Trigonometry Practice Question and Answer
8 4 Q:
5f2e3d53be9f31290fbc5f92 4 Q:
6007f30c1187ab386914c60f 4 Q:
60ae1d553ac44b3ce011f604 4 Q:
6007f19e1187ab386914c385 4 Q:
60fe3186f8986716bdf6948b 4 Q:
5ff8354ac24e1471a7fa62bb 4 Q:
602268792dc71d4148a16d2f 4 Q:
602266862dc71d4148a16323
Q: $${cotA+tanB}\over{cotB+tanA}$$ का सरलीकृत मान क्या है?
785 05f2e3d53be9f31290fbc5f92
5f2e3d53be9f31290fbc5f92- 1tanAcotBfalse
- 2tanBcotAtrue
- 3tanAtanBfalse
- 4cotAcotBfalse
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Answer : 2. "tanBcotA"
Q: यदि 5sinθ – 4cosθ=0, 0°˂θ˂90°, है तो $$ {5\sinθ-2\cosθ}\over {5\sinθ+3\cosθ}$$ का मान होगा—
783 06007f30c1187ab386914c60f
6007f30c1187ab386914c60f- 1$$ {3\over 8}$$false
- 2$$ {2\over 7}$$true
- 3$$ {5\over 7}$$false
- 4$$ {3\over 5}$$false
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Answer : 2. "$$ {2\over 7}$$"
Q: (cosA - sinA)2 +(cosA + sinA)2 का मान है –
777 060ae1d553ac44b3ce011f604
60ae1d553ac44b3ce011f604- 10false
- 21false
- 32true
- 43false
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Answer : 3. "2"
Q: $$ {(cos {\ 9°}+sin{\ 81°}})({sec {\ {9°}+cosec{\ 81°}}})\over{sin{\ 56°}sec{\ 34° }}+ {cos{\ 25°}cosec{\ 65°}}$$ का मान है।
776 06007f19e1187ab386914c385
6007f19e1187ab386914c385- 1$$ {1\over 4}$$false
- 24false
- 32true
- 4$$ {1\over 2}$$false
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Answer : 3. "2"
Q: (1– sin A cos A)(sin A + cos A) का सरलीकृत मान क्या है?
775 160fe3186f8986716bdf6948b
60fe3186f8986716bdf6948b- 1$$cos^2A – sin^2A$$false
- 20false
- 3$$sin^3A + cos^3A$$true
- 4$$sin^2A – cos^2A$$false
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Answer : 3. "$$sin^3A + cos^3A$$ "
Q: समीकरण $$ {{ATan62°Sec 28°Cot 38°}\over {Cosec62°Tan11°}}=1$$ बनाने के लिए A के लिए निम्नलिखित में से कौन सा मूल्य सूट करता है?
752 05ff8354ac24e1471a7fa62bb
5ff8354ac24e1471a7fa62bb- 1$$ {{Tan38°Tan79°}\over {Tan 28°}}$$false
- 2$$ {{Tan28°Tan38°}\over {Tan 79°}}$$true
- 3$$ {{Tan38°}\over {Tan 79°Tan28°}}$$false
- 4$$ {{Tan28° Tan 79°}\over { Tan38°}}$$false
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Answer : 2. "$$ {{Tan28°Tan38°}\over {Tan 79°}}$$"
Q: $$ {tan\ 40°+tan\ 20° +\sqrt{3}\ tan20° tan40°}$$ का मान है—
751 0602268792dc71d4148a16d2f
602268792dc71d4148a16d2f- 1$$ {\sqrt{12}}$$false
- 2$$ {1\over{\sqrt{3}}}$$false
- 31false
- 4$$ {\sqrt{3}}$$true
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Answer : 4. "$$ {\sqrt{3}}$$"
Q: यदि $$ {Acos^{2}θ+Bsin^{2}θ}={sin^{2}θ(sec^{2}θ+1)\over{sec^{2}θ-1}}$$ है तो cotθ=?
734 0602266862dc71d4148a16323
602266862dc71d4148a16323- 1$${\sqrt{B-2\over2-A}}$$false
- 2$${\sqrt{B-1\over2-A}}$$true
- 3$${\sqrt{B-1\over A-2}}$$false
- 4$${\sqrt{2-B\over 2-A}}$$false
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Answer : 2. "$${\sqrt{B-1\over2-A}}$$"
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