Answer : 3. "secA"

Q:

यदि  $$ {cosAcotA \over( 1 - sinA ) }=x $$ है, तो x का मान क्या हैं ? 

1060 0

  • 1
    1 - cosecA
    Correct
    Wrong
  • 2
    1 + cosecA
    Correct
    Wrong
  • 3
    1 + secA
    Correct
    Wrong
  • 4
    1 - secA
    Correct
    Wrong
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Answer : 2. "1 + cosecA "

Q:

यदि  x cos2300.sin600=$${tan^2{45}^0.sec60^0}\over cosec\ 60^0$$ है तो x का मान होगा ? 

1053 0

  • 1
    $$ 1\over \sqrt { 3} $$
    Correct
    Wrong
  • 2
    $$ 2{2\over 3} $$
    Correct
    Wrong
  • 3
    $$ 1\over \sqrt { 2} $$
    Correct
    Wrong
  • 4
    $$ {1\over 2} $$
    Correct
    Wrong
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Answer : 2. "$$ 2{2\over 3} $$"

Q:

दिये गये चित्र में BC=15 cm  , Sin B=4/5  है तो AB का मान होगा।

1028 0

  • 1
    25 सेमी
    Correct
    Wrong
  • 2
    20 सेमी
    Correct
    Wrong
  • 3
    5 सेमी
    Correct
    Wrong
  • 4
    4 सेमी
    Correct
    Wrong
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Answer : 1. "25 सेमी"

Q:

यदि $$ {\sqrt{3}\ CosA=SinA}$$  है तो Cot A का मान ज्ञात कीजिए

1028 0

  • 1
    $$ {\sqrt{3}}$$
    Correct
    Wrong
  • 2
    $$ {2\over {\sqrt{3}}}$$
    Correct
    Wrong
  • 3
    $$ {1\over {\sqrt{3}}}$$
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 3. "$$ {1\over {\sqrt{3}}}$$"

Q:

यदि A और B न्यून कोण है और Sec A =3; Cot B=4, है तो $$ {Cosec^{2}A}+Sin^{2}B\over {Cot^{2}A+Sec^{2}B}$$  का मान होगा 

1023 0

  • 1
    2
    Correct
    Wrong
  • 2
    $$ {25\over 261}$$
    Correct
    Wrong
  • 3
    $$ {322\over 323}$$
    Correct
    Wrong
  • 4
    $$ {1\over 261}$$
    Correct
    Wrong
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Answer : 3. "$$ {322\over 323}$$"

Q:

यदि cosec 39°= x है तो का $$ {1\over {cosec^{2}{51°}}} +sin^{2} 39^{°}+tan^{2}{51^{°}}-{1\over {sin^{2}{51^{°}}}{Sec^{2}{39^{°}}}}$$ मान होगा।

1019 0

  • 1
    $$ {\sqrt{x^{2}-1}}$$
    Correct
    Wrong
  • 2
    $$ {\sqrt{1-x^{2}}}$$
    Correct
    Wrong
  • 3
    $$ {x^{2}-1}$$
    Correct
    Wrong
  • 4
    $$ {1-x^{2}}$$
    Correct
    Wrong
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Answer : 3. "$$ {x^{2}-1}$$"

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