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प्र: A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained? 1680 0

उत्तर : 2. "1/6"
व्याख्या :
Answer: B) 1/6 Explanation: Total work is given by L.C.M of 72, 48, 36 Total work = 144 units Efficieny of A = 144/72 = 2 units/day Efficieny of B = 144/48 = 3 units/day Efficieny of C = 144/36 = 4 units/day According to the given data, 2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100 3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54 p = 198/16.5 p = 12 days. Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day (C+D) in p days = (4 + 6) x 12 = 120 unit Remained part of work = (144-120)/144 = 1/6.

प्र: 14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together. 1679 0

उत्तर : 3. "24/625"
व्याख्या :
Answer: C) 24/625 Explanation: Total no of ways = (14 – 1)! = 13! Number of favorable ways = (12 – 1)! = 11! So, required probability = 11!×3!13! = 39916800×66227020800 = 24625

प्र: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1678 0

उत्तर : 1. "61%"
व्याख्या :
Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220, S.P. = Rs.320. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195 Required percentage = 195320×100== 60.9 =~ 61%

प्र: The ratio of speeds of a car, a train and a bus is 5:9:4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together ? 1676 0

उत्तर : 1. "84 km/hr"
व्याख्या :
Answer: A) 84 km/hr Explanation: Let the speeds of the car, train and bus be 5x, 9x and 4x km/hr respectively.Average speed = 5x + 9x + 4x/3 = 18x /3 = 6x km/hr.Also, 6x = 72 => x = 12 km/hrTherefore, the average speed of the car and train together is = 5x+9x2= 7x = 7 x 12 = 84 km/hr.

प्र: A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet? 1674 0

उत्तर : 1. "378"
व्याख्या :
Answer: A) 378 Explanation:

प्र: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ? 1669 0

उत्तर : 3. "5"
व्याख्या :
Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1) But (3x + 2)(2x - 5) = 6x2-11x-10........(2) so by comparing (1) & (2), we get a= 6, k= -11 , n= -10 (a - n + k) = 6 + 10 - 11 = 5.

प्र: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1669 0

उत्तर : 3. "209"
व्याख्या :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.

प्र: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 1668 0

उत्तर : 4. "15"
व्याख्या :
Answer: D) 15 Explanation: Let 'K' be the total number of sweets.Given total number of students = 112If sweets are distributed among 112 children,Let number of sweets each student gets = 'L' => K/112 = L ....(1)But on that day students absent = 32 => remaining = 112 - 32 = 80Then, each student gets '6' sweets extra. => K/80 = L + 6 ....(2)from (1) K = 112L substitute in (2), we get112L = 80L + 48032L = 480L = 15 Therefore, 15 sweets were each student originally supposed to get.

प्र: 14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together. 1679 0

उत्तर : 3. "24/625"
व्याख्या :
Answer: C) 24/625 Explanation: Total no of ways = (14 – 1)! = 13! Number of favorable ways = (12 – 1)! = 11! So, required probability = 11!×3!13! = 39916800×66227020800 = 24625

प्र: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1678 0

उत्तर : 1. "61%"
व्याख्या :
Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220, S.P. = Rs.320. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195 Required percentage = 195320×100== 60.9 =~ 61%

प्र: The ratio of speeds of a car, a train and a bus is 5:9:4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together ? 1676 0

प्र: A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet? 1674 0

उत्तर : 1. "378"
व्याख्या :
Answer: A) 378 Explanation:

प्र: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ? 1669 0

उत्तर : 3. "5"
व्याख्या :
Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1) But (3x + 2)(2x - 5) = 6x2-11x-10........(2) so by comparing (1) & (2), we get a= 6, k= -11 , n= -10 (a - n + k) = 6 + 10 - 11 = 5.

प्र: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1669 0

उत्तर : 3. "209"
व्याख्या :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.

प्र: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 1668 0

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प्र: 14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together. 1679 05b5cc6b6e4d2b4197774d5b8

उत्तर : 3. "24/625" व्याख्या :Answer: C) 24/625 Explanation: Total no of ways = (14 – 1)! = 13! Number of favorable ways = (12 – 1)! = 11! So, required probability = 11!×3!13! = 39916800×66227020800 = 24625

प्र: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1678 05b5cc767e4d2b4197774fe45

उत्तर : 1. "61%" व्याख्या :Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220, S.P. = Rs.320. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195 Required percentage = 195320×100== 60.9 =~ 61%

प्र: The ratio of speeds of a car, a train and a bus is 5:9:4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together ? 1676 05b5cc736e4d2b4197774f83c

प्र: A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet? 1674 05b5cc6b7e4d2b4197774d63d

उत्तर : 1. "378" व्याख्या :Answer: A) 378 Explanation:

प्र: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ? 1669 05b5cc74fe4d2b4197774fafe

उत्तर : 3. "5" व्याख्या :Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1) But (3x + 2)(2x - 5) = 6x2-11x-10........(2) so by comparing (1) & (2), we get a= 6, k= -11 , n= -10 (a - n + k) = 6 + 10 - 11 = 5.

प्र: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1669 05b5cc774e4d2b41977750011

उत्तर : 3. "209" व्याख्या :Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.

प्र: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 1668 05b5cc741e4d2b4197774f9a4

त्रुटि की रिपोर्ट करें

त्रुटि की रिपोर्ट करें

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त्रुटि की रिपोर्ट करें

त्रुटि की रिपोर्ट करें

त्रुटि की रिपोर्ट करें

त्रुटि की रिपोर्ट करें

त्रुटि की रिपोर्ट करें

प्र: 14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together. 1679 0

उत्तर : 3. "24/625"
व्याख्या :
Answer: C) 24/625 Explanation: Total no of ways = (14 – 1)! = 13! Number of favorable ways = (12 – 1)! = 11! So, required probability = 11!×3!13! = 39916800×66227020800 = 24625

प्र: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1678 0

उत्तर : 1. "61%"
व्याख्या :
Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220, S.P. = Rs.320. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195 Required percentage = 195320×100== 60.9 =~ 61%

प्र: The ratio of speeds of a car, a train and a bus is 5:9:4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together ? 1676 0

प्र: A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet? 1674 0

उत्तर : 1. "378"
व्याख्या :
Answer: A) 378 Explanation:

प्र: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ? 1669 0

उत्तर : 3. "5"
व्याख्या :
Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1) But (3x + 2)(2x - 5) = 6x2-11x-10........(2) so by comparing (1) & (2), we get a= 6, k= -11 , n= -10 (a - n + k) = 6 + 10 - 11 = 5.

प्र: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1669 0

उत्तर : 3. "209"
व्याख्या :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.

प्र: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 1668 0