Quantitative Aptitude Practice Question and Answer
8Q: One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill tank in 36 min, then the slower pipe alone will be able to fill the tank in ? 1769 05b5cc6f1e4d2b4197774ef3f
5b5cc6f1e4d2b4197774ef3f- 185 minfalse
- 292 minfalse
- 3187 minfalse
- 4144 mintrue
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Answer : 4. "144 min"
Explanation :
Answer: D) 144 min Explanation: Let the slower pipe alone fill the tank in x min. Then, faster pipe will fill it in x/3 min. 1/x + 3/x = 1/36 4/x = 1/36 => x = 144 min.
Q: Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ? 1767 05b5cc6f8e4d2b4197774f06d
5b5cc6f8e4d2b4197774f06d- 184 yrsfalse
- 296 yrsfalse
- 3116 yrsfalse
- 4108 yrstrue
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Answer : 4. "108 yrs"
Explanation :
Answer: D) 108 yrs Explanation: Let the present ages of the mother and daughter be 2x and x years respectively. Then, (2x - 18) = 3(x - 18) => x = 36 Required sum = (2x + x) = 108 years.
Q: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20% ? 1764 05b5cc6dbe4d2b4197774e937
5b5cc6dbe4d2b4197774e937- 130 %false
- 225 %false
- 315 %false
- 420 %true
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Answer : 4. "20 %"
Explanation :
Answer: D) 20 % Explanation: SP2 = 2/3 SP1CP = 100SP2 = 802/3 SP1 = 80 SP1 = 120100 --- 20 => 20%
Q: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ? 1761 05b5cc6dce4d2b4197774e997
5b5cc6dce4d2b4197774e997- 15 kmphfalse
- 27 kmphfalse
- 33 kmphfalse
- 44 kmphtrue
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Answer : 4. "4 kmph"
Explanation :
Answer: D) 4 kmph Explanation: Speed of Man = 4.5 kmphSpeed of stream = 1.5 kmphSpeed in DownStream = 6 kmphSpeed in UpStream = 3 kmphAverage Speed = (2 x 6 x 3)/9 = 4 kmph.
Q: 7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age? 1760 05b5cc6bbe4d2b4197774d849
5b5cc6bbe4d2b4197774d849- 191 yearsfalse
- 2115 yearsfalse
- 3103 yearstrue
- 4Can't be determinedfalse
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Answer : 3. "103 years"
Explanation :
Answer: C) 103 years Explanation: Let present Anirudh's age be 'A' and Bhavana's age be 'B' Given seven years, their ratio is 7:9 => A-7 : B-7 = 7 : 9 => 9A - 7B = 14 .......(1) And given, Chandhu is 12 years older than A nad 12 years younger than B => C = A + 12....(2) => B = C + 12 => B = A + 12 + 12 .....(From (2)) => B = A + 24 ....(3) Put (3) in (1) 9A - 7(A+24) = 14 9A - 7A - 168 = 14 2A = 182 => A = 91 years => C = A + 12 = 91 +12 = 103 years.
Q: Which value is equal to 5% of 1,500? 1756 05b5cc666e4d2b4197774bee9
5b5cc666e4d2b4197774bee9- 135false
- 255false
- 375true
- 445false
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Answer : 3. "75"
Explanation :
Answer: C) 75 Explanation: In the question it is asked for 5% of 1500 5 x 1500/100 = 15 x 5 = 75. Hence, 5% of 1,500 is equal to 75.
Q: Population of a colony of mosquitoes is increasing by 20% per day. If the population on Monday was 3000, on which day of that week the population would be 5184 ? 1756 05b5cc73ae4d2b4197774f8f1
5b5cc73ae4d2b4197774f8f1- 1Thursdaytrue
- 2Fridayfalse
- 3Tuesdayfalse
- 4Mondayfalse
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Answer : 1. "Thursday"
Explanation :
Answer: A) Thursday Explanation: Given monday population = 3000Per day 20% increase in population. Tuesday population = 3000 + 3000x20/100 = 3000 + 600 = 3600 Wednesday population =3600 + 3600x20/100 = 3600 + 720 = 4320 Thursday population = 4320 + 4320x20/100 = 4320 + 864 = 5184 So that day is Thursday.
Q: A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village ? 1755 05b5cc74ae4d2b4197774facc
5b5cc74ae4d2b4197774facc- 140 kmfalse
- 230 kmfalse
- 320 kmtrue
- 410 kmfalse
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Answer : 3. "20 km"
Explanation :
Answer: C) 20 km Explanation: Average speed = 2aba+b, here a=25 b=4 = 2 x 25 x 4/(25+4) = 200/29 km/hr. Distance covered in 5 hours 48 minutes = Speed x time = (200/29)x (29/5) Distance covered in 5 hours 48 minutes = 40kms. Distance of the post office from the village = (40/2) = 20 km.