Quantitative Aptitude Practice Question and Answer
8Q: Vishal and Raghu jointly started a business. Vishal invested three times as Raghu did and invested his money for double time as compared to Raghu. Raghu earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was ? 1453 05b5cc6dee4d2b4197774ea8f
5b5cc6dee4d2b4197774ea8f- 1Rs. 28,000true
- 2Rs. 18,000false
- 3Rs. 14,000false
- 4Rs. 8,000false
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Answer : 1. "Rs. 28,000"
Explanation :
Answer: A) Rs. 28,000 Explanation: Investments ratio is = 3:1Time period ratio is = 2:1 As they are proportional to gain ------Gain ratio of Vishal and raghu = 6:1 But given Raghu got Rs. 4000, =? 1 ----- 4000 7 ----- ? => Rs.28,000 The total gain = Rs.28,000
Q: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit ? 1427 05b5cc6dee4d2b4197774ea80
5b5cc6dee4d2b4197774ea80- 1Rs. 660false
- 2Rs. 560false
- 3Rs. 1060false
- 4Rs. 960true
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Answer : 4. "Rs. 960"
Explanation :
Answer: D) Rs. 960 Explanation: Let C.P. = Rs. C. Then, 832 - C = C - 4482C = 1280 => C = 640Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.
Q: 10 boys can complete a work in 7 days and 10 girls take 14 days to complete the work. How many days will 5 boys and 10 girls take to complete the work ? 899 05b5cc6dee4d2b4197774ea85
5b5cc6dee4d2b4197774ea85- 113 daysfalse
- 210 daysfalse
- 37 daystrue
- 416 daysfalse
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Answer : 3. "7 days"
Explanation :
Answer: C) 7 days Explanation: 1 boy's 1 day work = 1/70 1 girl's 1 day work = 1/140 (5 boys + 10 girls)'s 1 day work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7 5 boys and 10 girls will complete the work in 7 days.
Q: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned ? 1722 05b5cc6dee4d2b4197774ea74
5b5cc6dee4d2b4197774ea74- 1Rs. 11828.80false
- 2Rs. 19828.80true
- 3Rs. 9828.80false
- 4Rs. 19328.80false
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Answer : 2. "Rs. 19828.80"
Explanation :
Answer: B) Rs. 19828.80 Explanation: Let the sum be Rs. P P{ 1+81002- 1 } = 2828.80 It is in the form of a2-b2 = a+ba-b P(8/100)(2 + 8/100) = 2828.80 P = 2828.80 / (0.08)(2.08) = 1360/0.08 = 17000 Principal + Interest = Rs. 19828.80
Q: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ? 2717 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
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Answer : 3. "4312 sq.m"
Explanation :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively. 2πs = 264 and 2πl = 352 s = 2642π and l = 3522π Difference between the areas =πl2-πs2 = π1762π2-1322π2 = 1762π-1322π = (176 - 132)(176 + 132) / π = (44 x 308) / (22/7) = 4312 sq.m
Q: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 3749 05b5cc6dee4d2b4197774ea65
5b5cc6dee4d2b4197774ea65- 120true
- 235false
- 354false
- 440false
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Answer : 1. "20"
Explanation :
Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.
Q: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? 1350 05b5cc6dee4d2b4197774ea5b
5b5cc6dee4d2b4197774ea5b- 110 secfalse
- 248 secfalse
- 336 sectrue
- 456 secfalse
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Answer : 3. "36 sec"
Explanation :
Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.
Q: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train ? 3466 05b5cc6dee4d2b4197774ea56
5b5cc6dee4d2b4197774ea56- 168 kmphtrue
- 252 kmphfalse
- 376 kmphfalse
- 450 kmphfalse
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Answer : 1. "68 kmph"
Explanation :
Answer: A) 68 kmph Explanation: Let the speed of the faster train be 'X' kmph, Then their relative speed= X - 48 kmphTo cross slower train by faster train, Distance need to be cover = (400 + 600)m = 1 km. and Time required = 180 sec = 180/3600 hr = 1/20 hr.Time = Distance/Speed => 1/20 = 1/(x-48)X = 68 kmph