Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ

рдкреНрд░: What is the next number in this series ?  4, 6, 12, 18, 30, 42, 60, ? 1463 0

  • 1
    71
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    72
    рд╕рд╣реА
    рдЧрд▓рдд
  • 3
    73
    рд╕рд╣реА
    рдЧрд▓рдд
  • 4
    69
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ : 2. "72"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 72 Explanation: With close observation, you will note that each number in the list is in the middle of two prime numbers. Thus: 4 is in the middle of 3 and 5, 6 is in the middle of 5 and 7, 12 is in the middle of 11 and 13, 18 is in the middle of 17 and 19, 30 is in the middle of 29 and 31. 42 is in the middle of 41 and 43, 60 is in the middle of 59 and 61. Therefore, the next number would be the one that is in the middle of the next two prime numbers, which is 72 (which is in the middle of 71 and 73).

рдкреНрд░: The ratio between the length and breadth of a rectangular field is 5 : 4 if the breadth is 20m less than the length, the perimeter of the field is : 1106 0

  • 1
    260m
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    280m
    рд╕рд╣реА
    рдЧрд▓рдд
  • 3
    360m
    рд╕рд╣реА
    рдЧрд▓рдд
  • 4
    none of these
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ :
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: Explanation:

рдкреНрд░: Three friends, P, Q and R started a partnership business investing money in the ratio of 5 : 4 : 2 respectively for a period of 3 years. What is the amount received by P as his share in the total profit ? a. Total amount invested in the business in Rs. 22,000. b. Profit earned at the end of 3 years is 3/8 of the total investment. c. The average amount of profit earned per year is Rs. 2750. 3374 0

  • 1
    Only c is sufficient
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    Both a & b are sufficient
    рд╕рд╣реА
    рдЧрд▓рдд
  • 3
    Both A & B gives result
    рд╕рд╣реА
    рдЧрд▓рдд
  • 4
    None
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ : 3. "Both A & B gives result"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) Both A & B gives result Explanation: a and b give, profit after 3 years = Rs.(3/8 x 22000) = Rs.8250. From c also, profit after 3 years = Rs. (2750 x 3) = Rs. 8250. тИ┤ P's share = Rs.(8250 x 5/11) = Rs. 3750. Thus, (either C is redundant) or (a and b are redundant).

рдкреНрд░: What is the difference in the shares of profit between P and Q in a joint business at the end of one year ? a. P Invested Rs. 80,000 and withdrew Rs. 20,000 after 6 months. b. Q joined four months after the start of business. c. Q's amount was 80% of P's amount during the last six months. 1560 0

  • 1
    Only a
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    Only c
    рд╕рд╣реА
    рдЧрд▓рдд
  • 3
    Both a & b
    рд╕рд╣реА
    рдЧрд▓рдд
  • 4
    Data is not sufficient
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ : 4. "Data is not sufficient"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) Data is not sufficient Explanation: a. P's investment = (80000 x 6 + 60000 x 6) = 840000 for 1 month. b & c. Q's investment = 80% of Rs. 60000 for 8 months. = Rs.(48000 x 8) for 1 month = 384000 for 1 month P : Q = 840000 : 384000 = 35 : 16. But, the total profit is not given, so data is inadequate.

рдкреНрд░: Find the regular polygon whose interior angel is 150 more than exterior angle. note the total sum of interior and exterior angle should be 180 at one point ? 914 0

  • 1
    12
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    24
    рд╕рд╣реА
    рдЧрд▓рдд
  • 3
    36
    рд╕рд╣реА
    рдЧрд▓рдд
  • 4
    6
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ : 2. "24"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 24 Explanation: Sum of Interior angle is 180 .and it is given that interior angle is 150 more than exterior,so let exterior angle is x then interior will be x+150 now , interior + exterior =180x+150+x=180x=15 now , number of sides of polygon = 360 / exterior anglen = 360 / 15n = 24

рдкреНрд░: A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time ? 2348 0

  • 1
    2 days
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    3 days
    рд╕рд╣реА
    рдЧрд▓рдд
  • 3
    4 days
    рд╕рд╣реА
    рдЧрд▓рдд
  • 4
    5 days
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ : 1. "2 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 2 days Explanation: work done=total number of person x number of days;half of work done = 140 x 66;For half of remaining work 25 extra men are added.Therefore, total men for half work remaining = 140 + 25 = 165;Let 2nd half work will be completed in K days;140 x 66 = 165 x KK = 122;Hence, extra days => 122-120 = 2days.

  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ : 2. "17"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 17 Explanation: Since floor starts form the 1 therefore 2 will be the 1st floor.Form 1 to 10 only 4,6,8,9,10 are not prime.Form 11 to 20 only 14 ,16,18 are not prime also non of their digits are prime.From 21 to 30 each number has a prime number so it must no be consider.In between 40 to 49 we have to consider only 40,44,46,48,49.50 to 59 follow either of the condition so we have too neglect it.In between 60 to 68 60,64,66,68.total option = 17.

рдкреНрд░: What is the sum of all 3 digits number that can be formed using digits 0,1,2,3,4,5 with no repitition ? 1209 0

  • 1
    28450
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    26340
    рд╕рд╣реА
    рдЧрд▓рдд
  • 3
    32640
    рд╕рд╣реА
    рдЧрд▓рдд
  • 4
    36450
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
  • Workspace

рдЙрддреНрддрд░ : 3. "32640"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 32640 Explanation: We know that zero can't be in hundreds place. But let's assume that our number could start with zero.   The formula to find sum of all numbers in a permutation is   111 x no of ways numbers can be formed for a number at given position x sum of all given digits   No of 1 s depends on number of digits   So,the answer us   111 x 20 x (0+1+2+3+4+5) = 33300   We got 20 as follows. If we have 0 in units place we can form a number in 4*5 ways. This is for all numbers. So we have substituted 20 in formula.   Now, this is not the final answer because we have included 0 in hundreds place. so we have to remove the sum of all numbers that starts with 0.   This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5. Because 0 at first place makes it a 2 digit number.   So the sum for this is 11 x 4 x (1+2+3+4+5). =660   Hope u understood why we use 4. Each number can be formed in 4x1 ways   So, the final answer is 33300-660 = 32640

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ