Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: 250 मीटर लम्बी एक ट्रेन एक खम्भे को 15 सैंकण्ड में पार करती है। ट्रेन की गति किमी/घंटा में क्या है? 1906 05d15fcbb5fdb2c68495d9dff
5d15fcbb5fdb2c68495d9dff- 190false
- 245false
- 370false
- 4इनमें से कोई नहींtrue
- उत्तर देखें
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उत्तर : 4. "इनमें से कोई नहीं"
प्र: Rajitha's present age is three years less than twice her age 12 years ago. Also, the ratio of Raj's present age to Rajitha's present age is 4:9. What will be Raj's age after 5 years ? 1899 05b5cc736e4d2b4197774f82d
5b5cc736e4d2b4197774f82d- 117 yrstrue
- 216 yrsfalse
- 319 yrsfalse
- 421 yrsfalse
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उत्तर : 1. "17 yrs"
व्याख्या :
Answer: A) 17 yrs Explanation: Let the present age of Raj and Rajitha be 4x and 9x.Then, according to question,9x = 2(9x-12)-3 => 9x = 27 => x = 3Raj's present age = 4x = 12yrs, After 5 years Raj's age will be 12 + 5 = 17 yrs.
प्र: Two trains 85 m and 75 m long are running in same direction with speeds of 62 km/hr and 44 km/hr respectively. In what time will the first train cross the second train ? 1898 15b5cc783e4d2b41977750214
5b5cc783e4d2b41977750214- 122 secfalse
- 232 sectrue
- 342 secfalse
- 452 secfalse
- उत्तर देखें
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उत्तर : 2. "32 sec"
व्याख्या :
Answer: B) 32 sec Explanation: Given that, 1st train speed = 62 km/hr 2nd train speed = 44 km/hr Hence the relative speed of two trains is : 62-44 = 18 km/hr = 18×518 m/s = 5 m/s. There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in, time = distancespeed = 85+755 = 32 sec.
प्र: How many degrees will the minute hand move, in the same time in which the second hand move 5400 ? 1894 05b5cc6e9e4d2b4197774ee29
5b5cc6e9e4d2b4197774ee29- 190 degreestrue
- 285 degreesfalse
- 360 degreesfalse
- 445 degreesfalse
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उत्तर : 1. "90 degrees"
व्याख्या :
Answer: A) 90 degrees Explanation: Minute hand covers 5400/60 = 90°
प्र: How many square units in 13 by 9? 1891 05b5cc615e4d2b4197774b6b8
5b5cc615e4d2b4197774b6b8- 113false
- 29false
- 3117true
- 413/9false
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उत्तर : 3. "117"
व्याख्या :
Answer: C) 117 Explanation: Number of square units in 13 by 9 is given by the area it forms with length and breadth as 13 & 9 Area = 13 x 9 = 117 Hence, number of square units in 13 by 9 is 117 sq.units.
प्र: Munna and Chinna are partners in a firm out of which Munna is sleeping partner and Chinna is working partner. Munna invests Rs. 1,40,000 and Chinna invests Rs. 80,000. Chinna receives 14.5% of profit for managing the business and the rest is shared between both in ratio of their investments. Munna's share in the profit of Rs. 19600 is ? 1890 05b5cc6cae4d2b4197774e04a
5b5cc6cae4d2b4197774e04a- 1Rs. 9580.25false
- 2Rs. 10600false
- 3Rs. 10664.15true
- 4Rs. 11060.48false
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उत्तर : 3. "Rs. 10664.15"
व्याख्या :
Answer: C) Rs. 10664.15 Explanation: Profit received by Chinna as working partner = 14.5% of Rs. 19600 = 14.5x19600/100 = Rs. 2842 Balance in profit = 19600-2842 = Rs. 16758 Ratio of investment of Chinna & Munna = 80,000 : 1,40,000 = 4 : 7 Hence share of Chinna in investment = 4x16758/100 = Rs. 6093.85 Therefore, Share of Munna = 19600 - 2842 - 6093.85 = Rs. 10664.15
प्र: Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to ___ ? 1889 05b5cc6bee4d2b4197774d983
5b5cc6bee4d2b4197774d983- 13.7false
- 22.7false
- 33.6false
- 42.9true
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उत्तर : 4. "2.9"
व्याख्या :
Answer: D) 2.9 Explanation: xz = y2 10(0.48z) = 10(2 x 0.70) = 101.40 0.48z = 1.40 z = 140/18 = 35/12 = 2.9 (approx.)
प्र: A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is : 1887 05b5cc783e4d2b419777501e7
5b5cc783e4d2b419777501e7- 19.5 km/hrfalse
- 210 km/hrtrue
- 310.5 km/hrfalse
- 411 km/hrfalse
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उत्तर : 2. "10 km/hr"
व्याख्या :
Answer: B) 10 km/hr Explanation: Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr. Therefore, Man's rate against the current = (12.5 - 2.5) = 10 km/hr.