Answer: B) 29.63 litres Explanation: Given that container has 50 litres of milk.  After replacing 8 litres of milk with water for three times, milk contained in the container is:  ⇒501-8503 ⇒50×4250×4250×4250  = 29.63 litres.

Answer: D) 25% Explanation: Let the list price be Rs.100.    Therefore, the retailer is buying the products at Rs.60 and selling it to the customer at Rs.75, earning a profit of Rs.15.   Therefore, his percentage is = 1560x100 = 25%

Answer: D) 3/10 Explanation: One hour = 60 min 18/60 = 3/10

Answer: C) 10 Explanation: Let the price of each note book be Rs.x. Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y. Hence xy = 300 => y = 300/x (x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy =>5(300/x) - 10x - 50 = 0 => -150+x2+5x multiplying both sides by -1/10x => x2+15x-10x-150=0 => x(x + 15) - 10(x + 15) = 0 => x = 10 or -15 As x>0, x = 10.

Answer: B) Rs. 2200 Explanation: He sold 4 cycles for Rs. 8400[It means each cycle price is Rs. 2100]And again he sold 3 cycles for Rs. 1900 eachIf he want to gain avg profit on each cycle is Rs. 320 per cycle.So profit for 10 cycles is @ Rs.320 is,10 x 320 = Rs. 3200He already got Rs. 1850 profit by selling 7 cycles.Now, remaining amount is 3200 - 1850 = 1350So from remaining 3 cycles we want to get Rs. 1350 profit ,1350/3 = 450so he must sell remaining 3 cycles at Rs. 2200 each one.

Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115  ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23   Hence, required number of gentlemen in the family = x = 23.

Answer: B) 437 Explanation: Given number series is 514   470   ?   415   404       Here the pattern it follows is   514   514 - 44 = 470   470 - 33 = 437   437 - 22 = 415   415 - 11 = 404   Hence, the missing number in the given number series is 437.

Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters   If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.   Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters   10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.   The ratio of milk and water in the new mixture = 16:4 = 4:1   If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters.   Amount of water removed = 2 liters.   Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters.   Now 10 lts milk is added => total milk = 18 lts   The required ratio of milk and water in the final mixture obtained   = (8 + 10):2 = 18:2 = 9:1.