Bank Exams Practice Question and Answer
8Q: If 4th december 1999 is Monday then what day is 3rd january 2000 ? 2343 05b5cc73ae4d2b4197774f8ba
5b5cc73ae4d2b4197774f8ba- 1Sundayfalse
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdaytrue
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Answer : 4. "Wednesday"
Explanation :
Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.
Q: What is the next number in series? 10, 9, 60, 90, 70, 66, ? 1728 05b5cc73ae4d2b4197774f8b0
5b5cc73ae4d2b4197774f8b0- 173false
- 219false
- 396true
- 422false
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Answer : 3. "96"
Explanation :
Answer: C) 96 Explanation: ten = 3(number of letters)nine = 4(number of letters)sixty = 5(number of letters)ninety = 6(number of letters)seventy = 7(number of letters)sixtysix = 8(number of letters)ninetysix=96(number of letters) Then, likwise choose the number which has 9 letters in its Spelling.
Q: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 1823 05b5cc73ae4d2b4197774f8ab
5b5cc73ae4d2b4197774f8ab- 12101 hrsfalse
- 24125 hrsfalse
- 35124 hrsfalse
- 46011 hrstrue
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Answer : 4. "6011 hrs"
Explanation :
Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
Q: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? 519 328 746 495 837 1269 05b5cc73ae4d2b4197774f8a6
5b5cc73ae4d2b4197774f8a6- 1146true
- 2203false
- 3345false
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Answer : 1. "146"
Explanation :
Answer: A) 146 Explanation: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? Now arranging the given numbers in descending order.837 746 519 495 328 519 - 746/2 = 519 - 373 = 146.
Q: If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ? 1800 05b5cc73ae4d2b4197774f8a1
5b5cc73ae4d2b4197774f8a1- 131/25false
- 215/17true
- 314/25false
- 411/16false
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Answer : 2. "15/17"
Explanation :
Answer: B) 15/17 Explanation: The original fraction is 2551 × 350+100150+100 = 15/17.
Q: Sonika invested an amount of Rs.5800 for 2 years. At what rate of compound interest will she get an amount of Rs.594.50 at the end of 2 years ? 1769 05b5cc73ae4d2b4197774f89c
5b5cc73ae4d2b4197774f89c- 16.5%false
- 26%false
- 35%true
- 44.5%false
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Answer : 3. "5%"
Explanation :
Answer: C) 5% Explanation: C.I = P1+r100t-1 594.5 = 58001+r1002-1 594.55800+1=1+r1002 r100=1.05-1=0.05=> r = 5 % .
Q: There are two numbers such that the sum of twice the first number and thrice the second number is 100 and sum of thrice the first number and twice the second number is 120. Which is the larger number ? 1121 05b5cc736e4d2b4197774f892
5b5cc736e4d2b4197774f892- 132true
- 224false
- 326false
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Answer : 1. "32"
Explanation :
Answer: A) 32 Explanation: Let the first number be K and second number be LThen, 2K + 3L = 100.....(1)3K + 2L = 120.......(2)solving (1)&(2), we getK = 32 and L = 12 Hence the largest number is 32.
Q: Statements : All keys are locks. All locks are bangles. All bangles are cars. Conclusion : a. Some cars are locks. b. Some bangles are keys. c. Some cars are keys. 1987 05b5cc736e4d2b4197774f897
5b5cc736e4d2b4197774f897- 1Only a followsfalse
- 2Only c followsfalse
- 3Only a & b followsfalse
- 4a, b & c followstrue
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Answer : 4. "a, b & c follows"
Explanation :
Answer: D) a, b & c follows Explanation: All locks are bangles + All bangles are cars = A + A = A= All locks are cars => Some cars are locks.Hence conclusion (a) follows.All keys are locks + All locks are bangles = A + A = A= All keys are bangles => some bangles are keys.Hence conclusion (b) follows.All keys are bangles + All bangles are cars = A + A = A= All keys are cars => Some cars are keys.Hence conclusion (C) follows. Thus all a, b and c follows.