Quantitative Aptitude Practice Question and Answer
8Q: What is the equivalent compound ratio of 5:6::7:10::6:5 ? 1868 05b5cc6e3e4d2b4197774eccf
5b5cc6e3e4d2b4197774eccf- 17 : 9false
- 29 : 7false
- 37 : 4false
- 47 : 10true
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Answer : 4. "7 : 10"
Explanation :
Answer: D) 7 : 10 Explanation: Given 5:6 :: 7:10 :: 6:5 We know that compound ratio is calculated as a:b :: c:d :: e:f(axcxe):(bxdxf) => (5x7x6):(6x10x5)=> (210):(300)= 7:10
Q: Find the next number in the given number series? 35, 36, 55, 111, ? 1868 05b5cc62ae4d2b4197774b8a5
5b5cc62ae4d2b4197774b8a5- 1278.5true
- 2264.5false
- 3212.5false
- 4202false
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Answer : 1. "278.5"
Explanation :
Answer: A) 278.5 Explanation: The given number series is 35, 36, 55, 111, ? 35 35 x 1 + 1 = 36 36 x 1.5 + 1 = 55 55 x 2 + 1 = 111 111 x 2.5 + 1 = 278.5 Hence, the next number in the given number series is 278.5.
Q: A house owner wants to get his house painted. He is told that this would require 45 kg of paint allowing 6% wasting. And if the paint is available in 4 kg tins only, the number of tins required for painting the house is ? 1867 05b5cc6d1e4d2b4197774e3e3
5b5cc6d1e4d2b4197774e3e3- 112true
- 213false
- 311false
- 410false
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Answer : 1. "12"
Explanation :
Answer: A) 12 Explanation: Given 45 kg for painting And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg Now total paint required = 45+2.7 = 47.7 kgs But tins are available in only 4kgs Then, no. of tins req = 47.7/4 = 11.4 => 12 tins
Q: One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill tank in 36 min, then the slower pipe alone will be able to fill the tank in ? 1865 05b5cc6f1e4d2b4197774ef3f
5b5cc6f1e4d2b4197774ef3f- 185 minfalse
- 292 minfalse
- 3187 minfalse
- 4144 mintrue
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Answer : 4. "144 min"
Explanation :
Answer: D) 144 min Explanation: Let the slower pipe alone fill the tank in x min. Then, faster pipe will fill it in x/3 min. 1/x + 3/x = 1/36 4/x = 1/36 => x = 144 min.
Q: Find the odd term from the given series of numbers ? 125, 127, 130, 135, 142, 153, 165 ? 1864 05b5cc6dde4d2b4197774e9e7
5b5cc6dde4d2b4197774e9e7- 1153false
- 2165true
- 3142false
- 4127false
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Answer : 2. "165"
Explanation :
Answer: B) 165 Explanation: From the beginning, the next term comes by adding prime numbers in a sequence of 2, 3, 5, 7, 9, 11, 13... to its previous term. But 165 will not be in the series as it must be replaced by 166 since 153+13 = 166.
Q: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 1861 05b5cc75ee4d2b4197774fc9d
5b5cc75ee4d2b4197774fc9d- 1Rs.2010false
- 2Rs.2200false
- 3Rs.2000true
- 4Rs.2100false
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Answer : 3. "Rs.2000"
Explanation :
Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.
Q: A man rows his boat 60 km downstream and 30 km upstream taking 3 hrs each time. Find the speed of the stream ? 1856 05b5cc777e4d2b41977750098
5b5cc777e4d2b41977750098- 15 kmphtrue
- 210 kmphfalse
- 315 kmphfalse
- 445 kmphfalse
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Answer : 1. "5 kmph"
Explanation :
Answer: A) 5 kmph Explanation: Speed of the boat downstream s=a/t= 60/3 = 20 kmph Speed of the boat upstream s= d/t = 30/3= 10 kmph Therefore, The speed of the stream = speed of downstream - speed of upstream2=5 kmph
Q: Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour ? 1852 05b5cc6e2e4d2b4197774ec57
5b5cc6e2e4d2b4197774ec57- 12 hrsfalse
- 220 mintrue
- 340 minfalse
- 430 minfalse
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Answer : 2. "20 min"
Explanation :
Answer: B) 20 min Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.