Bank Exams प्रश्न और उत्तर का अभ्यास करें
8प्र: Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue? 5766 05b5cc7f2e4d2b41977751eac
5b5cc7f2e4d2b41977751eac- 141false
- 240false
- 328true
- 427false
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उत्तर : 3. "28"
व्याख्या :
Answer: C) 28 Explanation: Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB. We may consider the two cases as under: Case I: ←3C↔8B↔5A→21 Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40 Case II: ←3C A↔5B Number of persons between A and C = (8 - 6) = 2 ∵[C↔8B A→21B] Clearly number of persons in the queue = (3+1+2+1+21) = 28 Now, 28 < 40. So, 28 is the minimum number of persons in the queue.
प्र: Boy, man, uncle, fireman, grandfather are... 5744 05b5cc6dee4d2b4197774ea51
5b5cc6dee4d2b4197774ea51- 1Feminine titlesfalse
- 2Masculine titlestrue
- 3Both Feminine and Masculine titlesfalse
- 4None of the abovefalse
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उत्तर : 2. "Masculine titles"
व्याख्या :
Answer: B) Masculine titles Explanation: As they are the titles of male gender, they are called as Masculine titles.
प्र: 2 is to 55 as 6 is to 5714 05b5cc66de4d2b4197774bfe4
5b5cc66de4d2b4197774bfe4- 199true
- 244false
- 39false
- 433false
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उत्तर : 1. "99"
व्याख्या :
Answer: A) 99 Explanation: Given 2 is to 55 2 + 3 = 5 5 x 11 = 55 Similarly, 6 6 + 3 = 9 9 x 11 = 99 Hence, 2 is to 55 as 6 is to 99.
प्र: In a certain coding language, iF GO = 32 & SHE = 49 then SOME will be equal to ? 5687 05b5cc73de4d2b4197774f96d
5b5cc73de4d2b4197774f96d- 156true
- 258false
- 362false
- 464false
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उत्तर : 1. "56"
व्याख्या :
Answer: A) 56 Explanation: If we count letters till the end of the alphabet including that letter in reverse order then Here the values are nothing but the values corresponding to the alphabets when taken in a reverse order,i.e,A=26 ,B=25...,Z=1G = 20 and O = 12 totaling 32S = 8, H = 19 and E = 22 totaling 49 So SOME = 8 + 12 + 14 + 22 = 56.
प्र: What is the number of digits in 333? Given that log3 = 0.47712? 5667 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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उत्तर : 2. "13"
व्याख्या :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
प्र: Amar can do a piece of work in 10 days. He works at it for 4 days and then Arun finishes it in 9 days. In how many days can Amar and Arun together finish the work ? 5649 05b5cc6d6e4d2b4197774e66a
5b5cc6d6e4d2b4197774e66a- 14 daysfalse
- 28 daysfalse
- 33 daysfalse
- 46 daystrue
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उत्तर : 4. "6 days"
व्याख्या :
Answer: D) 6 days Explanation: 4/10 + 9/x = 1 => x = 15 Then both can do in 1/10 + 1/15 = 1/6 => 6 days
प्र: Which of the following is NOT true about enterprise systems? 5639 05b5cc697e4d2b4197774c5cf
5b5cc697e4d2b4197774c5cf- 1The software is expressly built to allow companies to mimic their unique business practicestrue
- 2The software includes analytical tools to evaluate overall organization performancefalse
- 3They help firms respond rapidly to customer requests for info or productsfalse
- 4The data have standardized definitions and formats that are accepted by the entire organizationfalse
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उत्तर : 1. "The software is expressly built to allow companies to mimic their unique business practices"
व्याख्या :
Answer: A) The software is expressly built to allow companies to mimic their unique business practices Explanation: Enterprise systems (ES) are large-scale application software packages that support business processes, information flows, reporting, and data analytics in complex organizations. Here option A) The software is expressly built to allow companies to mimic their unique business practices is not TRUE about enterprise systems.
प्र: A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior ? 5629 05b5cc6eee4d2b4197774eed7
5b5cc6eee4d2b4197774eed7- 1²²C₁₀ + 1false
- 2²²C₉ + ¹⁰C₁false
- 3²²C₁₀false
- 4²²C₁₀ - 1true
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उत्तर : 4. "²²C₁₀ - 1"
व्याख्या :
Answer: D) ²²C₁₀ - 1 Explanation: The total number of ways of forming the group of ten representatives is ²²C₁₀. The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way The required number of ways = ²²C₁₀ - 1