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In a single throw of two dice , find the probability that neither a doublet nor a total of 8 will appear.5
Q: In a single throw of two dice , find the probability that neither a doublet nor a total of 8 will appear.
- 17/15false
- 25/18true
- 313/18false
- 43/16false
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Answer : 2. "5/18"
Explanation :
Answer: B) 5/18 Explanation: n(S) = 36 A = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)} B = { (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) } nA=6, nB=5, nA∩B=1 ∴Required probability = PA∪B = PA+PB-PA∩B = 636+536-136 = 518
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