Answer: A) 244 Explanation: The given number series 22, 26, 42, 78, 142, 244 follows a pattern that, 2222 + 22 = 22 + 4 = 2626 + 42 = 26 + 16 = 4242 + 62 = 42 + 36 = 7878 + 82 = 78 + 64 = 142142 + 102 = 142 + 100 = 242    Hence, the odd one in the given number series is 244.

Answer: A) 4320 Explanation: Given Word is PROMISE. Number of letters in the word PROMISE = 7 Number of ways 7 letters can be arranged = 7! ways Number of Vowels in word PROMISE = 3 (O, I, E) Number of ways the vowels can be arranged that 3 Vowels come together = 5! x 3! ways   Now, the number of ways of arrangements so that three vowels should not come together = 7! - (5! x 3!) ways = 5040 - 720 = 4320.

Answer: A) 4 days Explanation: Given that  6 men and 8 boys can do a piece of work in 10 days  26 men and 48 boys can do the same in 2 days   As the work done is equal, 10(6M + 8B) = 2(26M + 48B) 60M + 80B = 52M + 96B => M = 2B => B = M/2 ……(1)   Now Put (1) in 15M + 20B => 15M + 10M = 25M Now, 6M + 8B in 10 days => (6M + 4M) 10 = 100M Then D(25M) = 100M => D = 4 days.

Answer: D) None Explanation: Amount = 80001+51002   = 8000 x 21/20 x 21/20    = Rs. 8820

Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking.    (i) 1 lady out of 4 and 4 gentlemen out of 6  (ii) 2 ladies out of 4 and 3 gentlemen out of 6  (iii) 3 ladies out of 4 and 2 gentlemen out of 6  (iv) 4 ladies out of 4 and 1 gentlemen out of 6    In case I the number of ways = C14×C46 = 4 x 15 = 60  In case II the number of ways = C24×C36 = 6 x 20 = 120  In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6    Hence, the required number of ways = 60 + 120 + 60 + 6 = 246

Answer: A) 70 kms Explanation: Let the time taken by train be 't' hrs. Then, 40t = 35t + 1560 40t = 35t + 35/4 t = 7/4 hrs Therefore, Required length of the total journey d = s x t = 40 x 7/4 = 70 kms.

Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways  (i) Selecting bag I and then drawing a red ball from it.   (ii) Selecting bag II and then drawing a red ball from it.   Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore  P(E1) = 1/2  and  P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7   PAE2  = Probability of drawing a red ball when the second bag has been selected = 2/6  Using the law of total probability, we have   P(red ball) = P(A) = PE1×PAE1+PE2×PAE2                              = 12×47+12×26=1942

Answer: A) 92.8% Explanation: Here, x = 40 and y = 30;Therefore second number= [[100+y100+x] x 100 ]% of first number= [[100+y100+x] x 100 ]% of first numberSecond number = 92.8% of the first number.