Bank Exams प्रश्न और उत्तर का अभ्यास करें
8प्र: Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ? 1405 05b5cc75ee4d2b4197774fcb6
5b5cc75ee4d2b4197774fcb6- 181false
- 278false
- 380.5false
- 481.5true
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उत्तर : 4. "81.5"
व्याख्या :
Answer: D) 81.5 Explanation: Let the number of students in classes A, B and C be P, Q and R respectively.Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.Also given that,(83P + 76Q) / (P + Q) = 79=>4P = 3Q.(76Q + 85R)/(Q + R) = 81=>4R = 5Q,=>Q = 4P/3 and R = 5P/3Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5
प्र: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 3933 05b5cc75ee4d2b4197774fcb1
5b5cc75ee4d2b4197774fcb1- 16:31false
- 211:30false
- 37:30true
- 431:6false
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उत्तर : 3. "7:30"
व्याख्या :
Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30 Therefore, the ratio is 7 : 30
प्र: What should come next in the following letter series based on English alphabet ?CEA JLH QSO ? 1901 05b5cc75ee4d2b4197774fcac
5b5cc75ee4d2b4197774fcac- 1WYUfalse
- 2UXWfalse
- 3WXVfalse
- 4XZVtrue
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उत्तर : 4. "XZV"
व्याख्या :
Answer: D) XZV Explanation: In the given series, each letter moves seven letters forward to obtain the next.So, XZV replaces ? in the series.
प्र: In a certain code language, 'how can you go' is written as 'ja da ka pa', 'can you come here' is written as 'na ka sa ja' and 'cone and go' is written as 'ra pa sa'. How is 'here' written in that code ? 4086 05b5cc75ee4d2b4197774fca7
5b5cc75ee4d2b4197774fca7- 1natrue
- 2jafalse
- 3safalse
- 4Nonefalse
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उत्तर : 1. "na"
व्याख्या :
Answer: A) na Explanation: From the given information : how can you go = ja da ka pa....(1)can you come here = na ka sa ja...(2)come and go = ra pa sa....(3)from (1)&(2), can you = ja ka...(4)from (2)&(3), come = sa...(5)Using (4)&(5) in (2), we get here = na.
प्र: 'A' sold an article to 'B' at a profit of 20%. 'B' sold the same article to 'C' at a loss of 25% and 'C' sold the same article to 'D' at a profit of 40%. If 'D' paid Rs 252 for the article, then find how much did 'A' pay for it? 2163 05b5cc75ee4d2b4197774fca2
5b5cc75ee4d2b4197774fca2- 1Rs.196false
- 2Rs.210false
- 3Rs.200true
- 4Rs.235false
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उत्तर : 3. "Rs.200"
व्याख्या :
Answer: C) Rs.200 Explanation: Let the article costs 'X' to ACost price of B = 1.2XCost price of C = 0.75(1.2X) = 0.9XCost price of D = 1.4(0.9X) = 1.26X = 252Amount paid by A for the article = Rs. 200.
प्र: In a certain code DOWN is written as '5@9#' and NAME is written as '#6%3'. How is MODE written in that code ? 2941 05b5cc75ee4d2b4197774fc98
5b5cc75ee4d2b4197774fc98- 16@53false
- 2%@53true
- 353%#false
- 4%#35false
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उत्तर : 2. "%@53"
व्याख्या :
Answer: B) %@53 Explanation: From the given information : D O W N A M E == 5 @ 9 # 6 % 3 MODE = %@53
प्र: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 1743 05b5cc75ee4d2b4197774fc9d
5b5cc75ee4d2b4197774fc9d- 1Rs.2010false
- 2Rs.2200false
- 3Rs.2000true
- 4Rs.2100false
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उत्तर : 3. "Rs.2000"
व्याख्या :
Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.
प्र: A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ? 6274 05b5cc75ee4d2b4197774fc93
5b5cc75ee4d2b4197774fc93- 1Rs.37,500true
- 2Rs.36,400false
- 3Rs.37,415false
- 4Rs.36,500false
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उत्तर : 1. "Rs.37,500"
व्याख्या :
Answer: A) Rs.37,500 Explanation: Assume A be the cost price. Therefore,35×A×10100 - 25×A×5100 = 1500 => A = Rs 37,500.