Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1666 05b5cc767e4d2b4197774fe45
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उत्तर : 1. "61%"
व्याख्या :
Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220, S.P. = Rs.320. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195 Required percentage = 195320×100== 60.9 =~ 61%
प्र: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 1663 05b5cc741e4d2b4197774f9a4
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उत्तर : 4. "15"
व्याख्या :
Answer: D) 15 Explanation: Let 'K' be the total number of sweets.Given total number of students = 112If sweets are distributed among 112 children,Let number of sweets each student gets = 'L' => K/112 = L ....(1)But on that day students absent = 32 => remaining = 112 - 32 = 80Then, each student gets '6' sweets extra. => K/80 = L + 6 ....(2)from (1) K = 112L substitute in (2), we get112L = 80L + 48032L = 480L = 15 Therefore, 15 sweets were each student originally supposed to get.
प्र: The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ? 1663 05b5cc6fbe4d2b4197774f09f
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उत्तर : 1. "87"
व्याख्या :
Answer: A) 87 Explanation: Cp1 = p2 - p1 , Cp2 = p3 - p2 ......Cp23 = p24 - p23Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)All terms get cancelled, except p1 = 2 and p24 = 89 So Sum = -p1 + p24Sum of series = -2 + 89 = 87
प्र: P, Q, and R can do a job in 12 days together. If their efficiency of working be in the ratio 3 : 8 : 5, Find in what time Q can complete the same work alone? 1661 05b5cc698e4d2b4197774c61d
5b5cc698e4d2b4197774c61d- 136 daystrue
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उत्तर : 1. "36 days"
व्याख्या :
Answer: A) 36 days Explanation: Given the ratio of efficiencies of P, Q & R are 3 : 8 : 5 Let the efficiencies of P, Q & R be 3x, 8x and 5x respectively They can do work for 12 days. => Total work = 12 x 16x = 192x Now, the required time taken by Q to complete the job alone = 162x8x = 24 days.
प्र: What is the angle made by the hour hand and the minute hand, if the clock shows 9:15 pm ? 1659 05b5cc6d2e4d2b4197774e410
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उत्तर : 2. "172.5 degrees"
व्याख्या :
Answer: B) 172.5 degrees Explanation: The minute hand angle is the easiest since an hour (i.e. 60 minutes) corresponds to the entire 360 degrees, each minute must correspond to 6 degrees. So just multiply the number of minutes in the time by 6 to get the number of degrees for the minute hand. Here 15 minutes corresponds to 15 x 6 = 90 degrees Next, you have to figure out the angle of the hour hand. Since there are 12 hours in the entire 360 degrees, each hour corresponds to 30 degrees. But unless the time is EXACTLY something o'clock, you have to write the time as a fractional number of hours rather than as hours and minutes.Here the time is 9:15 which is (9 + 15/60) = 37/4 hours. Since each hour corresponds to 30 degrees, we multiply 30 to get (37/4)(30) = 277.5 degrees. Since the hour hand is at 277.5 degrees and the minute hand is at 90 degrees, we can subtract to get the angle of separation. 277.5 - 90 = 187.5 =~ 360 - 187.5 = 172.5 degrees.
प्र: A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet? 1658 05b5cc6b7e4d2b4197774d63d
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उत्तर : 1. "378"
व्याख्या :
Answer: A) 378 Explanation:
प्र: H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is : 1648 05b5cc6e7e4d2b4197774eda6
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उत्तर : 2. "180"
व्याख्या :
Answer: B) 180 Explanation: 4 x 27 x 3125 = 22 × 33 × 55 ; 8 x 9 x 25 x 7 = 23 × 32 × 52 × 7 16 x 81 x 5 x 11 x 49 = 24 × 34 × 5 × 11 × 72 H.C.F = 22 × 32 × 5 = 180.
प्र: A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ? 1648 05b5cc723e4d2b4197774f690
5b5cc723e4d2b4197774f690- 1Rs. 345.15true
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उत्तर : 1. "Rs. 345.15"
व्याख्या :
Answer: A) Rs. 345.15 Explanation: area of the plot = 120m x 60m = 7200 sq.marea of plot excluding gravel = 117m x 57m = 6669 sq.marea of gravel = 7200 sq.m - 6669 sq.m = 531 sq.mcost of building it = 531 sq.m x 65 ps = 34515 psIn Rs. = 34515/100 = Rs. 345.15.