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A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?5
Q: A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?
- 1136/345false
- 217/87false
- 3316/435true
- 4158/435false
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Answer : 3. "316/435"
Explanation :
Answer: C) 316/435 Explanation: ns=C230 Let A be the event of getting two oranges and B be the event of getting two non-defective fruits. and A∩B be the event of getting two non-defective oranges ∴ PA=C220C230, PB=C222C230 and PA∩B=C215C230 ∴PA∪B=PA+PB-PA∩B = C220C230+C222C230-C215C230=316435
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