undefined

In the figure the simplest Triangles are GLK, DLJ, DJM,HMN,QRE,IRA,IPA, and FPO is the 8 triangle

and another is BDO,CDQ,DLM, PRA, KFI, NEI, HJI, GJI,DKI, and DNI is the 10 triangle

and another is DIE, DFI, DOA, DQA, and GHI is the 5 triangle

and DCA, DBA is the 2 triangle and DEF and ABC so that according to the figure the total no. of triangle is 8+10+5+2+1+1=27

Answer: A) 30, 5 Explanation: The figure may be labelled as shown     Rectangles :   The simplest rectangles are CVSR, VETS, RSWM and STKW i.e 4 in number.   The rectangles composed of two components each are CETR, VEKW, RTKM and CVWM i.e 4 in number.   The rectangles composed of three components each are ACRP, PRMO, EGHT and THIK i.e 4 in number.   The rectangles composed of four components each are CEKM, AVSP, PSWO,VGHS and SHIW i.e 5 in number.   The rectangles composed of five components each are AETP, PTKO, CGHR and RHIM i.e 4 in number.   The rectangles composed of six components each are ACMO and EGIK i.e 2 in number.   The rectangles composed of eight components each are AGHP, PHIO, AVWO and VGIW i.e 4 in number.   The rectangles composed of ten components each are AEKO and CGIM i.e 2 in number.   AGIO is the only rectangle having sixteen components   Total number of rectangles in the given figure = 4 + 4 + 4 + 5 + 4 + 2 + 4 + 2 + 1 = 30.   Hexagons :   The hexagons in the given figure are CDEKLM, CEUKMQ, CFHJMQ, BEUKNP and BFHJNP. So, there are 5 hexagons in the given figure.

In this figure counting the squares and we get the 27 squares.

Answer: A) 35/36 स्पष्टीकरण: जब दो पासे एक साथ फेंके जाते हैं, तो संभावना है n(S) = 6x6 = 36 आवश्यक, दो संख्याओं का योग 12 से कम है जो कि n(E) = { के रूप में किया जा सकता है 1,1), (1,2), (1,3), (1,4), (1,5), (1,6)(2,1), (2,2), (2,3 ), (2,4), (2,5), (2,6)(3,1), (3,2), (3,3), (3,4), (3,5), ( 3,6)(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)(5,1), (5,2) , (5,3), (5,4), (5,5), (5,6)(6,1), (6,2), (6,3), (6,4), (6 ,5)} = 35 इसलिए, अपेक्षित प्रायिकता = n(E)/n(S) = 35/36।

उत्तर: B) 1/9 स्पष्टीकरण: S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2) , 1), (2, 2), ......... (6, 5), (6, 6)} => n (S) = 6 x 6 = 36 E = {(6, 3) ), (5, 4), (4, 5), (3, 6)} => n (E) = 4 इसलिए, P (E) = 4/36 = 1/9

undefined